Can you solve this? | iota maths problem | Oxford entrance exam questions

[@phillipmaxwellastrology2978]

Elegant! I wanted to multiply out top and bottom completely with a similar pairing trick to what you used but you showed that that would be cumbersome and unnecessary extra work!

[@MathBeast.channel-l9i]

Thanks for praiseing
And
Sorry for what you have not liked as you feel it extra work.
But fact is that i have to explain the steps well so that everyone watching the video get the steps easily as everyone watching have not same mind level 😊

[@MathBeast.channel-l9i]

Thanks for sharing your precious feedback 😌

[@NewsTopThe]

Good solution 4:39

[@MathBeast.channel-l9i]

Thanks a lot Boss for praiseing and sharing your precious feedback 😌
It means a lot for a content creator

[@popodori]

Answer = 1-i, (1+i)^4 = -4, (1-i)^4 = -4i, (1+i)^2024 / (1-i)^2023 = (-4)^506*(1-i)/(-4i)^506 = (1-i)

[@에스피-z2g]

P=given formula
P=[(1+i)/(1-i)]^2024(1-i)
(1+i)/(1-i)=i
i^2024=1
P=1-i

[@MathBeast.channel-l9i]

Thanks for sharing your approach 😊

[@ghamoz]

Ma perché scrivete sempre i problemi ditti notevoli? Dovrebbero essere contenti sciuti se fai la n test d'entrata e se non li sai è giusto che stai fuori

[@user-홍동백서]

풀이가 틀렸다.
답이 1+¿될려면 분모가 1+¿가 되어야 한다.