ANOVA Testing (Given Mean and Standard Deviation; Question 2)

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Q. A researcher studying genetic influences on learning compares the maze performance of four genetically different strains of mice, using eight mice per strain. Performance for the four strains were as follows:
Using the .01 significance level, is there an overall difference in maze performance among the four strains?

[@thisismecindy]

It's crazy how hard it was to find anova test examples where you aren't given any data. Thank you for this video

[@rosaleejarrett8048]

Omg you just saved my life!!! Every other video had the data. Thank you!!!!

[@denys239]

Thank you so much, It helped a lot.

[@iamfleetw6622]

does the same approach apply if the groups have different sample sizes? if j had 9, m had 8, q had 11, and w had 13?

[@maheshvernekar8915]

Well explained .

[@tylerchelston7270]

This came in handy! thank you!

[@maryamshamsaei1485]

this was amazing . thank you😍

[@dusanprodanovic557]

Can we do post hoc test based on those results? With only means and SD? Tukey for example? Very nice video btw!

[@StudyForceOnline]

Absolutely, take a look @ our Tukey example: ua-cam.com/video/U3NUHr3O4wI/v-deo.html

[@dusanprodanovic557]

@@StudyForceOnline Thank you :)

[@adhoccerswings]

Thanks!
Question! When multiplying / dividing datasets (unfortunately it's unknown if independent or not), how do the standard deviations (or variances) behave?? I know that when multiplying by a constant, the stdev is also multiplied, and when adding or subtracting, Var(X+Y)=Var(X)+Var(Y) so sqrt(X^2+Y^2) is the new stdev. But what about multiplying...

[@memodowidar]

Thanks

[@dagobertopulido7650]

Can i do the same using t student distribution?

[@StudyForceOnline]

No, you cannot because we have multiple groups being compared at once.