Python Program to Find Armstrong Number in an Interval - Complete Guide

In this video, learn Python Program to Find Armstrong Number in an Interval - Complete Guide. Find all the videos of the 100+ Python Programs Course in this playlist: • Python Program to Add ...
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[@UmeshKumar-uy6we]

def armstrong_number(number):
alpha=sum(int(item)**len(str(number))for item in str(number))
return alpha
def armstrong_sum_in_an_interval(a,b):
armstrong_number_int = []
for i in range(a,b+1):
if armstrong_number(i) == i:
armstrong_number_int.append(i)
return(armstrong_number_int)
# case for finding in interval (25,134)
print(f"armstrong in given interval is:{armstrong_sum_in_an_interval(25,154)}")

[@rockyharrison8881]

Thank you so much for this video 📸

[@SerendipitySage29]

but what if the range is from 1 to 1000 , its showing 1 to 9 in the output?

[@TravelandTell]

Ver Helpful........Thanks for sharing....big like 43

[@minecraftkhanboy3738]

Sir payload ko phone m kaise copy kre

[@shortsgaming9337]

Nice video Dedi

[@sscode3809]

Mam python me ek function ke aunder kitne function define kar sakate hai please tell me

[@sscode3809]

Mam bataye please

[@__Atif_7190]

Mam but 1 to upper print kar rahe hai tou tou 1 to 9 bhi print hu rahe hai but 1 to 9 is not an Armstrong number??

[@snewkid9590]

The above code is not well structured , use this:
def is_armstrong(number):
num_str = str(number)
num_digits = len(num_str)
armstrong_sum = sum(int(digit) ** num_digits for digit in num_str)
return armstrong_sum == number
def print_armstrong_numbers_in_range(start, end):
print(f"Armstrong numbers between {start} and {end}:")
for num in range(start, end + 1):
if is_armstrong(num):
print(num)
start_range = int(input("Enter the start of the range: "))
end_range = int(input("Enter the end of the range: "))
print_armstrong_numbers_in_range(start_range, end_range)

[@rehanclasher115]

One to nine are also called armstrong numbers dude

[@__Atif_7190]

@@rehanclasher115 Yes brother you are right 👍

[@puneetraghavable]

Sir devops ke lie video bnao from bigning

[@soniskc2545]

1 is armstrong number or not?

[@ankurgupta6124]

m getting the outputs like 125, 153 ,216, 371, 729 for same code
lower = int(input('Enter the lower limit:'))
upper = int(input('Enter the upper limit:'))
for num in range(lower, upper+1):
order = len(str(num))
sum = 0
temp = num
while temp>0:
digit = temp%10
sum = sum+digit**order
temp//=10
if num == sum:
print(num)

[@akashkhan5264]

First like me bro

[@shoaib4x533]

Kachra h. Bro

[@SagnikDas-fb4st]

Thik bujhlam na didi

[@GoogleAndroidSmart]

💅💅💅💅💅💅💅💅💅