U kidding me ?? Why aren't you not uploading anymore ???? Your way of explaining things are EXTREMELY good like seriously u are making all things simple !
No. Assume D_1 is ON and D_2 is OFF. If D_1 is ON, then V_A = 2 V. But then the cathode of D_2 is lower than 3 V, meaning D_2 must be ON, contrary to our assumption.
there is no current flowing through R which means it's a short circuit with no potential difference, if V was to change that would imply that there was current flowing but we assumed earlier that I = 0. (since there is no current flowing in the circuit then the Voltage is the same(5 V)at any point higher than the ground)
U kidding me ?? Why aren't you not uploading anymore ???? Your way of explaining things are EXTREMELY good like seriously u are making all things simple !
Here is the video that shows how to determine the state of diode: ua-cam.com/video/bkGy0GrMA-Y/v-deo.html
This is more than amazing.
Thank you a lot.
Please upload more videos.
Excellent ideas you've just given
this video saved me, thank you so much
I'm really pleased it was of use to you. Thanks.
Nice explanation sir ❤
Thanx, for explaining it so well.
Thanks alot please keep making more content you're very good.
Great tutorial, thank you for this.
This video shows how to determine the diode state: ua-cam.com/video/bkGy0GrMA-Y/v-deo.html
Thankyou for sharing your knowledge!
I am from Italy and I am trying to share mine...
I finally understood :) this helped a lot
Thanks DJ M.Andy!
Thank you so much!!!!!! Life saver
Great explaintions !! Thanks you
electron flow makes this odd. electron move from negative to positive? current flow is in the opposite direction of electron flow?
in your example of two diode their is also possibility that D2 is off and D1 on then still current will flow and in the downward direction.
No. Assume D_1 is ON and D_2 is OFF. If D_1 is ON, then V_A = 2 V. But then the cathode of D_2 is lower than 3 V, meaning D_2 must be ON, contrary to our assumption.
@@MarkTheEngineer Thanks
Wouldnt V4 be the same as V5 if the diode is conducting?
Can you provide a timestamp so I know which part of the video you are referring to?
thank you sir
Great Thanks
man this is fuckign awesome
Taymaz Abraham I’m pleased you found it useful!
in 9:35 how is the voltage still 5V there? isn't the 5V passing on 1Kohm, which is 1000 Ohms, we've to do Ohm's low, right?
there is no current flowing through R which means it's a short circuit with no potential difference, if V was to change that would imply that there was current flowing but we assumed earlier that I = 0. (since there is no current flowing in the circuit then the Voltage is the same(5 V)at any point higher than the ground)
at 12:55
Take away D1, D2 and then v=2v So D1 off, D2 on,id2=ia=4mA,Va=8+(-5)=3v, id1=0 mA...Answer
Thats very complicated
Here is the video that shows how to determine the state of diode: ua-cam.com/video/bkGy0GrMA-Y/v-deo.html
It is very simple concept