278. First Bad Version || LeetCode Placement Series || Explained in HINDI

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  • Опубліковано 9 лют 2025
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    Approach:
    1) The function firstBadVersion finds the first bad version in a sequence of versions using binary search.
    2) We define two pointers:
    left = 1, representing the first version.
    right = n, representing the last version.
    3) The function repeatedly finds the middle version (mid) and checks if it is bad using isBadVersion(mid):
    4) If mid is a bad version, then the first bad version must be at or before mid, so we move right to mid.
    5) Otherwise, the first bad version must be after mid, so we move left to mid + 1.
    6) The loop continues until left == right, which points to the first bad version.
    7) The function returns left, which is the first bad version.
    Time Complexity:
    O(log N), where N is the number of versions.
    The function halves the search space in each iteration, making it logarithmic in complexity.
    Space Complexity:
    O(1), as only a few integer variables (left, right, mid) are used, requiring constant space.
    Whether you're new to problem-solving or seeking insights into Java programming techniques, this video offers valuable insights into tackling similar challenges effectively.
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