Problems on Properties of Relations Equivalence Relation Posets Part1-Relation- Discrete Mathematics

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  • Опубліковано 7 лис 2024

КОМЕНТАРІ • 20

  • @marywangui-i1v
    @marywangui-i1v 2 дні тому

    Thanks sir.... excellent teaching 👌

  • @maruthirompicherla4549
    @maruthirompicherla4549 Рік тому +1

    excllent teaching sir
    you are awesome sir

  • @trailone6417
    @trailone6417 10 місяців тому +7

    R8 can't be transitive as it includes (3,1) & (1,4) then there should be (3,4) but that is not in the set.. ?!!

  • @shreyaupadhyay1447
    @shreyaupadhyay1447 11 місяців тому +1

    Thank you sir, dher ghante baad exam hai

  • @shreyaskhatavkar9976
    @shreyaskhatavkar9976 8 місяців тому +1

    u are god sir

  • @prathameshzingade6791
    @prathameshzingade6791 Рік тому +5

    kal exam hai aur aaj padd rahe hai sab!

  • @skrehanakhtar4757
    @skrehanakhtar4757 9 місяців тому +2

    R8 not Transitive

  • @sejal_0438
    @sejal_0438 6 місяців тому

    Why you're not taking Assymetric
    Irreflexive sir

  • @ladisravya
    @ladisravya 11 місяців тому +1

    A×A mey toh sab element rahega?

  • @mrreyance1587
    @mrreyance1587 Рік тому +1

    thank you sir, kal exam hain

  • @Unknownvloger55
    @Unknownvloger55 4 місяці тому

    According to you the concept you gave about Anti symmetry is wrong here
    If (a,b)∈R,(b,a)∈R⇒ a=b,for all a,b∈A is the right equation for anti symmetry.And symmetry and anti-symmetry are not opposite

  • @ladisravya
    @ladisravya 11 місяців тому +1

    Sir R7 antisymmetric me nhi ayega kya?

  • @priyanshugupta1592
    @priyanshugupta1592 Рік тому

    sir jo aapne transitive ke liye R5 bataya uske according dekhe , to R9 me (4,2),(2,4) ko swap kre to (2,4),(4,2) so it is (2,2) to sir ye to present h set me...fir ye transitive kyu nhi hua ???

    • @ssukhani29
      @ssukhani29 Рік тому +2

      because in r9 (1,3)(3,1) so it should be (1,1) so (1,1) doesnt exist in r9

  • @Unknownvloger55
    @Unknownvloger55 4 місяці тому

    According to you the concept you gave about Anti symmetry is wrong here
    If (a,b)∈R,(b,a)∈R⇒ a=b,for all a,b∈A is the right equation for anti symmetry.And symmetry and anti-symmetry are not opposite

  • @Unknownvloger55
    @Unknownvloger55 4 місяці тому

    According to you the concept you gave about Anti symmetry is wrong here
    If (a,b)∈R,(b,a)∈R⇒ a=b,for all a,b∈A is the right equation for anti symmetry.And symmetry and anti-symmetry are not opposite