Valence Bond Theory | VBT | Class 12 | Coordination Compounds | ISC / CBSE |
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- Опубліковано 28 вер 2024
- Class 12 | ISC | CBSE | Chemistry | valence bond theory VBT | in just 15 minutes | do any question in just a minute | chapter-Coordination Compounds
In this video you’ll be able to understand the reactions of carbonyl compounds with
Valence bond theory and it’s questions
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That one ramdon youtube teacher who is far better than popular ones🗿❤️
It was the best explanation i found on UA-cam..❤❤
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Naughty horah
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Mera bhi bro
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Now we want more revision as well as more practice of each types of numericals from diff. Chapters
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Pls take more questiona for physical chemistry as well as coordibation compounds
And tricks of any important topic or thing plss
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Hybridization= d²sp³
M.m =o
Octahedral
Diamanteic
Low spin ....
Best teaching style ❤😊
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धन्यवाद mam ji
Ma'am ap Lucknow me kaha rhti h ??
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You got a new Subscriberrrrr (Thanks for help, exam in 4 hours)
Mast explanation
Thank you soo much didi, wish me luck
Answer for the hw question --> hybridisation : d2sp3 , spin : low , magnetic moment : 0 , magnetic behaviour : diamagnetic , geometry : octahedral .
❤
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Mam exam ma sirf octahedral ka puchta ya sab ka
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1st I thought koi 12th pass out 19 20 sal ki bacchi Kya padhaygi.... Umm still confused for the age but literally sb smjh me aa gaya
d2sp3
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samajh nhi aa raha aapko dekhu ya board ko 🤐😸
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6:12 💀
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[Fe(CN)6]-4
Hybridization = d2sp3
M.M = 0
M.B = Diamagnetic
Spin = Low
Geometry = Octahedral
Hyb. d2sp3
Mm. 0
MB. Dia magnetic
Spin. Low
Geo. Octahedral
Low d😅
Me who is watching this before an hour of exam 🙂🙂
Same!!
us bhai us
How Was Your Exam?? 😂😂
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Rip😂
Played in 2x and revised once again 🙏 🙏 👍
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great lecture, best for revision
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Pathetic comment made by you ,
Hybridization - d2sp3
MM - 0
Mag. Behaviour - diamagnetic
Geometry - octahedral
Ma'am is this correct..?
Also Thank you so much❤❤🤗
Also ma'am 1doubt
Hm log ye maan k chl skte h ki if the ligand Is strong to vo pairing krwayega nd hybridization will b d2sp3 agr paper m show krne k liye na ho...?
hey how do you know what all the strong and weak ligands are
@@Proxz at 2:47 time stamp ma'am told abt strong and weak ligands nd how we can recognise them:)
@@kanak_rai1737 x-6=-4
@@kanak_rai1737 u hv to calculate the oxidation no.
[Fe(CN)6] ^-4
Here we hv to find Fe's oxidn no.
Nd CN is a negative charge ligand
So, the solving eq will b
X+(-1)6 = -4
-4 is the whole oxidn no. Of the complex nd we hv to put it in equals IF IT IS GIVEN...otherwise it's 0
Here the oxidn no. Is +2
Hope ur doubt is cleared now
Correct ✅
+3 hoga naa .mam?? +2 kyu
Low D 💀
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Thank you ma'am you are the best ❤ , revising in the morning at 6 am.
Thank you so much mam . Aaj mera board ka exam h or mujhe abhi tak VBT and CFT smnjh nhi aayi thi lekin aapki video dekhi or dono chiz phli baar m hi smnjh aagyi mam . Thank you ❤
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Teachers to bhut ha mam apka jasa nhi.... Bhut acha explain karta ho app 👍 sabi like karo jisko lecture Acha laga .... Or jiska kal paper ha 📄 👍👍👍
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Hybridization=d2sp3
Geometry=octahedral
Magnetic moment=0
Magnetic Behaviour=Diamagnetic
Spin=low
Miller Steven Lewis Nancy Davis Laura
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