nooooooooooooooooo! so many way, way, waaaaaaaaaaaay more talented math people than me. that is not just modesty : ) only the truth. but thanks all the same : )
thanks to you PatricJMT, i have an A in calculus and let me say, i have one of THE HARDEST, most TOUGHEST professors at my college.. but you make everything so understandable and straight forward. thank you sooo much!! i hope you teach up to multivariate calculus and linear algebra!!
You're awesome man! Thank's for turning what could have been a night-long search on how to use logarithmic differentiation into an 8 minute video on all the little things I had forgotten. Kudos. :)
Thank you for that comment about the (variable)^variable. That was always the thing that I couldn't get when trying to know when logarithmic differentiation is necessary.
some dude was like, you know what I'm gonna do, I'm gonna invent a method to make a computer, but not only am I gonna use non-English, I'm gonna make it with unknown symbols and unintuitive greek to make it universal... even though that makes it harder for the local people to know
Not hard Just need to learn the separate components Its alot if u dont know conponents Pretty simple with regards to the solution Nothing to stress about unless u havent taken college algebra
Thank you so much for helping me get through my exam in less than two days :D. I've watched every video from basic rules all the way towards this and it has helped me A LOT.
Where has this channel been hiding? Great videos! Within like 3 hours of bingeing your videos think I'm a little more equipped than before in calculus. Thanks a lot bro.
After every Calculus lecture I watch your videos to gain a greater understanding of the subject being taught. ~Thank you for these videos to help me learn and enjoy the wonderful beauty of Calculus!
your explanations are consistently well done, easy to follow. It's as though you never forgot what it was like trying to learn calc. .JK CTY is dead on! you're saving lives!
Thank you for posting these videos! I'm taking my math courses online and it's been more than a few years since I have been involved in any kind of math. Your videos are a tremendous help!!!
If I ever had to teach calculus - I would watch your videos and then just mimick everything that you say and do down to the T !! thank you for helping soo many of us pass and even start to enjoy Calculus
Hey Patrick. I like this technique and find it really useful. I would just like to provide the explicit way of doing this derivative, using multivariable calculus, in case you or anyone else reading was curious. First you rewrite y=ln(x)^x as y=u^v, where u=ln(x) and v=x. You then use the chain rule -- ∂y/∂u(du/dx)+∂y/∂v(dv/dx) -- and you will find your derivative to be ln(x)^(x-1)+ln(ln(x)) ln(x)^x, which (after factoring out ln(x)^x) is the answer you got. Thanks for reading! :)
i used to be scared of logarithmic differentiation... i always skipped problems if i saw a ln or an e. thanks to your explanations, i now appreciate them as a shortcut and am not so intimidated :))
@green1375 you multiply by y on the left side to cancel it out, and multiply it also on the right hand side. but because you want all your terms in x, you sub in the value of y which would be the original question.
Thank you soo much. I have a Calculus midterm tomorrow or rather later today and this was a good review of the material and actually shed light where I was confused on.
This is for others who might be wondering : He isn't using the power rule. It's simply a property of logarithms. Bringing the exponent of the term that you are taking a logarithm of: ln(x)^10 = 10 ln(x)
i visited your website... i have to say, you have an impressive amount of videos. I've only watched a few of your videos but i do think they may be able to help me for when i sit my IGCSE addmaths exam. So, "thankyou" in advance:)
Thanks =D, my teacher made this seem a lot harder than it really was.I am thankful that I still have several months before I take the actual AP exam (so I can also use videos like these to help me).
Essentially it is the product rule. If we were to use the product rule, then take the derivative of 10 is zero multiply but g(x) which is just zero+ whatever. It's faster to just kind of do that part in your head.
There is another way in the second problem without using log differentiation. You can change the base ln(x) to base e. The function (ln(x))^x can be rewritten as e^(ln(ln(x))*x)=e^(xln(ln(x))). Then, differentiate this function using the chain rule and go from there. It will end up the same answer.
it's 2019! still you are saving lives! I thank you Sir!
FORREAL!
It's also 2020... 12 yrs old but still need to mention one of the best math teachers on UA-cam..
2022 and he still popping off
It's 2024 and it's still saving lives!
Got a 97 on my calculus one test because of you, i had to miss two classes and watching your videos really helped to catch me up! Thanks.
it's 2016! still your saving lives! I thank you Sir!
2017 now :) This guy is my private math tutor
Now it’s 2018. and STILL saving lives. 😂
and now its 2019, but still saving lives
It's 2017 and you're still saving lives! I thank you Sir!
18
19
22
And cramming for finials just got a little easier, thanks man.
I gave up on the one problem I was working, then I watched this video and regained the confidence to complete mines....and I got it right!!!!!!!!!!
The compilation of views from all of your videos may actually prove you to be the most helpful math man in the world. Good work and thank you!
Cheers
nooooooooooooooooo!
so many way, way, waaaaaaaaaaaay more talented math people than me. that is not just modesty
: ) only the truth.
but thanks all the same : )
thanks man, you just saved another student's life today
thanks to you PatricJMT, i have an A in calculus and let me say, i have one of THE HARDEST, most TOUGHEST professors at my college.. but you make everything so understandable and straight forward. thank you sooo much!! i hope you teach up to multivariate calculus and linear algebra!!
You're awesome man! Thank's for turning what could have been a night-long search on how to use logarithmic differentiation into an 8 minute video on all the little things I had forgotten. Kudos. :)
Thank you for that comment about the (variable)^variable. That was always the thing that I couldn't get when trying to know when logarithmic differentiation is necessary.
Thnx it's helpful
Which devil invented this
Zohal H are you a stem student
some dude was like, you know what I'm gonna do, I'm gonna invent a method to make a computer, but not only am I gonna use non-English, I'm gonna make it with unknown symbols and unintuitive greek to make it universal... even though that makes it harder for the local people to know
Not hard
Just need to learn the separate components
Its alot if u dont know conponents
Pretty simple with regards to the solution
Nothing to stress about unless u havent taken college algebra
Thank you for making me lmao.!
@@jqyhlmnp Not sure, but I think "Logarithms" originated from Arabs and Indians. Do correct if I am wrong.
2018 still saving lives.
2020 still saving lives.
2021 still saving lives
I wonder how many of us would fail calc2 if it weren't for you...
You're a lifesaver. Thanks again!
plz keep posting these vidoes, i have improved alot in my calc class just from watching these videos. your the best teacher ever.
This man is literally saving my college GPA! THANK YOU!
Your videos are saving my sanity. Thank you for relieving many of us from depression.
"Hello everyone, this is YOUR daily dose of logarithmic differentiation"
how bout that cat stealing chicken nuggets tho
Thank you so much for helping me get through my exam in less than two days :D. I've watched every video from basic rules all the way towards this and it has helped me A LOT.
Where has this channel been hiding? Great videos! Within like 3 hours of bingeing your videos think I'm a little more equipped than before in calculus. Thanks a lot bro.
happy to help. spread the word.
hiding in plain sight :)
there already are links if you click on any video link on my site ;)
you saved my life
After every Calculus lecture I watch your videos to gain a greater understanding of the subject being taught.
~Thank you for these videos to help me learn and enjoy the wonderful beauty of Calculus!
your explanations are consistently well done, easy to follow. It's as though you never forgot what it was like trying to learn calc. .JK CTY is dead on! you're saving lives!
You have quite possibly the most useful channel on UA-cam
Thank you for posting these videos! I'm taking my math courses online and it's been more than a few years since I have been involved in any kind of math. Your videos are a tremendous help!!!
If I ever had to teach calculus - I would watch your videos and then just mimick everything that you say and do down to the T !! thank you for helping soo many of us pass and even start to enjoy Calculus
It's 2018 and you're still saving lives thank you sir !
@pinkybill2003 the derivative of a constant is zero - you can always use the product and see that you get the same thing
The first problem you did was literally the same problem I have to do for homework haha. This was a great help, thank you!
it's 2020! still saving lives.
Thank You very much!
you are the best math teacher, hands down, got a 96% on my calc midterm thanks to you!
This video is over 5 years old and it still helps people!
@RandomGuy shit's crazy
derivative on ln(x) is always 1/x, yes.
2021 you're our saviour, definitely helped me. Hope you are staying safe
You the MVP
Myung Jeon You should have said MVT (Mean Value Theorem).
*shivers in the corner*
+Myung Jeon no its *JMT*... patrickJMT
Hey Patrick. I like this technique and find it really useful. I would just like to provide the explicit way of doing this derivative, using multivariable calculus, in case you or anyone else reading was curious. First you rewrite y=ln(x)^x as y=u^v, where u=ln(x) and v=x. You then use the chain rule -- ∂y/∂u(du/dx)+∂y/∂v(dv/dx) -- and you will find your derivative to be ln(x)^(x-1)+ln(ln(x)) ln(x)^x, which (after factoring out ln(x)^x) is the answer you got. Thanks for reading! :)
It's 2022 and still saving lives! I thank you Sir
no. if the problem had been ln [ x^x] then that would work, but not for [ ln x ] ^x ; the rule does not apply now
Only Patrick's terms get to "go along for the ride" or just stay "hanging out." Great work as always
Wow, you are sooooo much better than my Calc 2 professor. She absolutely sucks.
That's what she said.
Thank you thank you thank you!!!!! You teach better than some of our college professors!!!!
Coronavirus, still the best math doctor out there.
14 years later and this video is still helping people!
It's Corona, Year 2 and still saving lives!
it's 2020! still saving lives! I thank you, Sir!
' If you want to get rich, you start a religion' - Hubbard
@cowboyzfan713 there it is
Very clear video! Still helping 13 years later
Thank you so much. You always make math seem easy. Last semester I got B+ because I was watching your videos.
Very Good explanation!!
its 2020 still saving lives. thank you sir
i used to be scared of logarithmic differentiation... i always skipped problems if i saw a ln or an e. thanks to your explanations, i now appreciate them as a shortcut and am not so intimidated :))
it's 2021! still you are saving lives! I thank you Sir!
You bet!
2020 STILL saving lives!
it's 3005! still your saving lives! I thank you Sir!
no problem!
omg this is the best type of this video I've ever seen. you have my sub sir
Patrickjmt is my savior!!!! Thanks for helping me get an A in my calculus class...heh is awesome.
you are the best teacher i never had.
@green1375 you multiply by y on the left side to cancel it out, and multiply it also on the right hand side.
but because you want all your terms in x, you sub in the value of y which would be the original question.
@Spiceman333 derivatives of exponential functions
Thank you soo much. I have a Calculus midterm tomorrow or rather later today and this was a good review of the material and actually shed light where I was confused on.
more important than saving my life, you saved my gpa! if you're ever in vancouver message me i'd like to buy you a beer!
I had been struggling to figure out logarithmic differentiation and this really helped, thanks!
It's 2018.. Still your saving lives... Really thanx
my pleasure :)
I love calculus! My teacher is as good as you are to teach differentiation, so he makes me understand everything. It's my absolute favourite class :)
This is for others who might be wondering : He isn't using the power rule. It's simply a property of logarithms. Bringing the exponent of the term that you are taking a logarithm of:
ln(x)^10 = 10 ln(x)
@patrickJMT you are my mathematical hero
thank you so much my teacher ,
always when I've faced any problems in math , I returned to your amazing videos ❤❤❤❤
I love your problems cause they are the same ones that get put on tests.
how do u write that as a product?!
bro...bro....bro!!! *bows* your awesome!
@sulmazz glad i could help : )
i visited your website... i have to say, you have an impressive amount of videos. I've only watched a few of your videos but i do think they may be able to help me for when i sit my IGCSE addmaths exam. So, "thankyou" in advance:)
Thanks =D, my teacher made this seem a lot harder than it really was.I am thankful that I still have several months before I take the actual AP exam (so I can also use videos like these to help me).
i wanna be like you man. you make me lose my hate for maths. thanks. you're a genius
your videos are a bliss to my upcoming tests xD
You're a great teacher. Thank you!
Thank you! I really love these videos! and you are extremely helpful!
@XangelkatzX i always try to use jedi mind trick to pick up the pen with my mind, but it has yet to work.
m ryting my test in a few hours from now....m glad i saw this b4 ryting!tnxalot!
your videos are so helpful!!!!
THANK YOU! You helped me understand everything I dont understand from my teacher! :)
3:17 you differentiation the x^2. But not the 10. Something seems wrong and inconsistent there
thanks!
Essentially it is the product rule. If we were to use the product rule, then take the derivative of 10 is zero multiply but g(x) which is just zero+ whatever. It's faster to just kind of do that part in your head.
Substituting back in the original y is where I was stuck. Thank you!
Hey Pat, you should totally put this in your first semester Calc playlist! Thanks for all the help!
sure! happy to help : )
@vehiclerandomvideos you use logarithms. i should have videos on solving exponential equations somewhere if you do a search on my videos on my channel
i knew it would be on there! that is why i made this!
Thanks, your lessons help me study a lot. I wished I had found these videos a lot earlier. I would of catch up on my math much faster.
man!!! this video was so reliable and well explained... thanks!!!
Such A BAAWS! these vids are 10 times better than my teacher
you have such neat handwriting..and this totally made things clear. thanks=)
There is another way in the second problem without using log differentiation. You can change the base ln(x) to base e. The function (ln(x))^x can be rewritten as e^(ln(ln(x))*x)=e^(xln(ln(x))). Then, differentiate this function using the chain rule and go from there. It will end up the same answer.
"My 10's along for the ride"
I like how you word things.
Thank you SO SO MUCH! Your videos are getting me through college!!