31. Convolution Theorem | Complete Concept and Problem#1 | Inverse Laplace Transform

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Topics covered under playlist of Laplace Transform: Definition, Transform of Elementary Functions, Properties of Laplace Transform, Transform of Derivatives and Integrals, Multiplication by t^n, Division by t, Evaluation of Integrals, Inverse Laplace Transform, Convolution Theorem, Unit Step Function, Unit Impulse Functions, Periodic Function, Application to Solution of Ordinary Differential Equations
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[@anushkakrishna2829]

2sinAcosA=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)+cos(A-B)
2sinAsinB=cos(B-A)-cos(A+B)

[@hafizmuhammadosamahasssan1330]

*2sinAcosB = sin(A+B)+sin(A-B)
*2 sinAsinB = cos(A-B)-cos(A+B)

[@basavarajhallikeri2602]

Love u

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Thank you sir

[@subratabiswas964]

yes sir

[@subhashreesahu692]

the students must be blessed in which institute you teach.. thnx for all lessons sir.

[@fanfsty.]

I have followed each and every video of yours regarding this chapter since the beginning and the results are quite good so far. Bunch of thanks 🙏🏻 sir

[@eternalknight2958]

2 cos(a) sin(b) = sin(a+b) - sin(a-b) , thank you sir for your work

[@moumitamog4167]

You're videos are short and can be easily understood .
Thank you sir .

[@pratyush2331raj]

2.SinA.CosB = Sin(A+B) + Sin(A-B)
2.CosA.SinB = Sin(A+B) - Sin(A-B)
2.CosA.CosB = Cos(A+B) + Cos(A-B)
-2.SinA.SinB = Cos(A+B) - Cos(A-B)

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[@priyanshuchaturvedi3706]

2sin(a)cos(b)=sin(a+b)+sin(a-b)
2cos(a)sin(b)=sin(a+b)-sin(a-b)
2cos(a)cos(b)=cos(a+b)+cos(a-b)
2sin(a)sin(b)=cos(a-b)-cos(a+b)

[@Code__king-u4n]

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Haina ❤😂

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Thank you so much for making this video❤

[@visweshvaranraamakrishnan2697]

thank you sir🙏🙏

[@abhinandanjain2399]

Thank you so much sir ji 🙏

[@NITSRINAGAR786]

2cosAsinB=sin(A+B)-sin(A-B)

[@deepakkumarmohanty6182]

2CosA.SinB=Sin(A+B)-Sin(A-B)

[@NITSRINAGAR786]

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[@rakhipikopiko1467]

Thanks to the right place

[@mukundhanthanigaimurugan9253]

Good experience

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Thank you🙏 but is it possible for you to change your videos to English?

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Sir can you plz make videos on linear algebra.

[@suhanaprajapat7769]

Yes

[@dr.rahulgupta7573]

सर,Laplace transform सीखने के लिए कौन सी किताब पढ़ें ?

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2sincos=sin+sin

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I can't understand hindi it will fyn if u teach fully in English

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[@umeshsilk9500]

2.SinA.CosB = Sin(A+B) + Sin(A-B)
2.CosA.SinB = Sin(A+B) - Sin(A-B)
2.CosA.CosB = Cos(A+B) + Cos(A-B)
-2.SinA.SinB = Cos(A+B) - Cos(A-B)

[@dinkark98]

2sinAcosB =sin(A+B)+sin(A-B)
2cosAsinB =sin(A+B)-sin(A-B)
2cosAcosB =cos(A+B)+cos(A-B)
2sinAsinB =cos(A-B)-cos(A+B)

[@abhinandanjain2399]

Thank you so much sir ji 🙏

[@Rajanandz]

2cosA.sinB = sin(A+B) - sin(A-B)

[@rashikaverma5261]

Thank u sir

[@Sunilkumar22341]

Thanks sir

[@letsdestroy8624]

Yes

[@vdo9372]

2sinAcosA=sin(A+B)+sin(A-B)
2cosAsinB=sin(A+B)-sin(A-B)
2cosAcosB=cos(A+B)+cos(A-B)
2sinAsinB=cos(B-A)-cos(A+B)

[@AkohbaThonger]

2cosAsinB = sin(A+B) + sin(A-B)

[@nissahgkvideos2112]

Thank you sir

[@fallacyfallacy1634]

2cosAsinB=sin(A+B) + sin(A-B)
2cosAcosB=cos(A+B) + cos(A-B)
2sinAcosB=sin(A+B) + sin(A-B)
2sinAsinB=cos(A-B) - cos(A+B)

[@AaryaPathak-gm6ft]

2sinAsinB=cos(A-B)-cos(A+B)
2cosAcosB=cos(A+B)+cos(A-B)
2sinAcosB=sin(A+B)+sin(A-B)
2cosAsinB =sin(A+B)-sin(A-B)