Forgive my impertinent question. It seems reasonable to say that a 2.5kg ball is falling at a velocity of 12.5 meters per second, but if it is dropped from 8m, isn't it unlikely that it could fall faster than 9.81 m/s in one second? It has only fallen 8 meters and hasn't even fallen for a whole second yet. Can a graph be made to show speed and distance together?
+chris thomson Sorry I did not answer earlier I was out of town for a week. Do the math to calculate the time it would take to fall 8 m. You can see a listing of all my videos at my website, www.stepbystepscience.com
+jospin lionel Thanks for your comment. I do need to make some videos about momentum and collisions but have not done them yet. You can see a listing of all my videos form my website at www.stepbystepscience.com
When you rise something at a constant velocity then the applied force is equal to the force of gravity. Theta is tha angle between the force and the direction of motion. You can see a listing of all my videos at my website, www.stepbystepscience.com
+Faisalkhan Sasoli The height and the change in the y are the same thing. In this example 8m is the vertical height of the stairs it is not the "length" of the stairs. I can see now that this could be a little confusing from the diagram. You can a listing of all my videos from my website, www.stepbystepscience.com
2:45 isn't the angle for the cos theta supposed to be the angle between direction of the two forces which are the applied force(Fa) and the force of gravity(Fg) ? so it should be cos180
GPS??? do you mean gravitational potential energy??? GPE = mgh, h for height. Right beofre it hits the ground the height is basically zero (0 m). Therefore the GPE is 0 Joules. You can see a listing of all my videos at www.stepbystepscience.com
ISn't the final velocity of the ball after it's dropped is ZERO ??? because velocity ceases to exit after it hits the ground !! or final velocity should be named the velocity in progress . in this case the progress of initial let go of the ball and the momentum it gains before hitting the floor . Please someone could explain to me ?? THANK YOU IN ADVANCE !
+kasra2003 Sorry I did not answer earlier but I was out of town for a week. When something is falling we take the final velocity to be the velocity just before it hits the ground and stops. You can see a listing of all my videos at my website, www.stepbystepscience.com
These videos are amazing (!!!!!!) pieces of work and I want you to know how much I appreciate them!! Thank you!
Nice and simple way of explaining. I am glad you tried to incorporate all the concepts of work through this problem.
Awesome explanation, your chanel is radically helping me improve!! Thank you immensely
You are very welcome...did you subscribe?
your videos are so straight forward! thank you soo much
Thanks for watching and all the great comments.
Very helpful sir. Thumbs up!
wow!! sir, you are awesome!! Thank you sooooo much! please keep it up!!
Great vídeo thanks
great video!
awesome video
Awesome comment, You can see a complete listing of my videos at www.stepbystepscience.com
Again, your the best Doc. So thorough. Cheers. B :) :) :)
And again, thanks for watching. Thanks for the support!
thank you
+sumeeth yadav You are very welcome!
You can see a listing of all my videos at my website, www.stepbystepscience.com
Nice video
very helpful sir
+jospin lionel Thank you foir watching
You can link to all my videos at my website: www.stepbystepscience.com
can you do New explanations that contain calculus ?
wow....Thank you awesome
thanks for the comment. You can see a listing of all my videos at my website, www.stepbystepscience.com
Like it...
Forgive my impertinent question. It seems reasonable to say that a 2.5kg ball is falling at a velocity of 12.5 meters per second, but if it is dropped from 8m, isn't it unlikely that it could fall faster than 9.81 m/s in one second? It has only fallen 8 meters and hasn't even fallen for a whole second yet. Can a graph be made to show speed and distance together?
+chris thomson Sorry I did not answer earlier I was out of town for a week. Do the math to calculate the time it would take to fall 8 m. You can see a listing of all my videos at my website, www.stepbystepscience.com
Great video, it makes so much more sense!
Thank you, this really helped me with my physics
Thank you so much!!!
can you create a video about collision mouvemnt please?
+jospin lionel Thanks for your comment. I do need to make some videos about momentum and collisions but have not done them yet.
You can see a listing of all my videos form my website at www.stepbystepscience.com
thanks!!!
you can see a listing of all my videos at my website, www.stepbystepscience.com
wooow it helps me thank you
+Kaled Ab Woooooow, you are welcome. You can see a listing of all my videos at my website, www.stepbystepscience.com
thank you so much
very helpful! thanks :-)
Pour Stephane et Antoine qui ont fait de la physique...
Thank you very much :^)
how do you know if the applied force equals gravity? also, how do you determine theta?
When you rise something at a constant velocity then the applied force is equal to the force of gravity. Theta is tha angle between the force and the direction of motion. You can see a listing of all my videos at my website, www.stepbystepscience.com
tks
You are welcome!
Can we use sin(theta) for the angle of work?
+Faisalkhan Sasoli I would have to say "No".
+Faisalkhan Sasoli You can use sin(theta)*cot(theta) (;
You should come teach at my school please
!
where do you go to school? i teach in Berlin Germany.
+Brian Swarthout Sir why didn't you put height in the formula of work instead of putting ∆y?
+Faisalkhan Sasoli The height and the change in the y are the same thing. In this example 8m is the vertical height of the stairs it is not the "length" of the stairs. I can see now that this could be a little confusing from the diagram. You can a listing of all my videos from my website, www.stepbystepscience.com
+Brian Swarthout No sir this question is not according to this topic.
+Brian Swarthout I know here in this topic mass of body covers distance in y.axis.
2:45 isn't the angle for the cos theta supposed to be the angle between direction of the two forces which are the applied force(Fa) and the force of gravity(Fg) ? so it should be cos180
just kidding i was wrong
No problem
You can see a listing of all my videos at my website, www.stepbystepscience.com
How do you find out how much GPS something has just before it hits the ground?
GPS??? do you mean gravitational potential energy??? GPE = mgh, h for height. Right beofre it hits the ground the height is basically zero (0 m). Therefore the GPE is 0 Joules.
You can see a listing of all my videos at www.stepbystepscience.com
Lol started laughing in the first 30 sec.
Why?
WHY DID YOU LEAVE ME?
WHY???
PAPA NEEDS HIS RAVIOLI
ok
Oh sorry I didn't think you would see that.
Great vid by the way.
Here's what I was talking about: ua-cam.com/video/NWoyTD27kFs/v-deo.html
you sound like vince vaughn
But I'm better looking! and don't forget.....you can see a listing of all my videos at my website, www.stepbystepscience.com
K
L
ISn't the final velocity of the ball after it's dropped is ZERO ??? because velocity ceases to exit after it hits the ground !! or final velocity should be named the velocity in progress . in this case the progress of initial let go of the ball and the momentum it gains before hitting the floor . Please someone could explain to me ?? THANK YOU IN ADVANCE !
+kasra2003 Sorry I did not answer earlier but I was out of town for a week. When something is falling we take the final velocity to be the velocity just before it hits the ground and stops. You can see a listing of all my videos at my website, www.stepbystepscience.com
what ever