A Controversial Maths Video.

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  • Опубліковано 16 кві 2024
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    Today we will show that circles and infinite sided polygons do indeed have a thing or two in common :) Let's solve some spicy limits and calculus, shall we? Enjoy! =D
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КОМЕНТАРІ • 75

  • @DatuxGames
    @DatuxGames Місяць тому +134

    Most polygons are just finitely sided circles

    • @PapaFlammy69
      @PapaFlammy69  Місяць тому +45

      brave

    • @genos1458
      @genos1458 Місяць тому +2

      Damn 😂

    • @angeldude101
      @angeldude101 Місяць тому +2

      This also means that polygons have circumferences and that attempting to correct a past word choice was pointless.

    • @johnacetable7201
      @johnacetable7201 Місяць тому +1

      Bruh

    • @joelklein3501
      @joelklein3501 15 днів тому

      Your mama's ass is just two finitely faced hemispheres

  • @HugoLHL
    @HugoLHL Місяць тому +34

    Lines are just circles of infinite radius so polygons are just collections of arcs of circles but also circles are collections of arcs of circles qed

    • @yonaoisme
      @yonaoisme Місяць тому +1

      all of them are just boundaries of convex sets

    • @gustavgnoettgen
      @gustavgnoettgen Місяць тому +1

      ​@@yonaoismeWhat if they're concave?

  • @thes7274473
    @thes7274473 Місяць тому +26

    This was one of the first things I independently discovered back in high school. It was one of the early things that helped establish my love of mathematics.
    I realized that a regular n-gon can be cut into n isosceles triangles and so I derived the relationship between the apothem (radius of the incircle) and the area and found it to be A = a² n tan(π/n). And the limit as n→∞ of n tan(π/n) is π. I later discovered that the perimeter is also given by p = 2n tan(π/n). For an interactive demonstration, see Desmos graph 6ijb6uc1yu

    • @Kloppin4H0rses
      @Kloppin4H0rses Місяць тому +1

      Suuuurrrreee buddy. Sure

    • @himanbam
      @himanbam Місяць тому +5

      @@Kloppin4H0rses No high schooler has ever taken a calculus class / liked doing math in their free time

    • @friender6886
      @friender6886 Місяць тому

      By the end of senior year in high school, I too discovered this problem. I am now a first-year math major. How cool! Being in calculus at the time, I also realized that the integral of our result yielded the formula for the area of a circle as well.

    • @symphonyofsolidarity
      @symphonyofsolidarity Місяць тому

      Sameee :)

  • @advaitkamath8442
    @advaitkamath8442 Місяць тому +16

    Aren't infinte sided polygons are called aperigons, they have the exact same properties as a circle, with the same area, the only difference is that they have interior angles which eachone 180 degrees, while a circle has none

    • @soupisfornoobs4081
      @soupisfornoobs4081 Місяць тому +4

      Apeirogons, from the greek word for infinite "Apeiro" (Άπειρο). And they're very cool

    • @Filipnalepa
      @Filipnalepa Місяць тому +1

      With world apeirogon you just reminded me of mind bending clip of jan Mislai about regular polihedra. Starts with platonic solids, somewhere in the middle we land in honeycomb apeirogon to end in some stellated net of pointy helixes.

    • @advaitkamath8442
      @advaitkamath8442 Місяць тому +1

      @@Filipnalepa I watched that one too!

    • @youtuberdisguiser6075
      @youtuberdisguiser6075 Місяць тому

      Not really, i agree the distance converges, but some points on the border of the circle will never be touched, since the border of the circle is uncountable yet the points of the infinigon are only countable infinite.
      For example lets go with aquidistant n-gon, the point on the border at the angle sqrt(2) will never be exactly touched by any n-gon.
      You could say you take a setunion integral, but that's cheating. And not n gon convergence

    • @Daniel-ef6gg
      @Daniel-ef6gg Місяць тому

      The difference is that, for a circle, every point on the circumference is a radial point, and there are uncountably many points on the circumference, whereas an apeirogon only has a countably infinite number of radial points.
      Also, polygons are kinky ;), circles aren't.

  • @Mystery_Biscuits
    @Mystery_Biscuits Місяць тому +5

    What a coincidence! I was just using this idea to prove the curved surface area of a cone formula (pi r l) from the limit of an n-gon based pyramid. Very cool!

  • @10-year-oldcalculus19
    @10-year-oldcalculus19 Місяць тому +8

    Good to know

  • @winteringgoose
    @winteringgoose Місяць тому +2

    "We're going to start off with a square." *draws a kite*
    Love the vids, keep up the good work!

  • @jack002tuber
    @jack002tuber Місяць тому +1

    I did this last March on PI day. I calculated a/2 by splitting the triangle and made two right triangles and solved for a/2 using law of cosines. Try it, I think it's easier.

  • @destinlol277
    @destinlol277 Місяць тому +5

    Let's go another video

  • @ricardoparada5375
    @ricardoparada5375 Місяць тому +1

    I love seeing these arguments. Great video Flammy ma boi

  • @Katzeblow
    @Katzeblow Місяць тому +2

    My heart is boiling blood already, I'm shocked by the thumbnail 😢

  • @avinashbabut.n4123
    @avinashbabut.n4123 Місяць тому +1

    I love your videos. They make me enjoy math.

  • @wjalp
    @wjalp Місяць тому +1

    I love your videos papa! Looking forward for the next video!

  • @maxhagenauer24
    @maxhagenauer24 Місяць тому +1

    If you have a polygon and increase the number of sides, the perimeter will approach the circumference of a circle of the same radius and you can use this to compute digits of pi. 2^n * sqrt(2 - sqrt( 2 + sqrt (2 + ...) with n many square roots, plug in huge numbers for n to get a better approximation for pi.

  • @John-zx2ss
    @John-zx2ss Місяць тому +1

    What about substituting the Taylor series of cos instead of the double angle formula

  • @bachvaroff
    @bachvaroff Місяць тому

    ~12:22 ← one can also apply the Cesàro-Stolz theorem from that point on…

  • @gustavgnoettgen
    @gustavgnoettgen Місяць тому

    It's like saying that all reality happens in my head.
    Well, sort of. And this polygon is sort of a circle. And it sort of is not.

  • @douglasfalter2337
    @douglasfalter2337 Місяць тому +1

    Papaflammy papapaflammy6969 love your videos…we need a video/series on numerical methods ❤️❤️ atmospheric science rulez btw ✨

  • @TheGildedMackerel0
    @TheGildedMackerel0 Місяць тому

    I came up and did this problem a while ago in high school. very cool!

  • @Happy_Abe
    @Happy_Abe Місяць тому

    I don’t think using l'hospital would’ve been illegal here since a limit in a continuous variable x converging implies that it converges in the discrete variable of naturals n. The other way doesn’t work so we can’t use limits in n for limits in x but we can use limits in x for limits in n so we can use l'hospital for the x limit and then conclude it for this n limit as well.

  • @jasurmakhkamov
    @jasurmakhkamov Місяць тому +2

    Feels great to understand this stuff/see the solution just about before it happens. Thanks papa flammy for making us more smarter :D

  • @joelklein3501
    @joelklein3501 15 днів тому

    Alternative approache for the "cheatung" part
    sqrt(1-cos(2π/n)) =
    sqrt(1-cos(2π/n))*sqrt(1+cos(2π/n)) /sqrt(1-cos(2π/n))
    =
    sqrt(1-cos²(2π/n))/sqrt(1+cos(2π/4n) =
    sqrt(sin²(2π/n))/sqrt(1+cos(2π/n)) =
    |sin(2π/n)|/sqrt(1+cos(2π/4))
    for n >1 , 0 1,
    cos(2π/n) > -1
    So we can conclude
    sqrt(1-cos(2π/n)) =
    sin(2π/n)/sqrt(1+cos(2π/n))
    In conclusion
    L[ n*sqrt(2)*r*sqrt(1-cos(2π/n)) ] =
    L[ n*sqrt(2)*r*sin(2π/n)/sqrt(1+cos(2π/n)) ] =
    L[ r*sqrt(2)/sqrt(1+cos(2π/n)) ] * L [ n*sin(2π/n) ] =
    r * L[ 2π * sin(2π/n)/(2π/n) ] =
    2πr

  • @tszhanglau5747
    @tszhanglau5747 Місяць тому

    I derived that the area of regular polygons approach that of circles myself

  • @ivnsaw7422
    @ivnsaw7422 Місяць тому

    A circle is an infinitely cornered polygon without any sides

  • @gracebrehaut1102
    @gracebrehaut1102 Місяць тому

    Aperigon: 2 plus 2 plus 2 plus 2 plus 2 plus 2 plus 2 plus 2
    Numberblock 18: AHH!!!

  • @koenth2359
    @koenth2359 Місяць тому

    It's somewhat easier with a = 2rsin(π/n),
    so lim na= lim 2nr sin (π/n) = 2πr, using that lim sin x = x as x approaches 0.

  • @jimnewton4534
    @jimnewton4534 Місяць тому +2

    Is a perimeter a number or a set of edges?

  • @johnacetable7201
    @johnacetable7201 Місяць тому +1

    Well if 0.999...=1 it's not all that strange. Like there's a reason mathematicians avoided infinity for a long time, - it doesn't follow normal rules which makes it weird.

  • @Bobbel888
    @Bobbel888 Місяць тому +3

    Infinitely-Sided, already the interior .... :) :) :),

  • @Rafau85
    @Rafau85 Місяць тому

    Did I hear you cannot use l'Hospital for a sequence? You can do it. There is nothing wrong about it, if you can extend the sequence to a function.

  • @neutronenstern.
    @neutronenstern. Місяць тому

    its easier with a non regular polygon. you can always draw your polygon in a way, such that the edges are perpendicular to the radius. And then its just pythagoras. And if ypu take the inscribed polygon and compare it to the outscribed one,you will see, that they dont differ for n->∞.

  • @ChrisVenus
    @ChrisVenus Місяць тому

    Feels like you might have saved yourself a whole lot of working by just bisecting your triangle to give a right triangle and using sin(pi/n) = a/2r . so a = 2rsin(pi/n) . Then you take n lots of that to get 2rn*Sin(pi/n) and then solve the limit as you did...

  • @mighty8357
    @mighty8357 Місяць тому +1

    What I take from this video is that perimeter and circumference are the same thing!

    • @PapaFlammy69
      @PapaFlammy69  Місяць тому

      KInda ye, that's probably why I messed up the terms before XD

  • @emmettnelson7260
    @emmettnelson7260 Місяць тому +1

    I think polygons are a key to alot of things in math, I just used them to prove that sin^2(a+c) = sin(a)sin(b) + sin(c)sin(d) when a+b+c+d = pi

  • @encounteringjack5699
    @encounteringjack5699 Місяць тому

    Each side length of a circle is epsilon. One over omega. Some infinitely small quantity.
    But wait!
    Unpopular opinion, there is only one size of infinity. This means the idea of infinitely large and infinitely small quantities no longer make sense.
    Thus, a circle is not an infinitely sided polygon. However, it can be approximated as a polygon, getting an exact answer for the limit as the polygons side lengths go to zero. Precisely getting the circumference of the circle even though there are lengths involved, since they go to zero.

  • @Gabriel-tf5ws
    @Gabriel-tf5ws Місяць тому +1

    you said that using L'Hospital is not very clean, because we are dealing with discrete values. But if i'm not mistaken, to show that sin(x)/x approches 1 you also use L'Hospital and x is pi/n and therefore also discrete, so you run into the same problem

    • @PapaFlammy69
      @PapaFlammy69  Місяць тому +1

      Noone ever uses L'Hospital to prove this limit lol

  • @karthikk5384
    @karthikk5384 Місяць тому +4

    first papa flammy❤

  • @monishrules6580
    @monishrules6580 Місяць тому

    "Infinitely sided polygon" mfs when i tell them about a oval

  • @user-ns5si6st1z
    @user-ns5si6st1z Місяць тому

    Brooo, you are good

  • @UrbanJackJr
    @UrbanJackJr Місяць тому

    Polygons are discreet circles

  • @billevans7488
    @billevans7488 Місяць тому

    @12 min - LOL! Sorry but 1 divided by infinity is NOT zero. It may be infinitely close (as close as you like) to zero but it never quite gets there. You are perpetuating a fantasy similar to the one about 0.9999 ad infinitum being equal to 1 - which it isn't - they are ALWAYS different no matter what decimal place you wish to examine.
    Things that are always different can never really be the same. But it can be, and is, useful to assume they are the same.
    Limits are a 'convenient' mathematical concept that are useful in understanding. A circle with a 'rational' radius will have an irrational circumference because you multiple by Pi, an irrational number.
    Likewise a circle with a 'rational' circumference will have an irrational radius.
    As far as I know no one has ever proven/shown that a circle with an irrational radius can have a rational circumference. Put another way the result of multiplying two irrational numbers is NEVER, and can not be, rational.
    Yet square roots (e.g. square root of 2) are useful conveniences.
    I think a lot of the confusion arises because even mathematicians forget the difference between the contrived, and logical, world of mathematics and the physical world.
    In the physical world there is no such thing as an 'exact' distance. How big is an atom? an electron, a proton? There is no such thing as a physical ruler that is exactly 12 inches long because physical things don't have exact dimensions.

  • @C0MPLEXITY
    @C0MPLEXITY Місяць тому

    damn

  • @phenixorbitall3917
    @phenixorbitall3917 Місяць тому

    Did he say papa Pythagoras? :D

  • @caiollvllal
    @caiollvllal Місяць тому

    Geometry is beautiful :)

  • @sonicmaths8285
    @sonicmaths8285 Місяць тому

    Tbh this is so cool I gonna come

  • @ruslantrocin108
    @ruslantrocin108 Місяць тому

    nice

  • @pensulpusher2729
    @pensulpusher2729 Місяць тому

    I fail to see the controversy

  • @landsgevaer
    @landsgevaer Місяць тому +1

    Flat-Earthers will like this video that argues that circles are fundamentally straight essentially everywhere.

  • @Viki13
    @Viki13 Місяць тому

    Epic

  • @tubalnavarro8962
    @tubalnavarro8962 Місяць тому

    As a physicist I just believe your mathematical ass if it says a circle is a polygon.

  • @bunnybreaker
    @bunnybreaker Місяць тому

    Disappointed you started with a 4 sided polygon. Everyone knows circles are just try hard triangles.

  • @leewilliam3417
    @leewilliam3417 Місяць тому

    en.wikipedia.org/wiki/Pythagorean_cup