sir, at 8:37 you wrote 2^14.. it is bytes not bits ..... in bits format the answer would be 2^(12+5)=2^19 bits I suppose. and thanks for the lecture it was awesome :-)
14 bits indicate the number of bits required to address all the byte addressable locations in the primary memory. 14 bits is basically the size of the address.
thank you. somehow i completely missed what a word is during my years in college and this explained it clearly. :D
I think there might be a mistake at around 7:36. To represent 4096 as an unsigned integer you'd need at least 13 bits (2^12
That is correct, thanks for highlighting the noticed slip. However, I believe it is an honest flaw.
You have a reasonable point.
It should be 4095 = 12binary digits of 1. Then add 1 (zero location) to make 4096 total.
I love the way Indian people say "which is nothing but..." !lol my Indian friends always use this expression. good video btw.
Or when he says, "This is a memory." Ah, those were some good memories, weren't they?
@@ex0stasis72 lol
Thank you sir you solved my problem 👍
At 15:20 :- so, bit addressable memory means, we require 16,15, 12 and 15 bits respectively.. is it right?
Truly a wonderful explanation!
7:58 you are mistaken it is accually 1 flowed by 12 zeros which is equal to 4096
thank you soo much..Excellent tutorial!
where did 4096 come from
does it mean the ram is 4KB ?
no. 4gb
ok, but how did he come up with 4096?
2^12 = 4096. 8 bits x 4 =32 bits. 32x8=256. 256x4= 1024. 1024x4 = 4096
i think he asked for this = he just made it up... something like: "let's say i have memory with 4096 words"
man you are a lifesaver thank you
great video,can you add this "how to identify memory capacity by used number of bits/bytes"
Excellent tutorial!
Verry very good explaimed
So the word size, is that essentially the maximum length that the address of that memory cell can be?
very great lecture. Thank you!
what address is the power supply located at?
You are super. Plz make us clear about if 4gb memory then how many word would be their
learning made tough
Excellent video!
sir, at 8:37 you wrote 2^14.. it is bytes not bits ..... in bits format the answer would be 2^(12+5)=2^19 bits I suppose.
and thanks for the lecture it was awesome :-)
14 bits indicate the number of bits required to address all the byte addressable locations in the primary memory. 14 bits is basically the size of the address.
This was amazing. Thanks a lot
Keep going man u r awesome ! : )
Super helpful! Thank you so much!!!!!!!!
A computer support a virtual memory of memory of 1 giga byte and physical memory of 64maga byte how many bits are needed to address the
Excellent tutorial
8-bit = 1 byte , 16-bit = word , 32-bit = doubleword, 64-bit = quadword
Pls tell me what is mean of 512MW? hiw many wors in 512MW and in 256KW.
Estail Se ,
256 KW - 256*2^10 words.
512 MW - 512*2^20 words.
256 GW - 256*2^30 words.
512 TW - 512*2^40 words
you are excellent!
Where is the full course on computer organisation
you are using the word 'bits' instead of 'word' at certain places.
Thank you very much.
Well understood
Thank you sir =)
Thank you
why u stop making videos on gate
4096 in binary has 12 zeros
thanks
grt
Bro difference between address and location plz
7.41 min..... 12 zero.
thank you