I'm struggling to solve this problem using two supernodes (v1-v2 and v2-v3), but it looks like you made a smart choice by considering v1-v3 as one supernode. It makes more sense now. Thank you for sharing this solution.
How did you take current (v1-v3)/6 twice and in opposite direction and cancelled them? Shouldn't we take just one polarity of a single flow of current? Please explain its very confusing
@@ElectricalBoost i know kcl. in KCL, we assume plus for entering and minus for leaving or vice versa. can you please explain that you assumed all plus.but we did not know current direction. how is that actually working. Sorry for my ignorance.
In case of nodal analysis, when we write node equations we consider that node potential is higher than other so that current flows higher to lower ,so I take like wise currents direction leaves from the node.
You welcome For finding 3 variable you can use Cramer's rule Please visit this link below courses.lumenlearning.com/ivytech-collegealgebra/chapter/using-cramers-rule-to-solve-a-system-of-three-equations-in-three-variables/
when a voltage source present in between two node . we didn't know what amount of current flowing to this so apply suppernode analysis . for details about supernode watch this video ua-cam.com/video/WGSwp3JtXcI/v-deo.html
Again he is correct because Input Current = Output current. V3-V1/6 = -(V1-V3)/6. So, V1-V3/6 - (V1-V3)/6 = 0. It's your lack of knowledge and manners that need to be fixed.
Here we are deal with supernode so that we applly KVL in between node-1 and node-2 because super node exist their You can also solve this problem by applying KVL in 3 loop
I'm struggling to solve this problem using two supernodes (v1-v2 and v2-v3), but it looks like you made a smart choice by considering v1-v3 as one supernode. It makes more sense now. Thank you for sharing this solution.
Are you get answer by two supernodes ? then please post solution here
Much appreciated Sir😊
Easy 😊(one minute)
Your v1 v2 v3 values are wrong, this question is from Alexander Matthew's book, correct values are v1=7.608
V2=-17.39
V3=1.63
He has a 10V betwn v1 and v2 dumbass
Why we r solving it as a single node? Cant we solve it as supernode 1 & supernode 2??
Yes you can
But when consider single supernode it more easy than two supernode
How did you take current (v1-v3)/6 twice and in opposite direction and cancelled them? Shouldn't we take just one polarity of a single flow of current? Please explain its very confusing
the first one was from doing voltage analysis from V1 node. the second was voltage analysis at V3 node.
can you elaborate how you execute the kcl?you showed all the current are leaving the node?
Just take assumption because you didn't know which direction current will flow , after calculating we find actual direction of current flow.
Please watch this for better understand
ua-cam.com/video/KSKGxoWMtL8/v-deo.html
@@ElectricalBoost i know kcl. in KCL, we assume plus for entering and minus for leaving or vice versa. can you please explain that you assumed all plus.but we did not know current direction. how is that actually working. Sorry for my ignorance.
In case of nodal analysis, when we write node equations we consider that node potential is higher than other so that current flows higher to lower ,so I take like wise currents direction leaves from the node.
@@ElectricalBoost thanks brother for the reply.it helps much.
Keep it up , supernode problems are tough
how did you solve the equations using calculator?
in scientific calculator their is option to solve equations.
you can also use matrix to solve the equations
@@ElectricalBoost my calculatior doesent have the matrix function i think
it is a mathematical formula which is belong to Matrix subject.
see this link
you may understand how to solve three equations
www.chilimath.com/lessons/advanced-algebra/cramers-rule-with-three-variables/
@@ElectricalBoost ok thanks
This 3 equation can be solved by cramer rule or not.
yes
Thanks 🙏 for concept😍
thank you keep watching
Bhai tera explaination iss example mai samaj nhi aa rha h
THANK YOU SO MUCH...........
You're welcome!
Its better to show how you computed the Vi,Vii, and Viii. , Can you shpw me how to solved it? , But anyway thankyou ! Godbless.
You welcome
For finding 3 variable you can use Cramer's rule
Please visit this link below
courses.lumenlearning.com/ivytech-collegealgebra/chapter/using-cramers-rule-to-solve-a-system-of-three-equations-in-three-variables/
You made voltage equal to current at v3-v2=5i i think it's a mistake
Sir a "super node is be considered as voltage source and element parallel to it" by why we are not considering that ll element
when a voltage source present in between two node . we didn't know what amount of current flowing to this so apply suppernode analysis .
for details about supernode watch this video
ua-cam.com/video/WGSwp3JtXcI/v-deo.html
How to solve without calculator .
Thanks!!
Welcome!
You make a mistake bro. You cannot cancel out v1-v3/6 & v3-v1/6 because they are unlike signs.
Again he is correct because Input Current = Output current. V3-V1/6 = -(V1-V3)/6. So, V1-V3/6 - (V1-V3)/6 = 0. It's your lack of knowledge and manners that need to be fixed.
Why don't we apply KVL to the upper loop?
Here we are deal with supernode so that we applly KVL in between node-1 and node-2 because super node exist their
You can also solve this problem by applying KVL in 3 loop
When it is considered a single node then current won't pass through 6 ohms resistor, don't mention 6 at all as it's the same point.
at 3:30 i was mentioned why 6 ohm is eliminated
i got it, big thanks
Re babu casio kuda chupinchali
And starting ela a eqn vesavo kuda chepaleadhu