You deserve a lot of appreciation..........very much relevant content, that too in a systematic manner.......easy to organize things in brain ,which help us remember the main concept forever.... thanks a lot sir!!
Hello! Should the address or content of BX be added as offset to find the physical address? According to my lecture slides, it was the address of BX, so I was very confused
Firstly, Physical Address= Segment Address * 10H + Offset/effective address OR Physical Address= Left shifted 4 Times Segment Address + Offset/effective address Secondly, CS, SS, DS, ES are Memory segment registers AX, BX, CX, DX are General purpose registers where AX=AH + AL, BX=BH + BL, CX=... etc SP, BP are Pointer Registers SI, DI are Index Registers SI points to DS DI points to ES and similarly, BX points to DS BP points to SS if BX is given, then the segment would be Data segment (DS) So, Physical Address= DS * 10H + Offset/effective address
@@ashiksaleem360 Hello!! Thank you so much for the very comprehensive summary! I've learned a lot more now compared to a month ago and is able to understand this concept now! But thank you again for your comment, it will be super helpful for revising for my upcoming finals for this subject!! :D
Here , I have given an example where I have considered 20H to be present in the memory location from before. It is just an example, any number can be present in that location. 05H gets translated to 20H in my example.
Man you just nailed it..... explanation level... ♾️♾️♾️♾️♾️
Please upload all the parts ASAP.
You're doing an amazing job .
Shared the playlist with my batch
You deserve a lot of appreciation..........very much relevant content, that too in a systematic manner.......easy to organize things in brain ,which help us remember the main concept forever.... thanks a lot sir!!
Thanks alot sir
No one explained too good like you!
thankyou so much ! XLAT was so confusing but u made it easy !
Glad it helped!
Ur teaching was amazing upload more videos
Khub bhalo.
TQ so much for clear cut explain
Sir why u not uploading continuation of this series
Thank you sir nice explanation, sir can you make a video of the program using XLAT instruction
bravo brother
Thank you so much for ur explanation!!
You are welcome!
sir can we use XCHG instruction for swapping program?
please upload part 2\
Hello! Should the address or content of BX be added as offset to find the physical address?
According to my lecture slides, it was the address of BX, so I was very confused
Firstly,
Physical Address= Segment Address * 10H + Offset/effective address
OR
Physical Address= Left shifted 4 Times Segment Address + Offset/effective address
Secondly,
CS, SS, DS, ES are Memory segment registers
AX, BX, CX, DX are General purpose registers where AX=AH + AL, BX=BH + BL, CX=... etc
SP, BP are Pointer Registers
SI, DI are Index Registers
SI points to DS
DI points to ES
and similarly,
BX points to DS
BP points to SS
if BX is given, then the segment would be Data segment (DS)
So, Physical Address= DS * 10H + Offset/effective address
@@ashiksaleem360 Hello!! Thank you so much for the very comprehensive summary! I've learned a lot more now compared to a month ago and is able to understand this concept now! But thank you again for your comment, it will be super helpful for revising for my upcoming finals for this subject!! :D
Memory lo already 20H enduku vuntundhi⁉️
Here , I have given an example where I have considered 20H to be present in the memory location from before. It is just an example, any number can be present in that location. 05H gets translated to 20H in my example.