I love your videos so much That I forget to comment... But You are Giving Quality Education.. Your Videos are very very Helpful.. No words to thank You..
Sir you have explained the concepts in previous videos so well that I could solve these without any clues ..this chapter was honestly so confusing for me but thanks to you that i can do the numericals so easily !! I love the way you explain everything with analogies❤
Sir i have a doubt in the 2nd question, why we can't use the above 2 formula for calculating power. Please sir clear it i have doubt that when we have to use these formula
In question 1 ... Like in general if 10V = 50W then 5 V will be it's half right it should be 25W no sir... Sir plz help.. I am confused.. Even when did first time i got 25 .... First I divided 50/10 to calculate 1V value then I got answer 5 then I multiplied it to 5V to get power of 5V ... Then I got 25 ... Sir plzzzzz help😭😭😭
Sir , in question 1 ; We can calculate current and use the direct formula P = VI But , when we calculate current I , Then , I = 50/10 = 5ohms Now , V = 5 and I = 5 , So , P = VI = 5×5 = 25 Please help me in this
Look u have taken P= VI And then I = P/V = 50/10 = 5 So in these cases when potential difference is 10 V then current is 5 ampere .. but in 2nd case how can u say that 5 ampere of current will pass through the bulb bcoz potential diff. = 5 V.. That's why we need to measure resistance because it will remain same in both cases..🙂
Because current won't be produced from the bulb resistance it will produce from your battery which is 5 voltage. so in the pathway of your electricity you have to know how much resistance electricity will face that's why we should know resistance first in this case. But when our bulb is been connected with the main line, we first calculate current flow (I) because we have abundant voltage. In this case your voltage source has limitation.
Btw, after knowing resistance, you can calculate how much current will flow, and then you simply put the calculation in P=VI formula. The answer and method will be same
I love your videos so much That I forget to comment... But You are Giving Quality Education.. Your Videos are very very Helpful.. No words to thank You..
Sir as u have told power dissipated is heat producing by object then why u re calculating power of bulb in both questions
Isn't it confusing 🤔
Killer concept👍👍
Ur voice👍
Sir you have explained the concepts in previous videos so well that I could solve these without any clues ..this chapter was honestly so confusing for me but thanks to you that i can do the numericals so easily !! I love the way you explain everything with analogies❤
Ram Sir please please include an example of bulbs connected in parallel that would be very helpful
LOVE YOU SIR..........
Sir ji you are good
ap na 5v battery wala resister ma current find keyu nahi kia?
please answer
Sir u are great
sir such me maja aa gaya
Great sir 😊
Amazing, tysm
Sir i have a doubt in the 2nd question, why we can't use the above 2 formula for calculating power. Please sir clear it i have doubt that when we have to use these formula
thanks
In question 1 ... Like in general if 10V = 50W then 5 V will be it's half right it should be 25W no sir... Sir plz help.. I am confused.. Even when did first time i got 25 .... First I divided 50/10 to calculate 1V value then I got answer 5 then I multiplied it to 5V to get power of 5V ... Then I got 25 ... Sir plzzzzz help😭😭😭
Dude u should not use unitary method
Thank you very much... For this.. I now understood how to solve that kind of problems..
At 8 : 59 , see...why same current
Current will be same bcoz they are in series
Sir , in question 1 ;
We can calculate current and use the direct formula P = VI
But , when we calculate current I ,
Then , I = 50/10 = 5ohms
Now , V = 5 and I = 5 ,
So , P = VI = 5×5 = 25
Please help me in this
Always find the resistance bcoz current may or may not be same
I also had the same question🙋
Look u have taken P= VI
And then I = P/V = 50/10 = 5
So in these cases when potential difference is 10 V then current is 5 ampere .. but in 2nd case how can u say that 5 ampere of current will pass through the bulb bcoz potential diff. = 5 V..
That's why we need to measure resistance because it will remain same in both cases..🙂
@@ranjitkumardas5263 tq for this explenation it helped a lot..... 😊😊😊😊thank you again
@@ranjitkumardas5263 again a question.. Current will not be same in both cases??
Sir AAP ekdm mast pdhate ho
Continue ram sir
But voltage of each bulb was given that is 20V amd 20V so why couldn't we simply use the formula v^2/R?
Because bulbs are in series
Thank you
@ 5:06 Q.2
Plzz tell
Why can't we first find "i" and then apply formula as P=VI..WE are gvn both V and P ..can't we calculate I and then solve it further
Because current won't be produced from the bulb resistance it will produce from your battery which is 5 voltage.
so in the pathway of your electricity you have to know how much resistance electricity will face that's why we should know resistance first in this case.
But when our bulb is been connected with the main line, we first calculate current flow (I) because we have abundant voltage.
In this case your voltage source has limitation.
Btw, after knowing resistance, you can calculate how much current will flow, and then you simply put the calculation in P=VI formula. The answer and method will be same
Second question me buld destroyed ho jayega
1st like
Which app are you using in this video to teach us
2 viewer
1st view
plz tell me
23 volts and 2 amperes find power
46 W