Gate Computer Organization-12 | Byte and Word Addressing

[@thierry9592]

thank you. somehow i completely missed what a word is during my years in college and this explained it clearly. :D

[@S24W2]

I love the way Indian people say "which is nothing but..." !lol my Indian friends always use this expression. good video btw.

[@ex0stasis72]

Or when he says, "This is a memory." Ah, those were some good memories, weren't they?

[@Baba-so6fh]

@@ex0stasis72 lol

[@Ryan-nl1wu]

I think there might be a mistake at around 7:36. To represent 4096 as an unsigned integer you'd need at least 13 bits (2^12

[@adhamamiin9528]

That is correct, thanks for highlighting the noticed slip. However, I believe it is an honest flaw.
You have a reasonable point.

[@mandcali7613]

It should be 4095 = 12binary digits of 1. Then add 1 (zero location) to make 4096 total.

[@codexAbhi007]

thats not the case you didn't get it. 4096x32 signifies 4096 total memory addresses and index starts from 0 so it will go upto 4095 so basically 12 bits are only required as 4095 is the last index

[@lordnk3698]

man you are a lifesaver thank you

[@virendraverma5855]

Thank you sir you solved my problem 👍

[@Dexilic]

Truly a wonderful explanation!

[@LNTraCricEd]

At 15:20 :- so, bit addressable memory means, we require 16,15, 12 and 15 bits respectively.. is it right?

[@damejelyas]

7:58 you are mistaken it is accually 1 flowed by 12 zeros which is equal to 4096

[@madhawagamage1036]

great video,can you add this "how to identify memory capacity by used number of bits/bytes"

[@bhashithaviduranga6207]

thank you soo much..Excellent tutorial!

[@yugrawal5541]

sir, at 8:37 you wrote 2^14.. it is bytes not bits ..... in bits format the answer would be 2^(12+5)=2^19 bits I suppose.
and thanks for the lecture it was awesome :-)

[@abhrodeepdas7225]

14 bits indicate the number of bits required to address all the byte addressable locations in the primary memory. 14 bits is basically the size of the address.

[@VikasSharma-wb9mx]

learning made tough

[@thebulletkin8393]

So the word size, is that essentially the maximum length that the address of that memory cell can be?

[@ahmetsguney]

Excellent tutorial!

[@Hippelala]

very great lecture. Thank you!

[@aymannasr1323]

Keep going man u r awesome ! : )

[@saugatkarki3169]

Super helpful! Thank you so much!!!!!!!!

[@amnashafqat7936]

Verry very good explaimed

[@albertonavarrete8230]

8-bit = 1 byte , 16-bit = word , 32-bit = doubleword, 64-bit = quadword

[@SumbaSlice]

This was amazing. Thanks a lot

[@enas_trelos]

Excellent video!

[@guliyevshahriyar]

Thank you very much.

[@jishankhan6686]

You are super. Plz make us clear about if 4gb memory then how many word would be their

[@rjl7655]

what address is the power supply located at?

[@someone-yw2qw]

where did 4096 come from

[@someone-yw2qw]

does it mean the ram is 4KB ?

[@HamSupZhai]

no. 4gb

[@bsce100]

ok, but how did he come up with 4096?

[@TheFlyguy31]

2^12 = 4096. 8 bits x 4 =32 bits. 32x8=256. 256x4= 1024. 1024x4 = 4096

[@catlord69]

i think he asked for this = he just made it up... something like: "let's say i have memory with 4096 words"

[@菜花农农在北欧]

you are excellent!

[@aartipareek6611]

A computer support a virtual memory of memory of 1 giga byte and physical memory of 64maga byte how many bits are needed to address the

[@hotlincoln1]

Where is the full course on computer organisation

[@NeoStreamLive]

Pls tell me what is mean of 512MW? hiw many wors in 512MW and in 256KW.

[@TheFlyguy31]

Excellent tutorial

[@popoporifox4229]

Thank you sir =)

[@c.danielpremkumar8495]

you are using the word 'bits' instead of 'word' at certain places.

[@rasika123ish]

Thank you

[@vikramank4521]

Well understood

[@omar_bayazeed]

thanks

[@InPic]

why u stop making videos on gate

[@timgoppelsroeder121]

4096 in binary has 12 zeros

[@GrowwithShadow]

grt

[@souravpramanik1547]

7.41 min..... 12 zero.

[@bloodshot2558]

Bro difference between address and location plz

[@ARUNSINGH-es8eh]

thank you