Cambridge University Entrance Exam Tricks | Find (a,b)=?

[@KeyserTheRedBeard]

Great video, Super Academy. Looking forward to seeing your next upload from you. I smashed the thumbs up button on your content. Keep up the fantastic work! Your breakdown of the quadratic equations was really clear. Could you elaborate on how you approach factoring in more complex scenarios?

[@superacademy247]

Thanks and sure. I'll work on factoring tough math questions 💡🥰😎😋😋💯

[@raghvendrasingh1289]

a^2 - b^2 = b - a
a+b = -1 because a and b are unequal
now b = a^2 - 183 hence
a^2+a -182 = 0
(a+14)(a-13) = 0
if a = - 14 then b= 13
if a = 13 then b = - 14

[@tassiedevil2200]

This seems much more direct.

[@superacademy247]

Thanks for sharing 👏🙏🤩💕🙏

[@FirstLast-n5b]

Exactly what I did. What to do here for 14 minutes???????? NB to be complete you have missed one step. After a^2-b^2=b-a it is good to say => (a-b)(a+b)=-(a-b) => a+b=-1

[@tassiedevil2200]

Since the initial equations are unchanged by exchanging a and b it is hardly surprising the two roots for your final quadratic are the solution pair.

[@superacademy247]

That's a great observation! 💯You're right - that's a key insight. 🙏

[@RyanLewis-Johnson-wq6xs]

a^2=b+183 b^2=a+183 (a,b)=(13,-14) or (a,b)=(-14,13)

[@cabasantbab]

A 14
B - 13

[@RyanLewis-Johnson-wq6xs]

It’s in my head

[@nikolayplatnov5148]

If a is not equal to b, then a+b=-1. Then its,easy 7:55 to resolve a square equation.

[@elliotlambert3817]

A and B have to be = the equations are =

[@prollysine]

(a-13)(a^3+13a^2-197a-2562)=0 , a=13 , b=a^2-183 , b=-14 , a^3+13a^2-197a-2562=0 , (a+14)(a^2-a-183)=0 , a= -14 , b=13 ,
sulu , (a,b) = (13 , -14) or (-14 , 13) ,
/ a^2-a-183=0 , a= (1+/-V(1+4*183))/2 , a=(1+V733)/2 , b=(1+V733)/2 , ---- a=(1-V733)/2 , b=(1-V733)/2 , a=b , not a solu , / ,