I'm in 8th grade and due to the pandemic, I'm having a hard time understanding the module given to us. This helps me a lot. Thanks! Edit:I just finished taking our test and I got a perfect score!
This is very late but we learn when we want to learn. thats why we search videos like these to understand the lessons we miss (since its hard to listen to teachers at school). Unless the teacher is really bad at teaching then
@@user-vd3pw6yf7b teachers suck i used to go to my algebra 2 teacher for help at lunch twice a week for almost the whole semester and she treated me like i was bothering her on her lunch i still hate her
@@Beansthecat99 you know that not all teachers are like that right? there are plenty of teacher who can actually a really close friend of yours maybe you just haven't found the right teachers
If you are confused as to where the numbers come from, we can simply choose a value for x and solve for the unknown y or vice versa. For Example: 3x + 5y = 10 I can just pick some value for x, let's say 1. Now since x is 1, I can plug a 1 in for x in the equation. 3(1) + 5y = 10 3 + 5y = 10 Now, I have a linear equation in one variable. I can solve for y: 3 + 5y = 10 5y = 7 y = 7/5 This tells us that if x is 1, y is 7/5. You can pick any number you want and plug in for x and solve for the unknown y or vice versa. If you have a question about the video, please leave a time marker with clear instructions as a new comment. We only respond to NEW COMMENTS WITH CLEAR INSTRUCTIONS.
@@kinglight1528 It depends on what you are trying to do? What are the instructions? Are you trying to just give some ordered pairs? If that's the case, you can just pick some values for x and solve for y. One solution, we could pick an x-value of 0 and just plug in. 9(0) - 7y = -7 0 - 7y = -7 y = 1 So if x = 0, then y = 1, so one ordered pair is (0, 1) See how that works, just pick something for x and solve for the unknown y.
@@israelbernardoabaga5644 Alright, that's a different video by the way. You need to work with solving linear systems. Anyway to solve a system by substitution, just solve one of the equations for one of the variables. So let's solve the first equation x + y = 10 for y: y = -x + 10 Now plug in for y in the second equation. This works because y is equal to or the same as the expression (-x + 10) 5x + 4(-x + 10) = 4 5x - 4x + 40 = 4 x + 40 = 4 x = -36 Now that we know what x is, we can plug in to either equation and find y. -36 + y = 10 y = 46 So we find that x = -36, and y = 46 or (-36,46) as an ordered pair. For elimination, you will add the two left sides together and set this equal to the sum of the right sides. Notice how your y variable will be eliminated since they are opposites (3y, -3y): 2x + 3y + 5x - 3y = 23 + 5 7x = 28 x = 4 Plug back in to find y 2(4) + 3y = 23 8 + 3y = 23 3y = 15 y = 5 So x = 4 and y = 5 or (4, 5)
Remember: The left value is the X-value and right value is the Y-value. Since you repeated it so many times, it got stuck in my brain. :D Jokes aside, I understood this very well.
I'm glad to hear that, you will work with ordered pairs and ordered triples moving forward, so it's important to remember. Good luck with your studies :)
Hes still replying after 5 years also i have a good ability of catchting things fast i just lost my intrest from learning on online school and when i try comimg back im struggling in math currently and these really help me and i know linear equations quite well now i just dont trust myself
so, for these types of equations, is this a liniar 2-var, diphantine equation (doing research for A-level maths) I do understand that you can use tables and graphs for this, just wondering if this would be the type "diphantine equation" liniar 2-var falls under (year 12 UK, 11th grade/junior US)
I am in University of 2022, and I graduated highschool in 2014. When I enterened my math this year (I avoided it last year lol) I had no idea what I was doing. My professor would always say "You guys should know this" but, to be FAIR. Not all of us transition from highschool to University right off the bat (like me). So this was very confusing. I've had 5 classes so far and I literally have a test on the 23rd. These hours Ive been in class I've had no idea until I stumbled onto your videos. YOU TEACH ME BETTER THAN MY SCHOOLS DOES!!! I've learned this under 2 hours of work put into than the 5 days of my class. I did my first practice quiz we have and got 3/12. After I studied and learned from you I retook the test and got 10/12 within those 2 hours of work. I just want to say THANK YOU!!! Im not so dumb at math like I thought I was
Sorry if this is a bother or if its just common sense but in the dividing/add/subtract process (starting from here 11:53), how do you if you're going to be adding/subtracting or dividing the number to the digit given in the =?
I typed out an answer for this and you deleted the comment. If you delete this one, you are on your own. Basically, you want to just plug in for x and y in your equation and see if the left and the right sides are equal. an ordered pair is (x, y), so the first value is x and the second is y: (-1, -3) Plug in a (-1) for x and a (-3) for y and check to see if the two sides are equal. -y = 4x + 7 -(-3) = 4(-1) + 7 3 = -4 + 7 3 = 3 true, so (-1, -3) is a solution. Now try the other two on your own. Plug in for x and y and see if the left and right sides are equal.
With a linear equation in two variables there is an infinite number of solutions. You have two variables. One thing you can do is choose a number for x and solve for y. This number you choose can be any number. Let's just pick 3 for x. x = 3, y = ? So plug in a 3 for x: 2(3) + 3y = -24 6 + 3y = -24 3y = -30 y = -10 So one solution is (3, -10) but there are an infinite number. Let's suppose we choose 0 for x. x = 0, y = ? 2(0) + 3y = -24 3y = -24 y = -8 So another solution is (0, -8). Your assignment should give you some instructions on what you need to do. Usually they will give you an ordered pair and ask if it's a solution or ask for you to make a few on your own. Let me know if you have another question :)
@@samanthawoodchuck9142 When you pick something for x, you plug it in. This gives you a linear equation in one variable. So you would solve it using the normal steps. 2x + 3y = -24 Let's pick x = 8 Plug in an 8 for x. 2(8) + 3y = -24 16 + 3y = -24 So now you have an equation with one variable, just y. So solve for y, get this on its own on the left hand side. 16 + 3y = -24 Let's subtract 16 away from each side: 16 - 16 + 3y = -24 - 16 3y = -40 Let's divide both sides by 3 to isolate y: 3y/3 = -40/3 y = -40/3 So if x is 8, y = -40/3 (8, -40/3) So again, just pick something for x and plug it in. This gives you a linear equation in one variable. Just solve for that variable. If you are still confused drop your homework problem here with the instructions and I'll show you how to solve it.
I'm just gonna say this but THANK YOU FOR DOING THIS I WAS SO CONFUSED AT FIRST BUT NOW WOW I CANT SAY THANK YOU ENOUGH TYTYTYTY FOR THIS I UNDERSTAND IT NA
With a linear equation in two variables you can simply pick a value for x and solve for y. This can be any value that you want. Let's just suppose we pick 5 for our x-value and this is random. Plug in a 5 for x and solve for the corresponding y: 4(5) + 2y = 12 20 + 2y = 12 2y = 12 - 20 2y = -8 y = -4 So another ordered pair is (5, -4). In other words, you can make as many ordered pair solutions as you want by picking something for x and solving for y or picking something for y and solving for x.
Hi, in the video I said you can pick anything you want for one variable and solve for the other. In other words, there are an infinite number of solutions for a linear equation in two variables. So if you choose a number, any number you want for x, then you can plug in that number and solve for y. Let's say we had: x + y = 4 Just pick some number for x, any number. Let's suppose we just choose 3: x = 3, so what does y equal? Plug in a 3 for x: 3 + y = 4 Solve for y: y = 4 - 3 y = 1 So (3, 1) is an ordered pair that satisfies this equation, but I could choose something else, anything else and do the same thing. Let's say I let x = 15. 15 + y = 4 y = -11 So (15, -11) is another ordered pair that satisfies this equation. You can continue in this fashion for as long as you like. Just pick something for x and plug it in and then solve for the unknown y.
When you are working with this topic, you are generally doing a plug and chug. So you pick a value for x and solve for the unknown y or you pick a value for y and solve for the unknown x. The value you pick can be whatever. Once you have your solution you can plug back in and see if it is a true statement. 2x + 3y = 6 I pick x = 1, so this gives me: 2(1) + 3y = 6 2 + 3y = 6 3y = 4 y = 4/3 So now I have one ordered pair, x = 1 and y = 4/3 (1, 4/3) If you want to check just plug back in and see if you get a true statement, meaning the left and the right sides will be equal. 2(1) + 3 * 4/3 = 6 2 + 4 = 6 6 = 6 true
I love Math and i can easily understand every lesson but NOW QUARANTINE AND NOW MY BRAIN STOP WORKING AND I NOW I CANT UNDERSTAND MY LESSONS BY MY SELF BECAUSE OF MODULES AND HOWW CAN I BRING BACK MY BRAIN :(
Are those individual problems? If they are just isolate the variable. This means you want to undo the operation. 2x = 5 Solve for x? Divide both sides by 2 (undo the multiplication by 2): x = 5/2 3y = 4 Solve for y? Divide both sides by 3 (undo the multiplication by 3): y = 4/3 4y = 5 Solve for y? Divide both sides by 4 (undo the multiplication by 4): y = 5/4 y = 6 is already solved for y.
I just replied to a different comment that said the same thing. You want linear inequalities. I have a video on that for graphing: ua-cam.com/video/lZZuKH0sU10/v-deo.html Let me know if you have questions. 😎
It depends on what you are trying to do. There should be some instructions, such as make a table of ordered pairs, or graph the equation. If you want to make a table of ordered pairs, just pick values for x and solve for y or vice versa.
Are you talking about 4x + 2y = 12, with (3,0) as the ordered pair? You plug in a 3 for x and a 0 for y as given by the ordered pair: 4(3) + 2(0) = 12 12 + 0 = 12 12 = 12 If you were talking about something else please give us a time marker and we'll be happy to explain. :)
Thank you so much it is easy when you teach i cannot understand when my teacher is teaching me i almost cried when i cannot understand this but when i watch this video i found out that this lesson is very easy thank you so much sir❤️❤️❤️
For this type of equation, you can pick any value you want for y and solve for x or pick any number you want and solve for y. For example. 3x - 5y = 10 Pick anything you want for x, I'm going to pick 1, but you can pick whatever: 3(1) - 5y = 10 After I plug in a 1 for x I can solve for y: 3 - 5y = 10 -5y = 10 - 3 -5y = 7 y = -7/5 So one ordered pair is (1, -7/5) Again you can choose whatever you want for x and solve for y or choose whatever you want for y and solve for x.
Thank you so much. This year for school I have 2 hour and 15 minute classes. I have a very short attention span so I don’t learn anything from math. These types of vids really help me. Thanks!
I have a short attention span also, especially if I'm bored. The best way to learn math is to practice so that you are actively doing stuff. It helps with spacing out. Good luck with the school year! :)
i understood almost everything, but i still can’t understand which numbers you have to choose for x or y in order to get a whole number, and not decimal. could somebody explain that, please?
Let's take one example. 2x + 3y = -24 If we are choosing x-values, then we know that we end up with: 3y = -24 - 2(x) If we want to only have integers, then what we choose for x, needs to result in a right-hand side that is divisible by 3.
11:33 why would it not be +3 times -5? because on the previous example, you didnt do -3 times +7. edit - oh, is it because you cant do a negative minus a negative? so you turn that only that one sign into a plus?
This can be done multiple ways, the easiest way is to bring the sign along for the ride. Method 1) -7(2) - 3(-5) = -7(2) + (-3)(-5) = -14 + 15 = 1 Another way would be to subtract away a negative, which changes into adding a positive. Method 2) -7(2) - 3(-5) = -14 - (-15) = -14 + 15 = 1
What's the time marker you are looking at? Are you trying to show multiplication or addition? I'm not sure what you are looking at. If you give us a time marker we are happy to explain anything you are confused about.
@@jetmirahajdari4686 If you have different signs, the the sign will be determined by the number with the larger absolute value. 6 + (-3) = 3 since positive 6 is larger in terms of absolute value. -6 + 3 = -3 since negative 6 is larger in terms of absolute value.
An equation with two variables has two unknowns. Normally this is given as x and y, but could be something else. For example: 3x + 2y = 5, here x and y are the two variables An equation with one variable has only one unknown. Normally this is given as x, but could be something else. For example: 2x + 7 = 19 Hope this helps, let me know if you have another question 😎
This 20 minute video teaches you more than school does in a entire quarter AND it is easier to understand
I'm glad the video was helpful! :)
i agree lol
I agree XD
Kinda agree
🙏🙏
I like the way you teach and explain. You've got yourself a new subscriber! :)
Perfect, glad it was helpful!
This legend is still replying to comments after 4 years
Yes I am :)
Nice
@@professionalprocrastinator4397 Thanks for noticing :)
6 years now
7 years
I'm in 8th grade and due to the pandemic, I'm having a hard time understanding the module given to us. This helps me a lot. Thanks!
Edit:I just finished taking our test and I got a perfect score!
You are very welcome! :)
@Bethany Joy Cool, good luck with class :)
@@professionalprocrastinator4397 It will get better, just keep working!
congrats on your test
What you guys are grade 8 to me too
When UA-cam videos help u more then 10 years of school..... thx for the vid it rlly helped me get that 💯
This is very late but we learn when we want to learn. thats why we search videos like these to understand the lessons we miss (since its hard to listen to teachers at school). Unless the teacher is really bad at teaching then
@@user-vd3pw6yf7b teachers suck i used to go to my algebra 2 teacher for help at lunch twice a week for almost the whole semester and she treated me like i was bothering her on her lunch i still hate her
@@Beansthecat99 you know that not all teachers are like that right? there are plenty of teacher who can actually a really close friend of yours maybe you just haven't found the right teachers
I'm so glad that it was helpful! :)
I am in 8th class and I want to know how to solve these for future excellence
Alright, good luck with high school.
Insane that 6 mins in, and I already understand more than in my 2 hour long lessons in my college class I had earlier this month.
Awesome, let me know if you have questions about the topic.
If you are confused as to where the numbers come from, we can simply choose a value for x and solve for the unknown y or vice versa.
For Example:
3x + 5y = 10
I can just pick some value for x, let's say 1. Now since x is 1, I can plug a 1 in for x in the equation.
3(1) + 5y = 10
3 + 5y = 10
Now, I have a linear equation in one variable. I can solve for y:
3 + 5y = 10
5y = 7
y = 7/5
This tells us that if x is 1, y is 7/5. You can pick any number you want and plug in for x and solve for the unknown y or vice versa.
If you have a question about the video, please leave a time marker with clear instructions as a new comment. We only respond to NEW COMMENTS WITH CLEAR INSTRUCTIONS.
How to solve 9x - 7y= -7?
I can't quite understand :(
1. Substitution
x+y =10
5x + 4y = 4
2.Elimination
2x + 3y = 23 (1)
5x - 3y = 5 (2)
Thank you sir for helping me
@@kinglight1528 It depends on what you are trying to do? What are the instructions? Are you trying to just give some ordered pairs? If that's the case, you can just pick some values for x and solve for y.
One solution, we could pick an x-value of 0 and just plug in.
9(0) - 7y = -7
0 - 7y = -7
y = 1
So if x = 0, then y = 1, so one ordered pair is (0, 1)
See how that works, just pick something for x and solve for the unknown y.
@@israelbernardoabaga5644 Alright, that's a different video by the way. You need to work with solving linear systems. Anyway to solve a system by substitution, just solve one of the equations for one of the variables. So let's solve the first equation x + y = 10 for y:
y = -x + 10
Now plug in for y in the second equation. This works because y is equal to or the same as the expression (-x + 10)
5x + 4(-x + 10) = 4
5x - 4x + 40 = 4
x + 40 = 4
x = -36
Now that we know what x is, we can plug in to either equation and find y.
-36 + y = 10
y = 46
So we find that x = -36, and y = 46 or (-36,46) as an ordered pair.
For elimination, you will add the two left sides together and set this equal to the sum of the right sides. Notice how your y variable will be eliminated since they are opposites (3y, -3y):
2x + 3y + 5x - 3y = 23 + 5
7x = 28
x = 4
Plug back in to find y
2(4) + 3y = 23
8 + 3y = 23
3y = 15
y = 5
So x = 4 and y = 5 or (4, 5)
How to solve
x + y=11; (1,2)
I can't quite understand :)
Sooooo if you make a table you can just pick any number for x or y?
Yes, pick any number for x and solve for y or vice versa. There's an infinite number of solutions that can be made for this type of equation.
thank you sir this help me a lot
Most welcome!
You Sir are a blessing.
Thanks for watching!
Remember: The left value is the X-value and right value is the Y-value. Since you repeated it so many times, it got stuck in my brain. :D
Jokes aside, I understood this very well.
I'm glad to hear that, you will work with ordered pairs and ordered triples moving forward, so it's important to remember. Good luck with your studies :)
Why so hard to understand math
It just requires practice like anything else.
How about something like this"" this? Btw i love this channel thanks for your lesson
You want linear inequalities. I have a video on that for graphing:
ua-cam.com/video/lZZuKH0sU10/v-deo.html
Let me know if you have questions. 😎
Hes still replying after 5 years also i have a good ability of catchting things fast i just lost my intrest from learning on online school and when i try comimg back im struggling in math currently and these really help me and i know linear equations quite well now i just dont trust myself
Let us know if you get stuck on a problem :)
so, for these types of equations, is this a liniar 2-var, diphantine equation (doing research for A-level maths) I do understand that you can use tables and graphs for this, just wondering if this would be the type "diphantine equation" liniar 2-var falls under (year 12 UK, 11th grade/junior US)
Glad you liked it :)
I am in University of 2022, and I graduated highschool in 2014. When I enterened my math this year (I avoided it last year lol) I had no idea what I was doing. My professor would always say "You guys should know this" but, to be FAIR. Not all of us transition from highschool to University right off the bat (like me). So this was very confusing. I've had 5 classes so far and I literally have a test on the 23rd. These hours Ive been in class I've had no idea until I stumbled onto your videos. YOU TEACH ME BETTER THAN MY SCHOOLS DOES!!! I've learned this under 2 hours of work put into than the 5 days of my class. I did my first practice quiz we have and got 3/12. After I studied and learned from you I retook the test and got 10/12 within those 2 hours of work. I just want to say THANK YOU!!! Im not so dumb at math like I thought I was
No one is "dumb at math", they just need lots of practice. Good luck with the test and with college.
Sorry if this is a bother or if its just common sense but in the dividing/add/subtract process (starting from here 11:53), how do you if you're going to be adding/subtracting or dividing the number to the digit given in the =?
You plug in for the variable in the equation and then solve for the other unknown.
Thanks a lot , phew now I will have no tension in the future
You are welcome.
Thank you so much for your videos!
Thanks for watching! :)
Thank you for the video❤❤
You are very welcome, good luck with your studies :)
sir pls answer this question Check whether the ordered pairs (-1, -3), (2, 15), and (0, 7) are solutions of the equation: -y = 4x + 7
I typed out an answer for this and you deleted the comment. If you delete this one, you are on your own.
Basically, you want to just plug in for x and y in your equation and see if the left and the right sides are equal.
an ordered pair is (x, y), so the first value is x and the second is y:
(-1, -3)
Plug in a (-1) for x and a (-3) for y and check to see if the two sides are equal.
-y = 4x + 7
-(-3) = 4(-1) + 7
3 = -4 + 7
3 = 3 true, so (-1, -3) is a solution.
Now try the other two on your own. Plug in for x and y and see if the left and right sides are equal.
I dont get the formula what happens if its like 2x+3y=-24 how do we solve that?
With a linear equation in two variables there is an infinite number of solutions. You have two variables. One thing you can do is choose a number for x and solve for y. This number you choose can be any number. Let's just pick 3 for x.
x = 3, y = ?
So plug in a 3 for x:
2(3) + 3y = -24
6 + 3y = -24
3y = -30
y = -10
So one solution is (3, -10) but there are an infinite number. Let's suppose we choose 0 for x.
x = 0, y = ?
2(0) + 3y = -24
3y = -24
y = -8
So another solution is (0, -8).
Your assignment should give you some instructions on what you need to do. Usually they will give you an ordered pair and ask if it's a solution or ask for you to make a few on your own. Let me know if you have another question :)
@@Greenemath afterwards how do we solve for y?
@@samanthawoodchuck9142 When you pick something for x, you plug it in. This gives you a linear equation in one variable. So you would solve it using the normal steps.
2x + 3y = -24
Let's pick x = 8
Plug in an 8 for x.
2(8) + 3y = -24
16 + 3y = -24
So now you have an equation with one variable, just y. So solve for y, get this on its own on the left hand side.
16 + 3y = -24
Let's subtract 16 away from each side:
16 - 16 + 3y = -24 - 16
3y = -40
Let's divide both sides by 3 to isolate y:
3y/3 = -40/3
y = -40/3
So if x is 8, y = -40/3
(8, -40/3)
So again, just pick something for x and plug it in. This gives you a linear equation in one variable. Just solve for that variable.
If you are still confused drop your homework problem here with the instructions and I'll show you how to solve it.
I'm just gonna say this but THANK YOU FOR DOING THIS I WAS SO CONFUSED AT FIRST BUT NOW WOW I CANT SAY THANK YOU ENOUGH TYTYTYTY FOR THIS I UNDERSTAND IT NA
I'm glad to hear that, let us know if you get stuck on a problem! :)
Thanks for this video! I could finally explain this lesson to my sister! 👍
Glad it was helpful!
from all of the videos I've watched, only this video made me realize that linear equations is definitely not hard hahah
It's very easy.
Thank you sir but there's a part that I didn't understand,on 4x + 2y =12 : check:(3,0)
Where did (3,0) came from?
With a linear equation in two variables you can simply pick a value for x and solve for y. This can be any value that you want. Let's just suppose we pick 5 for our x-value and this is random. Plug in a 5 for x and solve for the corresponding y:
4(5) + 2y = 12
20 + 2y = 12
2y = 12 - 20
2y = -8
y = -4
So another ordered pair is (5, -4).
In other words, you can make as many ordered pair solutions as you want by picking something for x and solving for y or picking something for y and solving for x.
Could you make another video about it? I'm poor not smart I'm me dumb and I couldn't pay a teacher to help me in math. Please help.sir.
Another video about what part specifically? If you type your question in the comments, I'll try to explain step by step.
Sir how do we get (3,0) as x and y value? I mean where does these two numbers come from?
Hi, in the video I said you can pick anything you want for one variable and solve for the other. In other words, there are an infinite number of solutions for a linear equation in two variables. So if you choose a number, any number you want for x, then you can plug in that number and solve for y.
Let's say we had:
x + y = 4
Just pick some number for x, any number. Let's suppose we just choose 3:
x = 3, so what does y equal?
Plug in a 3 for x:
3 + y = 4
Solve for y:
y = 4 - 3
y = 1
So (3, 1) is an ordered pair that satisfies this equation, but I could choose something else, anything else and do the same thing.
Let's say I let x = 15.
15 + y = 4
y = -11
So (15, -11) is another ordered pair that satisfies this equation. You can continue in this fashion for as long as you like. Just pick something for x and plug it in and then solve for the unknown y.
@@Greenemath Thank you so much sir. Now I totally get it.😍
I'm glad to hear that! 😁
Tnx tomorrow is my exam without this video i cannot pass
Perfect, glad it was helpful! :)
Thank You Sir.
You are very welcome! :)
That's pretty fking easy, good tutorial.
Awesome, glad you liked the video, good luck with your studies :)
wtf dude first you divided the numbers then minus and then add wheres the explanation??
What's the time marker of where you are confused? I'll walk you through what is going on step by step.
how can we get the check trial and error sir???? ty
When you are working with this topic, you are generally doing a plug and chug. So you pick a value for x and solve for the unknown y or you pick a value for y and solve for the unknown x. The value you pick can be whatever. Once you have your solution you can plug back in and see if it is a true statement.
2x + 3y = 6
I pick x = 1, so this gives me:
2(1) + 3y = 6
2 + 3y = 6
3y = 4
y = 4/3
So now I have one ordered pair, x = 1 and y = 4/3
(1, 4/3)
If you want to check just plug back in and see if you get a true statement, meaning the left and the right sides will be equal.
2(1) + 3 * 4/3 = 6
2 + 4 = 6
6 = 6 true
Thanks this is a great video
You are very welcome. Thanks for watching :)
You Speak English Fluently.
And I understand it Perfectly.
I am considering Subscribing and smashing that like and bell.
Sounds good, but GreeneMath.com is a better resource for all our free math content. Good luck with your studies :)
Thank you
You're welcome
Very helpful more easy to understand than the others🥰
Glad it was helpful!
Thanks sir you made it easier for me, tomorrow's my final exam of maths!
All the best, good luck with your test! :)
Find X And Y For 105x-87y=2988
Do you have a second equation or are you just trying to find an ordered pair solution?
@@Greenemath The Actual Question Was Very Long I just Want To Know How The Answer Was Derived. The Answer Was X=21
I can't give you an answer with part of a question.
Thankyou so much sir!
Most welcome!
THANKYOUUUU🥺🥰 BE SAFEEEE
You are welcome.
dude seriously, your dedication is unparalleled, thank you for making these videos. really calms my math anxiety haha
You are welcome, let me know if you have any questions about the topic. 😎
Thanks for this now i can understand and is able to answer my actitivity
I'm glad to hear that! :)
I love Math and i can easily understand every lesson but NOW QUARANTINE AND NOW MY BRAIN STOP WORKING AND I NOW I CANT UNDERSTAND MY LESSONS BY MY SELF BECAUSE OF MODULES AND HOWW CAN I BRING BACK MY BRAIN :(
For math it's just a lot of practice.
@@Greenemath THANK U SO MUCH AND NOW I BRING BACK MY REAL ME AND IM BEST IN MATH IN OURR CLASS AND THANK FOR YOUR VIDEOS I GOT EASILIER UNDERSTAND
@@thrailersandpreviews3405 I'm glad to hear you are doing well in your class 😎
@@Greenemath YES THANK U FOR YOUR VIDEOS I CAN EASILY UBDERSTAND OUR LESSON BY MY SELF
Finally, thanks for the clear explanation I understand how to do it now. Thanks a lot
I'm glad to hear that, let us know if you run into any tough problems and need help! :)
what if there are no coordinates given?
You can generate them. Choose a value for x and solve for the unknown y. If you drop your example here, I can show you.
@@Greenemath Thank you soo much!!!
I passed it just in time
@@SnowBoy1008 I'm so glad to hear that, let us know if you have any other questions :)
Oh wow, you really made this easy on my studies!
I'm so glad to hear that! :)
this really helped me out thanks
You are very welcome! :)
UA-cam is better than a classroom
Great, glad to hear that!
How can I solve 2x=5, 3y=4, 4y=5, y=6 ?
Are those individual problems? If they are just isolate the variable. This means you want to undo the operation.
2x = 5
Solve for x? Divide both sides by 2 (undo the multiplication by 2):
x = 5/2
3y = 4
Solve for y? Divide both sides by 3 (undo the multiplication by 3):
y = 4/3
4y = 5
Solve for y? Divide both sides by 4 (undo the multiplication by 4):
y = 5/4
y = 6 is already solved for y.
Thanks for this video it help me so much
I'm glad to hear that, let me know if you have any specific questions or get stuck on a problem 😎.
Wow, I'm really looking for this vid just what I looking for Thanks alot!
Glad I could help!
This is a big help for us students to learn. Thanks!
You are very welcome! :)
You explain so good more good than my teacher
Awesome! I'm glad you are learning! :)
What if is there symbol like this ""???? Btw im new subscriber
I just replied to a different comment that said the same thing.
You want linear inequalities. I have a video on that for graphing:
ua-cam.com/video/lZZuKH0sU10/v-deo.html
Let me know if you have questions. 😎
Thanks
@@ryzalineabanag4560 You are welcome, let me know if you have any questions 😎
Thank you so much brother
You are very welcome! :)
That’s it ..?. ..I tried the whole night trying to figure it out myself, I feel really stupid
You should never feel stupid, math is hard for everyone.
@@Greenemath thanks a lot after watching your video this was too easy
Happy teachers day
@@jayaaditya5143 Thanks, I am a programmer, but I appreciate it anyway!
i want to drop out bec of math but thank you for making this :]
You are welcome. If you want to get better at math, just keep practicing. It's really the only way to get better :)
I like the way you teach. I can really understand very well :)
Awesome, thank you!
This was so great to explain. I understand now
I'm glad to hear that, let me know if you have any questions about the topic.
Awesome video, as all of your videos, I've watched your videos since 2012.
I'm glad to hear that, thanks for watching :)
But then what uf they never give me a number for the variable? Like no check, no table. Then what?
It depends on what you are trying to do. There should be some instructions, such as make a table of ordered pairs, or graph the equation. If you want to make a table of ordered pairs, just pick values for x and solve for y or vice versa.
Thank you i appreciate sir
Most welcome
how did you get 12 in 4 plus 2 pls help
Are you talking about 4x + 2y = 12, with (3,0) as the ordered pair?
You plug in a 3 for x and a 0 for y as given by the ordered pair:
4(3) + 2(0) = 12
12 + 0 = 12
12 = 12
If you were talking about something else please give us a time marker and we'll be happy to explain. :)
Thank you so much it is easy when you teach i cannot understand when my teacher is teaching me i almost cried when i cannot understand this but when i watch this video i found out that this lesson is very easy thank you so much sir❤️❤️❤️
You are welcome! Glad the video was helpful! :)
How did you get the valie of Y?
For this type of equation, you can pick any value you want for y and solve for x or pick any number you want and solve for y.
For example.
3x - 5y = 10
Pick anything you want for x, I'm going to pick 1, but you can pick whatever:
3(1) - 5y = 10
After I plug in a 1 for x I can solve for y:
3 - 5y = 10
-5y = 10 - 3
-5y = 7
y = -7/5
So one ordered pair is (1, -7/5)
Again you can choose whatever you want for x and solve for y or choose whatever you want for y and solve for x.
Thank you so much. This year for school I have 2 hour and 15 minute classes. I have a very short attention span so I don’t learn anything from math. These types of vids really help me. Thanks!
I have a short attention span also, especially if I'm bored. The best way to learn math is to practice so that you are actively doing stuff. It helps with spacing out. Good luck with the school year! :)
This help me a lot thank you
Glad it helped! Good luck with your studies 😎
Thank u so much for the tutorial 😊
You are very welcome! :)
i understood almost everything, but i still can’t understand which numbers you have to choose for x or y in order to get a whole number, and not decimal. could somebody explain that, please?
Let's take one example.
2x + 3y = -24
If we are choosing x-values, then we know that we end up with:
3y = -24 - 2(x)
If we want to only have integers, then what we choose for x, needs to result in a right-hand side that is divisible by 3.
It helps a lot 😊
I'm glad to hear that! :)
grrr im just on 7th grade and it's so confusing to understand since we have this pandemic. thank you so much sir, keep safe!
I'm glad you are learning, good luck with your studies :)
daming filipino d2 omg hahaha
@@maeve9615 Thanks for the comment, hope you are doing well :)
Thank you!
You're welcome!
THANK YOU VERY MUCHHHHH
You are very welcome! 😎
I have test in. Hour
I hope you passed! :)
THANK YOU SO MUCHH THIS REALLY HELPS ME
You are welcome and I'm really glad it's helpful! :)
Thank you now I got it
I'm really glad to hear that! :)
we will have our exams tomorrow and this helped alot.Tysm :D
You are very welcome! :)
Thankyou
You are welcome.
Clear pronseation
Thanks for watching and commenting!
Thank you sir😊
Most welcome! :)
Thank you so much I understood this better because our professor teaches too fast so thank you so much I understand it better.
You're very welcome!
11:33 why would it not be +3 times -5? because on the previous example, you didnt do -3 times +7.
edit - oh, is it because you cant do a negative minus a negative? so you turn that only that one sign into a plus?
This can be done multiple ways, the easiest way is to bring the sign along for the ride.
Method 1)
-7(2) - 3(-5) = -7(2) + (-3)(-5) = -14 + 15 = 1
Another way would be to subtract away a negative, which changes into adding a positive.
Method 2)
-7(2) - 3(-5) = -14 - (-15) = -14 + 15 = 1
Thank you so much
You're most welcome
THANK YOU SIR BE MY MATH TEACHER PLZ
You are very welcome, all of our courses are free at GreeneMath.com if you want to do a deep study :)
I thought the + + - = -
What's the time marker you are looking at? Are you trying to show multiplication or addition? I'm not sure what you are looking at. If you give us a time marker we are happy to explain anything you are confused about.
If you add minus to plus its minus, i guess
(-)+(-)=+
(+)+(-)=-
(-)+(+)=-
(+)+(+)=+
@@jetmirahajdari4686 If you have different signs, the the sign will be determined by the number with the larger absolute value.
6 + (-3) = 3 since positive 6 is larger in terms of absolute value.
-6 + 3 = -3 since negative 6 is larger in terms of absolute value.
Thank you sir
All the best
You're a great teacher
@@gmn_kyl11 Thank you for your kind words :)
Thank you very much💜
You are very welcome! 😎
Thanks sir
You are very welcome! :)
your teachings is pog
Play of the Game from twitch? I had to look it up. Thanks for the nice comment :)
@@Greenemath eyy, no prob, it helped me alot
Thanks
You are welcome, good luck with your studies :)
can u gib me cheeseburbur? me hanguery
I am also hungry 🍔
Hiii
Hello!
Thank you so much I really understand it.It's ec to understand
Glad it helped!
what is two Variable and one variable
An equation with two variables has two unknowns. Normally this is given as x and y, but could be something else. For example:
3x + 2y = 5, here x and y are the two variables
An equation with one variable has only one unknown. Normally this is given as x, but could be something else. For example:
2x + 7 = 19
Hope this helps, let me know if you have another question 😎
Thank you so much this helped a lot 😁
@@ynn9173 You are welcome, let me know if you have any other questions 😎
ok
OMGGG THANK YOUUU I FINALLY GOT ITT!! Thank you so so much
Glad it was helpful! :)
dude my teacher told us to watch this instead of teaching us this smh
Thanks for watching :)
Very clear teaching, Thank you for helping me review for our exams
Awesome, thanks for watching :)
One equation with x and y has always infinite solutions.
Yes, that was covered in the video.