After watching 10 lectures on PDA the only quote coming to my mind is, "the more you sweat in peace, the less you bleed in war", such a great journey, thank you Sir for all your efforts.
@@AmitKhuranaSir if we make initial state as final to accept null string then still it is NDPDA not DPDA. Both are correct but if we make epsilon move then it will have one less state Thank you very much sir ❤
@@AmitKhuranaSirbut it still not DPDA bcz @1:12:39 there is more than one moves for (q2, a,a) similarly for (q2, b, b) = { (q1 , epsilon ) , ( q2, aa) }
sir, at @1:08:02 agar direct qnot se qf agar transition laga de like: delta(q0,lambda,z0)=(qf,z0) for accepting null string then ye bhi toh valid state diagram ho jaayega nah??
Even I also verified that If we give a direct transition from q0 to qf with delta move (q0, Epsillion,z0) = (qf,z0), then along with null string all other string of L are also accepted perfectly.
After watching 10 lectures on PDA the only quote coming to my mind is, "the more you sweat in peace, the less you bleed in war", such a great journey, thank you Sir for all your efforts.
Sir aapse padne ke bad kahi or se padne ka mann hi nahi karta..kyuki kahi or itna deep or easy way me kisi ne nahi padaya..❤❤
1:08:00 we can give simple one move (q0, epsilon, z0) from q0 to qf to accept null string.
yes we can...
But it will no longer remain DPDA
@@AmitKhuranaSir if we make initial state as final to accept null string then still it is NDPDA not DPDA. Both are correct but if we make epsilon move then it will have one less state
Thank you very much sir ❤
@@AmitKhuranaSirbut it still not DPDA bcz @1:12:39 there is more than one moves for (q2, a,a) similarly for (q2, b, b) = { (q1 , epsilon ) , ( q2, aa) }
great
PDA completed!!!!!!
Sir, Thank you for this amazing 10+ hours journey of PDA...
I think in Q24) we should also make a move for epsilon from q0 to qf as (E,z0/z0).
sir, at @1:08:02 agar direct qnot se qf agar transition laga de like: delta(q0,lambda,z0)=(qf,z0) for accepting null string then ye bhi toh valid state diagram ho jaayega nah??
Even I also verified that If we give a direct transition from q0 to qf with delta move (q0, Epsillion,z0) = (qf,z0), then along with null string all other string of L are also accepted perfectly.
53:45 sir, is there any problem if i connect move (#, z0 / z0) from q0 to q1.
Thank u so much sir
Last Q of palindrom won't work for odd lenght palindromic string
TM problem jroor btana
concepts ab jaake clear hua hai, meine toh pura PDA hi galat padh rakha tha 😂 Thank you sir.
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