BORDERED HESSIAN METHOD For Constrained Optimisation Numerical.

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[@rahulsinha3538]

Sir, The value of x here will be 40/3.
Thanks for solving the problem. It was really helpful

[@ECONMATHS]

I didn't notice . Is it so?

[@rahulsinha3538]

@@ECONMATHS yes sir.

[@breadzeppelin2705]

Thanks for the video sir.
In the matrix for x, i.e., where you substitute the x column with the constants, you'll get -2(0-320) not -2(0-360)

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My bad . Thanks

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[@baranaydn2876]

eyvallah

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Eyvallah kardesh

[@judahsibalwa2927]

Isn't -80×-4=320

[@hansaljames4489]

i assume its 90 in the objective function

[@basekuteeue3304]

How is 80 x -4 = 360

[@j-man7994]

Currently asking myself the same question? Perhaps he made a mistake!

[@almontheralmonther9712]

the final result is 48 which is bigger than zero. Shouldn't be minimum? Also, in the hessian matrix, you dropped the negative sign of numbers?

[@ECONMATHS]

Utility will be maximum ie (negative definite) if
|H2| > 0
And minimum (positive definite) if
|H2|

[@mulemwakusemwa6903]

shoudnt that be -80?

[@ECONMATHS]

Yes it is

[@mahmutbahcevan]

adamm

[@destabirhanu9282]

A