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Nice video
@@bhoopathim5566Thanks so much ❤️. God bless you for watching my videos
By simplifying with x you have lost the solution x=0.
@@adamfreundlich5295x ≠ 0. Because we will have division by 0, which is undefined
@ before dividing move x on the other side of the sign equal, you will have x3 -2x=0; x(x2-2)=0:
But, x = 0 is excluded based on the original equation.
@@karentusa9488Yes exactly
0 is not a solution because that would make the denominator of the right hand side of the equation equal to zero, and this is not allowed because division by zero is not allowed.
Nice video
@@bhoopathim5566
Thanks so much ❤️. God bless you for watching my videos
By simplifying with x you have lost the solution x=0.
@@adamfreundlich5295
x ≠ 0. Because we will have division by 0, which is undefined
@ before dividing move x on the other side of the sign equal, you will have x3 -2x=0; x(x2-2)=0:
But, x = 0 is excluded based on the original equation.
@@karentusa9488
Yes exactly
0 is not a solution because that would make the denominator of the right hand side of the equation equal to zero, and this is not allowed because division by zero is not allowed.