Parallel & Counter Flow Heat Exchangers (LMTD): Heat Transfer for Mechanical Engineers

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  • Опубліковано 16 гру 2024

КОМЕНТАРІ • 9

  • @davidholmes2157
    @davidholmes2157 2 роки тому

    thanks a lot, great explanation! Maybe you should consider using a pop filter over your mic. Just trying to help and not trying to be rude.

    • @mikeschertzer941
      @mikeschertzer941  2 роки тому

      Thanks David. These were some of the first videos i made. I agree that the pop filter helps.

  • @mahirkarim9566
    @mahirkarim9566 Рік тому

    When calculating the area of the parallel or counter flow heat exchanger, I noticed that the units in the denominator do not align. You left the log-mean temperature in units of Celsius but the overall HT coefficient as W/m^2 K. In this case, wouldn't we have to convert the log-mean temperature to Kelvin in order to get the correct area for the heat exchangers?

  • @sevenmaster7820
    @sevenmaster7820 7 місяців тому +1

    I don't have effective heat transfer co efficient value! And not even hi and ho value

  • @nawafaleid196
    @nawafaleid196 4 роки тому

    Your just awesome, very clear logical explaining.. Can I ask you for a copy of the matrix ?

    • @mikeschertzer941
      @mikeschertzer941  4 роки тому

      Thanks. I'm not sure what the best way to do this would be. It might be easiest for you to take a snip or screen capture of the matrix when it's in the frame (e.g. 2:35)?

  • @truongphamnhat7062
    @truongphamnhat7062 2 роки тому +1

    thank!

  • @OptimEnergy_co
    @OptimEnergy_co 3 роки тому

    awesome thank you