Conjugate Beam Method - Tricky Continuous Beam with Cantilever Solved Example

Difficult problem using the conjugate beam method. Tips and tricks on where to cut the beam and how to find slope and deflection.
Link to the introduction to conjugate beams video: • Conjugate Beam Method ...
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[@AFMathandEngineering]

Let us know if you want to see more structural analysis videos!
Link to an our intro video and another example problem: ua-cam.com/video/QsNvwRQVkBE/v-deo.html

[@sushilbhutada1644]

One location by mistake taken as 3.92 but actually it should be 3.82 and in one location while calculating displacement multiply dimension has taken 3/2 but it should be 2/3.

[@VoyagerLOAF]

yah. i was thinking the same

[@อิสรพงษ์ศรีพุทธา-ว3ธ]

Yes

[@duncangutse4367]

I also realized that

[@gopikaselvi4337]

It's a very good video to understand the conjugate beam method of analysis...
We need a clarification on resolving the 3span continuous beam with all the ends are simply supported. . Could you suggest us the trick.. !

[@sonshadowshadow5546]

If i maynot be wrong for getting deflection at D. ,you can calculate D(y) reaction at fix end and then taking only right side of internal hinge since moment =0 and calculate moment at fixed end will be easier .

[@markusbryant6789]

Is there a reason why you can’t just split the hinge and find internal shear and moment without finding the reaction at D?

[@alpereneylenceoglu7404]

You are amazing. Thanks, Conjugate beam is easy for me after this video. 👍

[@AFMathandEngineering]

Alperen Eylenceoglu thanks so much! Were glad we could help you out!

[@billmorrison5908]

you are the man! this is a great video. thanks so much

[@apollodamonbuilders]

Your sign convection for the moment was: Anticlockwise as positive, but when solving for moment of the conjugate at D, you took Ay as a negative moment yet it is in the anticlockwise direction. Why?

[@crunchbox7698]

Thanks broo.. Now I fully understand 😉

[@orbital16]

Hi there @10:22 about the term 564/70(2340) = 0.00344 rad.
Dis you get that answer exactly it is? I am using Casio 991Es calculator and Im getting 3.4432x10^-3 which i still need to press the back arrow to get the answer youve got..

[@AFMathandEngineering]

That level of accuracy is really not important, maybe if you had a really strict teacher, especially not in real life structural engineering.

[@Trump_Gaming]

Why didn't you take into account the parabolic loading when doing the reaction at A? You only did the 3 triangles.

[@civilographybsbd1817]

Thanku that was really helpful.

[@vanbeet5105]

I'm a little confused about the sign convention you've used, is anti clockwise supposed to be positive or negative

[@AFMathandEngineering]

van béet thanks for the comment! Can you give us an example of where you're confused specifically so we can help you out? Cheers :D

[@AFMathandEngineering]

Also to further clarify, Almost always the positive sign conventions we use for bending for beams is compression on top, tension on bottom and counterclockwise (+ve) for moments.

[@vanbeet5105]

I'm not from the US, so probably the conventions we use are quite different.
In other videos, i also noticed that in the drawing of the bending moment diagram, when the line or curve occurs below the baseline i. e if the beam sags, the moment is labeled as negative. At our university, we are taught that a sagging beam has positive moment, which is also clockwise

[@AFMathandEngineering]

I see. Everywhere has different convention. Usually in practice I'll draw the bending moment on the tension side of the beam, however in most textbooks it's on the opposite side for positive moment. I'm from canada btw :) thanks for sharing the different convention that you use at your school! What year are you currently in? Cheers!

[@vanbeet5105]

I'm in second year, doing civil engineering
Anyway, thanks for the great content, your videos have been very useful

[@gabrielefolino4005]

isn't it 3.92 x (2/3) not (3/2) when finding moment @ C?

[@briankoima9032]

youre right

[@itsme-tg4dr]

how you get the 3.92?

[@Ahmedsalah-mq9ef]

Not 3.92 it is 3.82

[@gigipensiri979]

Thank you, I appreciate it

[@zjyub]

(2417060 Nm^3)/((706N/m^2)(0.00234m^4) does not equal 14mm?? Did you mean 706GPa?

[@harshitsingh6954]

what if we have to find deflection at b point

[@kennethdevera2561]

when you solved for the new reaction at A, why did you only consider moment at left of "C" and didn't include the parabolic side?

[@AFMathandEngineering]

Because of the hinge at c, we can separate the beam into two parts, AC and CD and solve them independently.

[@haeseoya3123]

@@AFMathandEngineering But why did you calculate all when you solved slope D and deflection D?

[@AFMathandEngineering]

Because we need the reaction at the hinge.

[@badabc6969]

Please make more

[@Corvanor]

Question says deflection and slope at B but you solved for D?

[@AFMathandEngineering]

Yea, question at the start should read slope and deflection at D. Thanks

[@kkkkkkk-dl3qd]

B or D? Im confused

[@SURYA4407]

How to solve a fixed beam by conjugate beam method

[@vhk26]

Great!

[@AFMathandEngineering]

+Vrutant Kanakia thanks!