Since C is a constant, the sign doesn't matter. We typically make all of our constants positive. If I choose Ce^(-2x) and you were to choose -Ce^(-2x), we'd get the same answer in the end. The difference would be that our C values would have opposite signs. For example, I might get C=2 and you'd get C=-2.
Very clear explanation.Thank you
Thank you so much Luke! Your present is very important for me. Love from UMN
The way u pretended to do mistake naturally 🔥❤
The process was well explained. Thank you
Thanks so much sir you solve my problem.
Thank you for that mistake, it helps to be cautious surely. God bless you.
Thank you sir🎉🎉🎉❤❤❤❤❤
The second problem was a long story 😂❤️
I think you Yp should be Ax+B-Ce^(-2x).
Since C is a constant, the sign doesn't matter. We typically make all of our constants positive.
If I choose Ce^(-2x) and you were to choose -Ce^(-2x), we'd get the same answer in the end. The difference would be that our C values would have opposite signs. For example, I might get C=2 and you'd get C=-2.
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Miller Eric Jones Shirley Martin Dorothy
This is kinda confusing