Randomized smoothing for certified robustness

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  • Опубліковано 29 бер 2020
  • We give a short proof of the Cohen-Rosenfeld-Kolter theorem on the certified robustness of randomized smoothing.
    Cohen-Rosenfeld-Kolter paper: arxiv.org/abs/1902.02918
    Presented proof can be found in Salman-Yang-Li-Zhang-Zhang-Razenshteyn-Bubeck: arxiv.org/abs/1906.04584
    For more background on adversarial examples see e.g., this video: • Adversarial Examples

КОМЕНТАРІ • 4

  • @CuongTran-jj9bu
    @CuongTran-jj9bu 3 роки тому +1

    very useful :)

  • @sparsam
    @sparsam 2 роки тому

    Just watched the video and it was really interesting!
    Only the definition of \phi^{-1} was somehow inconsistent I think. If we define it to return the value that is smaller than the gaussian with probability p (in most of the video you have defined so I think), then there must be two modifications probably:
    1) if p -> 1 then \phi^{-1}(p) -> -\infinity
    2) at the end of the video \phi^{-1}(\hat{f}_B(x + \delta)) - \phi{-1}(\hat{f}_A(x + \delta)) must be examined

  • @yingruli2250
    @yingruli2250 4 роки тому

    at 10:30, I think this equality in the red box, there is no negative sign inside the expectation, although it will not affect the other derivations.