2:40 (1) Emf force on moving charges 5:08 (2) magnetic firce on moving charges 14:53 (3) deflection by a sector of mf 17:20 (4) not completing circle 20:30 (5) force between two parallel charges 24:27 (6) magnetic force on a current carrying wire:- 26:19 (7) force between parallel current carrying wire 28:57 (8) magnetic force on a random shaped wire. 31:28 (9) magnetic force on a closed current carrying loop/coil 32:30 (10) magnetic force b/w a parallel wire and strip 37:05 (11) current carrying conductor on a inclined plane 40:31 (12) cases of impulse by magnetic force 45:16 (13) motion of a charge in both ef and mf: --------- (14) torque on a coil in MF:- 56:41 (15) interaction energy of coil in mf and it's equilibrium 1:01:49 (16) magnetic flux through current carrying coil 1:08:17 (17) moving coil galvanometer
1. Electromagnetic force on moving charges 2:40 2. Magnetic force on moving charges 5:12 3. Deflection by sector of MF 15:05 4. Not completing a circle inside a magnetic field 17:12 5. Force between two parallel moving charges 20:18 6. Magnetic force on a current wire 24:26 7. Force between parallel current carrying wire 25:52 [to be noted] 8. magnetic force on a random shaped wire 28:50 9. magnetic force on a closed current carrying loop 10. magnetic force between a parallel wire and strip 11. current carrying inductor on an inclined plane 12. cases of impulse my magnetic force 13. motion of charge in both EF and MF [didn't quite get it] 14. torque on a coil in MF 15. interaction energy of coil in MF and its equilibrium 16. magnetic flux through a current carrying coil 17. moving coil galvanometer 18. relation in magnetic moment and angular momentum of a rotating charge 19. torque on a 3D loop in magnetic field
@@samarthraj2085 bro c square multiplied by mue not multiplied by epsilon not is equals to 1 Its a relation which can be derived by units and dimensions
@@physicsgalaxyworld 24:21 It would balance fe and fm at speed of light but practically it's not possible. Sir please tell the answer in comment section
Sir I can't afford coaching classes but you have given me the feel of coaching classes, keep making such contents sir, I would totally love it. 👏👏👏Padnam Sir.
Respected sir, I would like to point a silly correction in the 10th point viz. Magnetic force between current carrying wire and a strip in the entire derivation along with final expression, the denominator will be 2π instead of 4π
In case of parallel moving charges, the value of magnetic force and value of electric force will be equal if both the particles are projected with the speed = 1/sq root {(permittivity of free space)(permeability of free space)}, i.e., with the speed of light.
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
24:20, No it is not possible until and unless we consider a hypothethical case as Here the velocity between then is equal to The velocity of light which is not Possible for any particle to gain that speed yet
At 23:46 if V=c i.e speed of light the condition said could come true. But their is a twist classical magnetism dosent work when speed is compareble to speed of light so their should be no such velocitt possible i guess . Am i right sir?
At 24:04 the particles must attain the speed of light so as to balance the force of attraction and repulsion by magnetic field and coulombs force respectively. Hence it is not possible for them to balance each other as speed of light can't be attained
Aap hamare liye kitna kuch kar rahe hai thank you very much sir and love you. U r a best physics teacher. Aise hi achhe achhe vdos jee advanced ke liye bhi plz lana
24:20 Sir, the velocity is speed of light. If the velocity is less than the speed of light then Fe will dominate over Fm and as a result it will face repulsion. But in case of two wire carrying current in same direction we have seen that the wire repel each other only by considering magnetic force only. So, does it mean that the velocity of electrons in wire are more than velocity of light.
shyd tumne padha hoga wire ke andar electron ek jagah se dusri jagah tak move nahi krte h but vo ek sath potential turn on krne par har jagah unka ek net movement hota h to current ki speed nahi define hoti vo inf. large hi hoti h kyui hum to 0s me flow krta hua hi maante h also current carrying wire ko tum aisa direclty relate nahi kr skte free moving e ke sath
Thank you, sir. Your lectures are awesome, you teach loads and loads of applications that no other teacher teaches. These are probably the best lectures for JEE on UA-cam. These lectures are truly wonderful, but I don't understand why they're underrated.
It is possible to have a velocity for which the given charges will travel parallel to each other.. And the important thing is that, it only depends on the medium in which they are traveling
33:54 i checked thrice before commenting this and i am still in doubt since no one has said this but is the formula used incorrect, upon 2pix should be there na
Wow, it is very interesting assessment you gave sir actually that velocity is independent of charge as well as distance between two chargers and it is speed of light, sir it's appealing to be a secret about the nature of light which is an Electromagnetic wave.....
Well I think if sir has considered a semi infinite strip then in denominator 4πx should come but if full infinite wire then 2πx should come in denominator
Sir , you are saying (at 4:39) that "Magnetic force is frame dependent, Electric force is frame dependent but lorentz force is frame independent." I can understand magnetic force being frame dependent as it is a velocity dependent force and velocity depends on the frame from which it is measured. However, I can't understand why electric force is frame dependent. Lorentz force being frame independent makes me think that some components that arise due to shifting frame of reference, cancel each other out making the resultant lorentz force same. However, I am not able to get the complete picture. Can anyone give me the reason for this without using complex mathematics/theory of relativity? What's the intuition behind this?
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
@@devesharya5184 ky logic lagaya bro,mtlb jisne bhi dp lagayi usko attention chahiye 😂👏, maine tere cmnt aur jagah dekhe is cmnt section me isliye batara.
@@sachinpatel9372 logic yeh lgaya h bhai ki tum cmnt kr rhe ho aur pta chal rha h ki yeh aadmi h qki tumhari thoooth hi armi h DP ME but me cmnt krunga kya pta chalega kon hai toh attention seeker kon hua
At 23:46 if V=c i.e speed of light the condition said could come true. But their is a twist classical magnetism dosent work when speed is compareble to speed of light so their should be no such velocitt possible i guess . Am i right sir?
At v=1/root(μoϵo) which is the speed of light(c) the net force on two charges will be ZERO. Thanks sir you are the greatest resource of study material in times like these....
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
Namste sir, At 33:00, why don't you use ampere circuital law to find magnetic field due to strip and and then the force on the wire due to that field. When I did like this, my answer coming out is u⁰i¹i²L/ pi(2r +b)
Reall thank you sir before my jee main Feb attempt I watch all your checklist and Iget quick revison of whole syllabus in 3 days just I got 92 in phy marks now I had strategy of 100 and I watch all videos of your channel for next attempt thank by heart your are my hero real hero 💓💓💓💓💓💓💓💓💓💓💓💓
2:40 (1) Emf force on moving charges
5:08 (2) magnetic firce on moving charges
14:53 (3) deflection by a sector of mf
17:20 (4) not completing circle
20:30 (5) force between two parallel charges
24:27 (6) magnetic force on a current carrying wire:-
26:19 (7) force between parallel current carrying wire
28:57 (8) magnetic force on a random shaped wire.
31:28 (9) magnetic force on a closed current carrying loop/coil
32:30 (10) magnetic force b/w a parallel wire and strip
37:05 (11) current carrying conductor on a inclined plane
40:31 (12) cases of impulse by magnetic force
45:16 (13) motion of a charge in both ef and mf:
--------- (14) torque on a coil in MF:-
56:41 (15) interaction energy of coil in mf and it's equilibrium
1:01:49 (16) magnetic flux through current carrying coil
1:08:17 (17) moving coil galvanometer
Luv u yar 😢
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@@physicsgalaxyworld I tell my frdz
@@physicsgalaxyworld sir mujhe 35:49 min pe correction lag raha h pls check
@@Ankityadav-jc8wr yes I also think 🤔
@@Ankityadav-jc8wr it should 2 pie r not 4pie
2 things sir loves the most and use everyday
1. Pogi
2. Right hand palm rule
Wait till you realise that he could use 2 on 1.
@@banana6963 sus
@@banana6963 🤣🤣🤣🤣
@34:10 there should be 2π in the denominator; the same illustration is taken in the pg basic concepts video lecture..!
I was looking for the same
Bade bade Saharon mai chotti chotti batein hoti rehti hein
@@αρτα-ν3σ pehli fursat me nikal
Sahi pakde hain
Yes bro 🤜 mein too got the same...
24:04 : If the charges are thrown with the velocity equal to that of light in vacuum, then the magnetic and electric force will be balanced.
But any material particle cannot have v greater than or even equal to speed of light.
[So, Fm can never balance Fe]
No particle except photon can have speed of light so such Fm can never balance Fe
@@poonamramawat7637 great point
1. Electromagnetic force on moving charges 2:40
2. Magnetic force on moving charges 5:12
3. Deflection by sector of MF 15:05
4. Not completing a circle inside a magnetic field 17:12
5. Force between two parallel moving charges 20:18
6. Magnetic force on a current wire 24:26
7. Force between parallel current carrying wire 25:52 [to be noted]
8. magnetic force on a random shaped wire 28:50
9. magnetic force on a closed current carrying loop
10. magnetic force between a parallel wire and strip
11. current carrying inductor on an inclined plane
12. cases of impulse my magnetic force
13. motion of charge in both EF and MF [didn't quite get it]
14. torque on a coil in MF
15. interaction energy of coil in MF and its equilibrium
16. magnetic flux through a current carrying coil
17. moving coil galvanometer
18. relation in magnetic moment and angular momentum of a rotating charge
19. torque on a 3D loop in magnetic field
23:40 These particle have to move with speed of light for net force to be zero.
yes!!
how mine is sq.root of 1/epsilon*u*
@@samarthraj2085 bro c square multiplied by mue not multiplied by epsilon not is equals to 1
Its a relation which can be derived by units and dimensions
@@samarthraj2085 that is exactly the value of light
36:35 magn force bet parallel wire n strip
40:59 rails type qs
1:06:44 magn flux
1:17:51 magn moment of rotating charge
1:21:49 torque on 3d loop
23:31
|Velocity of charge|=c(Speed of light)
33:37 it'll be 2π and not 4π (force btwn 2 current carrying parallel wires)
Yes
but the wire is semi infinite so 4π is correct
24:05 velocity should be equal to speed of light💡
Yes
More intuitively , μ0 x v^2 should be equal to ε0
24:10 When Velocity will be equal to Speed of light then Magnetic 🧲 Force will be equal to Electric ⚡ Force.
@jshdbdjdk Ndjfjfnrh no
@jshdbdjdkndjfjfnrh3654photons are neutral particles and have no rest mass, they wouldn't feel either magnetic or electric force
24:19 - It comes out to be speed of light.
These checklist>>>>>>>>>>»all day and night hectic classes of coaching...
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Sir toh mains bol k adv bhi cover krr dete hai.. ❤❤
Bhai konsa college mila ??
@@binodbhai0018 lol
Although never met sir but still these videos have established such a great connection...Thanks sir for your efforts
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@@physicsgalaxyworld 24:21 It would balance fe and fm at speed of light but practically it's not possible. Sir please tell the answer in comment section
@@physicsgalaxyworld 33:54 sir shouldnt the formula used have upon 2pix pls reply
@@guni-pj4clyes
@@guni-pj4clyeah I think
24:14 , answer, if velocity is of charges are equal to speed of light
Provided in free space
Sir I can't afford coaching classes but you have given me the feel of coaching classes, keep making such contents sir, I would totally love it. 👏👏👏Padnam Sir.
Respected sir, I would like to point a silly correction
in the 10th point viz. Magnetic force between current carrying wire and a strip
in the entire derivation along with final expression,
the denominator will be 2π instead of 4π
Yes Sir, Please make a correction because we (students) trust uhh like anything and if uhh make a point we just take note without checking.
@@anuragprasad3775 Be concious while watching lectures...don't just write what is in the screen!
yes that was a mistake ig
Yes bro
might be possible that he had taken semi infinite strip in that case 4π is correct
In case of parallel moving charges, the value of magnetic force and value of electric force will be equal if both the particles are projected with the speed = 1/sq root {(permittivity of free space)(permeability of free space)}, i.e., with the speed of light.
Correct ✓✓✓
at 23:45 ..... Sir , the Answer to special case of force equality is v=speed of light =1/sqrt(ep0xmue0).... great eyeopener sir... wahat
Most dedicated teacher in our world
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Sure sir !!!
@@physicsgalaxyworld Sir Please reply to my comment
@@marutin8357 please comment earlier,during the video release
Best teacher in world
33:38 , there should be 2pi instead of 4pi. PLZ correct me if i am wrong.
Absolutely correct...sir had made a mistake.........maybe it's intentionally that he did to check if we just revise lightly or thoroughly.
@@prabalpratapsingh9699 😂bruh
Yes same
Yes bro you are correct
Magnetic field is observed due to finite wire so that's why, here 4pi is correct
2:31
I felt like I was sitting in doremon's time machine 😂 😎😎
Damn 😂😂😂🤣🤣🤣🤣
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For the question on 24:00 . Particles should move with speed of light
23:45 the particle should have the velocity of 1/√u0e0 which is equal to c(speed of light)
pls sir hear me out 36:00 in the question of pareller wire and width wire magnetic field due to wire should uo/2pi because it is infinite wire
I also have the same query but I think that sir might have considered a semi infinite wire as sir has extended the sheet only from top.
Vahi to lia hai b=uoI/2py.x
@24:00 speed of light 3*10^8 (answer of the HW question)
Super best channel on UA-cam no where else you would find this gem ✨
23:51 At the speed of light, Force due to both magnetic and electric fields become equal which not possible. So it is an ideal condition.
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
@@theb4stguy332 Absolutely
24:05 - The velocity at which the net force becomes 0 comes out to be c (Speed of light).
Which is not possible
that's true i got same
@@imPriyansh77 why?
@@nishchaykumar6942 No material particle can have speed greater than or equal to c.
@@imPriyansh77 where you studying at, stanford?
for v=c Electric force can balance magnetic force 24:23
23:19 , such velocity≈speed of light..
I am right ?
Most effective Initiative Checklist sirji..
Really it's helping a lot..
Thanks *SIR* 🔥♥️✨
@E s s Pradeep solve the equaton then u can see that it coming equal to speed of light
which is not possible to achieve thus it is not possible
don't look for the answer, look for the question that at c the mass becomes infinite ........ then still same laws follows ? :))
@@devesharya5184 we've assumed that the charged particles are massless, hence the result becomes independent of mass.
@@ikrgauravCharge is a property of Mass ! ( assumption hi lerhe ho toh kuch bhi assume kr skte hain it doesn”t matter )
@@devesharya5184 oh, thanks for information :)
23:32 q1q2/r² will get cancelled from both equations and v²/10⁷ = 9*10⁹
Thus v = ✓9*10¹⁶ = 3*10⁸ m/s which is the speed of light (approx)
Button for jee 2024 😅
Yes
Neet 2024 😂
NTA ne dhoka de diya bhai 27 aur 29 valo ko 😂 koi na ab April attempt mein phodenge
What is your percentile
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24:20, No it is not possible until and unless we consider a hypothethical case as Here the velocity between then is equal to The velocity of light which is not Possible for any particle to gain that speed yet
When velocity equals to speed of light (C).. Magnetic and electric forces becomes equal...... And thanks u so much sir for this amazing content😄 🙏🙏🙏
Yup !!!!!!!!!!
😪 already commented..I thought I would..
@@sriKritarth bro same name😁😁
@@kritharthbaishnab Highly unique, I found a few people and congrats you are one of them
At 23:46 if V=c i.e speed of light the condition said could come true. But their is a twist classical magnetism dosent work when speed is compareble to speed of light so their should be no such velocitt possible i guess . Am i right sir?
At 24:04 the particles must attain the speed of light so as to balance the force of attraction and repulsion by magnetic field and coulombs force respectively. Hence it is not possible for them to balance each other as speed of light can't be attained
Yes sir both magnetic force and electrostatic force can balance each other if velocity will be equal to speed of light
24:00 the answer is v=3x10^8 m/s i.e with the speed of light
Aap hamare liye kitna kuch kar rahe hai thank you very much sir and love you. U r a best physics teacher. Aise hi achhe achhe vdos jee advanced ke liye bhi plz lana
we luv u sir
@@sarthakbavdhankar4444 hey
23:00 sir electrostatic aur magnetic force ka barabar hone ke liye velocity of charges ko 3×10⁸ speed of light ke barabar hona padega
Fe=Fm when both charges move with the speed of light.
Yes
tui kolkata e thakis??
@@samirmondal4624 Hyan
Yes when v equals c
@@SohamChakraborty42069 what is your rank bro
At 24:05 Sir for Fm=Fe the velocity must be equal to speed of light which is 3×10^8 which is practically not possible
23:44 answer is 1/√ue
@23:48 Yes, Sir, it is possible if both the charges are moving at speed of light.
Jee 2025 💀
24:20 Sir, the velocity is speed of light. If the velocity is less than the speed of light then Fe will dominate over Fm and as a result it will face repulsion.
But in case of two wire carrying current in same direction we have seen that the wire repel each other only by considering magnetic force only.
So, does it mean that the velocity of electrons in wire are more than velocity of light.
shyd tumne padha hoga wire ke andar electron ek jagah se dusri jagah tak move nahi krte h but vo ek sath potential turn on krne par har jagah unka ek net movement hota h to current ki speed nahi define hoti vo inf. large hi hoti h kyui hum to 0s me flow krta hua hi maante h also current carrying wire ko tum aisa direclty relate nahi kr skte free moving e ke sath
Sir light ki speed se Dale ge to net force zero ho jayega 24:19
24:09 The net force on the two identical charges will be Zero if they move with velocity equal to the speed of light in the same direction.
Sir in magnetic force between strip and wire you have take 4π in denominator but there is 2π in the previous slide
At 24:07 , This case is only possible at speed of light .
Thank you, sir. Your lectures are awesome, you teach loads and loads of applications that no other teacher teaches. These are probably the best lectures for JEE on UA-cam.
These lectures are truly wonderful, but I don't understand why they're underrated.
Because most of the public goes for 'cheap' things
Its good, we will have less competition, other public will go for Alecc the almightly emotionless wallah and then later regret at last.
It is possible to have a velocity for which the given charges will travel parallel to each other..
And the important thing is that, it only depends on the medium in which they are traveling
33:54 i checked thrice before commenting this and i am still in doubt since no one has said this but is the formula used incorrect, upon 2pix should be there na
yes
exactly bro same
24:21 no because partical required light speed to get net force zero
24:10
Is the answer to this question is v=1/√μ°€°?? 🤔🤔
At 44:49, Sir, as the flux is changing, I think you should have also considered induced emf and current in the rod. I didn't understand exactly.
24:20 the speed must be speed of light
23:41
no, cause it will require v=c that cannot be achieved
IF the trajectory is cycloidal then can we apply mv^2/r ? ,At 49:00
34:19 - In Denominator 2 pi b should come .
yup.
Wow, it is very interesting assessment you gave sir actually that velocity is independent of charge as well as distance between two chargers and it is speed of light, sir it's appealing to be a secret about the nature of light which is an Electromagnetic wave.....
Yeah
Intresting result
24:18 V=E/B sir that velocity in wgich fm=Fb
the best revision source I have ever seen.. thank you sir..
33:42 it should be u°dI1*I2L/2πx
33:26 shouldn’t it be 2 pi x in the dnr…?
Yesss
S
Yes
Yup
Well I think if sir has considered a semi infinite strip then in denominator 4πx should come but if full infinite wire then 2πx should come in denominator
Sir , you are saying (at 4:39) that "Magnetic force is frame dependent, Electric force is frame dependent but lorentz force is frame independent."
I can understand magnetic force being frame dependent as it is a velocity dependent force and velocity depends on the frame from which it is measured. However, I can't understand why electric force is frame dependent. Lorentz force being frame independent makes me think that some components that arise due to shifting frame of reference, cancel each other out making the resultant lorentz force same. However, I am not able to get the complete picture.
Can anyone give me the reason for this without using complex mathematics/theory of relativity? What's the intuition behind this?
Watch concept videos of Physics Galaxy for this
@@physicsgalaxyworld Ok Sir
Sir you made a mistake at 33:40 there should be 2π in the denominator, not 4π.
Yes you are absolutely right
How can u explain me in detail plz bro im not understanding plz help
@33:50 it should be 2 pi in the denominator, not 4 pi
Sir thanks for your effort . The answer is c speed of light at which electrostatic force can balance out magnetic force
Yes sir light velocity se chalne pr dono force bal ho jayenge🙏..at 24:00
Plz make a video on How to prepare for Physics Olympiad and how to manage it with JEE preparation
Noted.
24:12 electrostatic force and magnetic force can balance each other at velocity = speed of light
To all my juniors
Add current sensitivity(BNA/C) and voltage sensitivity (BNA/CR).
Edit: 'c' is torsional constant
thanks a lot
What is the meaning of R?
Resistance
@Physics Galaxy 23:50 Ans is v = 1/(u°€°)½
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
Sir SHIVRATRI KI HARDIK shubhkamnaye.....meri bhagwan SHIV JI se prarthna hai ki aap hamesha khush rahe
Thank you so much beta, aap bhi humesha khush rahe aur safalta prapt karein. Saath mein subscribe bhi kare :)
@@physicsgalaxyworld 😂😂😂
@@physicsgalaxyworld 😂😂😂😂
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@@physicsgalaxyworld happy Mahashivratri 2021 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
24:06 sir speed of light use krenge tb possible hi but speed of light is not practically possible to achieve 😊
33:43 It must be /2πx not /4πx.
Exactly..no one in comment section talked about it..i was doubting on my concepts😂😂
Sir in 33:48 it shuold be 2 pi r istead of 4 pi r
Holy shit! Its when they travel with the speed of light!! Fascinating.
@@devesharya5184 tu har cmnt pe gyan chodra hai, attention seeker
@@sachinpatel9372 ok bhai hta deta hu apna comment but attention chahiye hota mujhe toh tumhari trah Apni DP lga kr rkhta
@@devesharya5184 ky logic lagaya bro,mtlb jisne bhi dp lagayi usko attention chahiye 😂👏, maine tere cmnt aur jagah dekhe is cmnt section me isliye batara.
@@sachinpatel9372 logic yeh lgaya h bhai ki tum cmnt kr rhe ho aur pta chal rha h ki yeh aadmi h qki tumhari thoooth hi armi h DP ME but me cmnt krunga kya pta chalega kon hai toh attention seeker kon hua
@@devesharya5184 kitna pyara logic lagaya h👏, WoKE netizen ho kya😂
39:21 Be careful while calculating direction of force while facing the screen you may break your wrist
Revise this checklist before JEE 2021....Im gaining confidence Thanks A lot Sir❤️
hello bro 2 years later how did your exam go?
At 23:46 if V=c i.e speed of light the condition said could come true. But their is a twist classical magnetism dosent work when speed is compareble to speed of light so their should be no such velocitt possible i guess . Am i right sir?
PG TEAM PLS. REPLY REGARDING FORMULA @34:23...IT SHOULD BE 2π IN DENOMINATOR INSTEAD OF 4π???
yaa
Yess
24:20 if v=1/√u€° which is speed of light
Answer to your exercise is 3×10^8 m/s which is really interesting (Speed of Light)
Yes
24:06 Speed of light is required to balance out
Legend of the physics
16:00 to 20:00 deflection
24:00
32:00 10
35:00 sn
At v=1/root(μoϵo) which is the speed of light(c) the net force on two charges will be ZERO.
Thanks sir you are the greatest resource of study material in times like these....
sir answer of the question u asked at 23:47 is when velocity becomes equal to speed of light then the forces become equal
On substituting experimental values of mu and epsilon which are 4π*10^-7 and 1/(4π*10^9) we get it equal to 3*10^8 m/s which is nearly equal to actual speed of light in vacuum with an error of 0.069% bcz actual speed of light is 299792458 m/s
This revision lecture is > 10000 lecture 🔥🔥🔥😍💯💯
This is one of fond checklist Question on JEE main were from each and every point of this checklist..
24:00 the velocity will be c i.e. speed of light ....am i right?
Yeahh
34:42
37:20
44:33
1:23:15
Thnq very much for u r efforts sir.. 🥰😍
Thanks for your appreciation Sahan, please subscribe and tell your friends.
Namste sir,
At 33:00, why don't you use ampere circuital law to find magnetic field due to strip and and then the force on the wire due to that field.
When I did like this, my answer coming out is u⁰i¹i²L/ pi(2r +b)
with speed of light , answer of question in 5 slide
17:00 Sir if I apply tandelta = Vy/ Vx
I get the same result but as tan‐¹ instead of sin‐¹ in
Reall thank you sir before my jee main Feb attempt I watch all your checklist and Iget quick revison of whole syllabus in 3 days just I got 92 in phy marks now I had strategy of 100 and I watch all videos of your channel for next attempt thank by heart your are my hero real hero 💓💓💓💓💓💓💓💓💓💓💓💓
how was your mains and advance ?
hey bud are his videos enough to score 92?