The Abstract World of Operational Calculus

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  • Опубліковано 6 вер 2024

КОМЕНТАРІ • 211

  • @akdn7660
    @akdn7660 2 роки тому +88

    You managed in fourteen minutes to render about a quarter of my college math courses redundant. Subbed.

    • @vnever9078
      @vnever9078 2 роки тому +2

      Based channel, based comment. Liked.

    • @MDNQ-ud1ty
      @MDNQ-ud1ty Рік тому +3

      If you learned category theory you would realize life is redundant. If you learned about "capitalism"(economics, psychology, finance, evolution, and politics) you would realize why college is redundant.

    • @TecknoVicking
      @TecknoVicking 9 місяців тому +3

      Yeah... as if what you previously learned has nothing to do with understanding this video...

  • @tomctutor
    @tomctutor 2 роки тому +31

    The simple shift Theorems themselves are very useful, you can even apply these ideas to integration:
    D^(-1) ≡ ∫
    D^(-n) ≡ ∭..nX
    or multivariate calculus;
    ⅅ_t f(x,t)= ∂f/∂t ⇒ e^(Tⅅ_t) f(x,t) = f(x, t+T) which is very useful when using periodic functions like trig.
    the list is endless and because we are dealing with linear operators, we are familiar with
    e^(DA) I = 1+A, where A^2=[0] the nul matrix.
    Yes totally agree a very powerful analytical technique if you deploy operational methods!
    Thankyou for a very well presented video, I appreciate the amount of work you put into making this, Mathologer would be proud!

  • @GeoffryGifari
    @GeoffryGifari 2 роки тому +42

    as a physicist, i imagine the shift operator working similarly to "ωt" expression in a wave ψ(x,t)=exp(ikx-ωt), so now we have a pattern that moves

    • @eliavrad2845
      @eliavrad2845 2 роки тому +17

      Yeah, quantum mechanics is mainly operational calculus (plus wave mechanics, probability, regular linear algebra...). The most famous exponentiated operator is the formal solution to Schrodinger equation exp(Ht/iℏ)|Ψ(0) ⟩ = |Ψ(t) ⟩ i.e. the time translation equation for the physical state |Ψ(0) ⟩ with propagator U= exp(Ht/iℏ) to the physical state at time t |Ψ(t) ⟩ . H, the Hamiltonian or energy, is at least a second order differentiation operator H=-(1/2m) ∂^2/∂x^2+U(x), with the kinetic energy -(1/2m) ∂^2/∂x^2 and the potential energy U(x) which is just a regular function.
      Especially in physics context, a lot of time the differential operator is shorted to ∂, rather than D, so expect a lot of ∂^2, ∂_x, ∂_t.

    • @hyeonsseungsseungi
      @hyeonsseungsseungi Рік тому +1

      Yeah! It's also amaging
      in quantum mechanics.

  • @mehulborad2400
    @mehulborad2400 2 роки тому +15

    U know when you mentioned the factorisation of linear diff eq i paused the video and then tried to prove everyting rigorously and it was very beautiful how linearity can be exploited and i actually had then thought of the solutions to recursive relationals as well. At this point i was amazed and in awe at how abstractness is not only beautiful but very useful and guess what u go ahead and take the inverse of 1-d and the Fiinng geometric series to find the solution of a very famous diff eq in one step 🤣🤣🤯🤯🤯. I HAVE NO WORDS i am still jumping around like a mad man at how CRAZY this is. This has gotta be one of if not the most beautiful thing i know . Never expected differentiantion to work like this, it was always very tricky to find solutions, yet somehow magically hidden from me all this time it was secretly behaving like a real variable and polynomial. INSANE JUST INSANE

    • @Supware
      @Supware  2 роки тому +3

      Really glad you were able to experience the video this way! :) this is pretty much what I went through while writing it

    • @MessedUpSystem
      @MessedUpSystem Рік тому +3

      I've completely lost it when he divided by 1-D and expanded as a power series xD

  • @ILSCDF
    @ILSCDF 2 роки тому +92

    Jaw dropping

    • @brendanmiralles3415
      @brendanmiralles3415 2 роки тому +3

      I started this video assuming this comment was hyperbolic... it was not

  • @logo2462
    @logo2462 2 роки тому +21

    Wow! This really cleared up why we can solve recurrence relations with “auxiliary polynomials”. My finite math course just had us plug and chug to solve these!

    • @Supware
      @Supware  2 роки тому +9

      This is something I really wanted to get right in particular :) I was wondering why auxilary polynomials work for differential equations, since I was similarly taught about them without explanation

    • @pantoffelkrieger8418
      @pantoffelkrieger8418 2 роки тому +4

      Another great way to derive these "auxiliary polynomials" is by looking at the generating function of the series. If you haven't heard of that, you should check it out; it's pretty cool.

    • @Supware
      @Supware  2 роки тому +4

      @@pantoffelkrieger8418 what that guy said :p if you're interested in this stuff and somehow haven't come across generating functions yet there are plenty of excellent videos on them here on yt

  • @EpsilonDeltaMain
    @EpsilonDeltaMain 2 роки тому +60

    Wow I was going to make a video on this topic eventually, and you did it so much better than what I would have done!! Congrats

    • @ILSCDF
      @ILSCDF 2 роки тому +1

      Hey, I love your videos

    • @EpsilonDeltaMain
      @EpsilonDeltaMain 2 роки тому

      @@ILSCDF thank you

    • @juanaz1860
      @juanaz1860 2 роки тому

      Still make it. I'm still don't understand 100% of this video even after watching the umbral video n this one

    • @alang.2054
      @alang.2054 2 роки тому

      @@juanaz1860 did you end your calculus 1?

    • @juanaz1860
      @juanaz1860 2 роки тому

      @@alang.2054 I did college Calc 1,2,3, diff eq, linear algebra

  • @lexinwonderland5741
    @lexinwonderland5741 2 роки тому +40

    I can't WAIT for the rest of this series! Both of your videos were extremely eye-opening even to a long-time maths student like me, and gave me that wonder of when I was first discovering a new field. Please please please keep it up, great job!

  • @Sk8aterBoy132
    @Sk8aterBoy132 Рік тому +3

    My mind exploded seeing how Binet's Formula was so easily derived just by treating the translations in the recurrence relation as linear operators.

  • @dmytrolevin738
    @dmytrolevin738 Рік тому +9

    I was familiar with operational way to solve ODEs, but it have never come to my mind that this idea can be extended this far. This is amazing! Looking forward to the next video.

  • @hwendt
    @hwendt 2 роки тому +45

    Keep it up man, you are making great videos.

  • @gustavoexel5569
    @gustavoexel5569 2 роки тому +4

    Almost all of these ideas we learn separately in college for example, within its own applications. What I found watching this video is that operational calculus makes these ideas so much closer, and interrelated among themselves, without the need for so much arbitration when deriving concepts and ideas. Really enlightening

  • @ianrobinson8518
    @ianrobinson8518 2 роки тому +7

    This topic was first treated in great depth as far back as the mid-1800s. The types of general results that came out it are fascinating but all but forgotten. It is actually a sub-topic of became known as the calculus of finite differences.
    It was used a lot in empirical research areas and professions such as actuarial studies. With the advent of computers, the topic fell by the way side.
    Old treatises can still be found online and Schaum had an edition covering it thoroughly.

    • @4grammaton
      @4grammaton 5 місяців тому

      Why did computers render this topic redundant, and is there is a reason why it could make a comeback?

    • @ianrobinson8518
      @ianrobinson8518 5 місяців тому

      The methods were used to provide numerical solutions to otherwise intractable big data problems in insurance and other professional fields. The old methods required simplifying assumptions, slide rules and log tables. Desktop calculators and mainframe computers went some of the way to easing the burden, but it was the advent of the
      modem desktop computer with almost unlimited computing power and ubiquitous tools such as spreadsheets which allowed us to dispense with approximations.
      I’ve no doubt that the finite calculus is used at a rudimentary level in some fields of work and research. However the subject matter was developed to a great depth with magical formulae and approaches somewhat akin to infinitesimal calculus’s. This is what has been “forgotten” and no longer taught.

  • @alejrandom6592
    @alejrandom6592 2 роки тому +5

    I understood the thumbnail just by reading it, yet I had never thought about it before. Just beautiful.

  • @KakoriGames
    @KakoriGames 2 роки тому +8

    Umbral Calculus didn't interest me that much, but Operational Calculus intrigued me that I went back and watched both videos. And boy, I don't regret doing that, awesome videos, can't wait for more.

  • @pacotaco1246
    @pacotaco1246 3 місяці тому +3

    I am now upset that they didnt teach us operational calculus upfront when i was learning quantum mechanics. Wtf, this clicked immediately

  • @defenestrated23
    @defenestrated23 Рік тому +3

    11:38 - mind=BLOWN. This reminds me of dual numbers and how exp(a+bê) acts like a scale & translation, which means translation is like rotation around a point at infinity. It also kind of implies ê (epsilon, ê^2=0) IS the differential operator. You should also do a vid on dual quaternions!

  • @AshleyCog
    @AshleyCog 5 місяців тому +1

    Using the first principles of differentiation you can right D in terms of T, h, and the "limit as h approaches 0" operator, D=L_(h -> 0)h^-1(T^h-1). Rearranging and replacing T with e^D, you can get a formula for this limit operator, L_(h -> 0) = hD(e^(hD)-1)^-1. Let h = 1 and replace e^D-1 with Delta to get L_(1 -> 0)=D(Delta)^-1 so the Bernoulli operator is the same as taking the limit as 1 approaches 0. The inverse of the forward difference is the sum so L_(1 -> 0)=D*Sigma is a cleaner form.
    This operator converts discrete problems into continuous. If you want to calculate the sum you can instead take the integral of the limit as 1->0 of the function. of if you want the forward difference you can instead take the limit as 1->0 of the derivative.

  • @oblivion5683
    @oblivion5683 Рік тому +2

    The moment you got phi to just pop out of nowhere I literally screamed! "No fucking way! Holy Shit!!!"

  • @hemat8129
    @hemat8129 2 місяці тому

    As a first-year electrical engineering student, the D operation was a mystery for me. Thanks for making this mystery more mysterious.

    • @Supware
      @Supware  2 місяці тому

      The D thing is just shorthand for d/dx haha, anything you want clarifying?

  • @Orionhart
    @Orionhart 2 роки тому +9

    The hard work you put in to these videos shows. I hope more folks see this video, and maybe some drop you some Patreon! Proud to be a patron.

  • @Bruno-el1jl
    @Bruno-el1jl 2 роки тому +10

    This is completely insane! Amaaaazing video
    The shift in mental model for the e^(a+bi) to the D case was mind blowing
    Curious: where dos this fail? And why?

  • @andy_lamax
    @andy_lamax 2 роки тому +3

    Umbral Calculus and Operation Calculus are a marvel in the math world

  • @netcat22
    @netcat22 2 роки тому +9

    I'm looking forward to your next videos! These topics are so interesting

  • @denki2558
    @denki2558 2 роки тому +2

    Fascinating. I used the thumbnail formula to derive the forward difference formula in just a few lines.
    With some rearranging, the backwards and central difference formula can be derived as well. It amazed me to see that the central difference formula has some connections to arcsinh.
    Our numerical methods prof didn't show derivations. I'm glad to learn that I could derive them on my own now.

  • @yamansanghavi
    @yamansanghavi 2 роки тому +3

    Wow, this was so good. Thanks a lot. A lot of things are something we know from quantum mechanics or differential equations but seeing them under one roof is absolutely amazing.

  • @zuzaaa1998
    @zuzaaa1998 2 роки тому +22

    These ideas are also applied to partial differential equations where you can solve equations by using formal sums of laplacian operator. I remember that these ideas were really fascinating form me during my PDE classes but I haven't seen much of it since then. Do you have any books recommendations on the operational calculus?

    • @Supware
      @Supware  2 роки тому +13

      Not yet I’m afraid, but I think I’ll need to find some books before I continue this series! I’ve been recommending Rota - Finite Operator Calculus and Roman - The Umbral Calculus but those are more umbral than operational

  • @pandavroomvroom
    @pandavroomvroom 5 місяців тому +2

    this channel is underrated

    • @Supware
      @Supware  5 місяців тому +2

      I do need to make another video eventually haha, but thank you!

  • @diana-pestana
    @diana-pestana Рік тому +1

    Soooo awesome! Simple and elegant, yet such non-trivial results!

  • @__-cx6lg
    @__-cx6lg 2 роки тому +3

    bruh i started cracking up laughing when you expanded (1-D)^-1 as a geometric series 😆 And it actually works!!
    And then you did that thing with e^D.... I am flabbergasted
    This video is great

  • @toizh_x
    @toizh_x Рік тому +2

    Theres "Guy Drinks Soda and then Turns Distorted Meme but it's an ADOFAI Custom Level" and theres this:

  • @braden4141
    @braden4141 2 роки тому +2

    7:05 in the video couldn't f(x) also be a multiplied with a periodic function with period 1 and still be a solution to the equation.

  • @matiasbpg
    @matiasbpg 2 місяці тому

    Great video! I always found interesting how these concepts are made rigorous and expanded in functional analysis and operator theory. Also extensively used in quantum physics

  • @TC159
    @TC159 2 роки тому +1

    Thanks for the shoutout, great video!

  • @fedorkochemasov4533
    @fedorkochemasov4533 2 роки тому +1

    Never could I ever imagine that subtracting a number from a letter would get me a triangle

  • @DrJaneLuciferian
    @DrJaneLuciferian 2 роки тому +1

    I am really looking forward to seeing more of this series. These first two videos are great.

  • @alejrandom6592
    @alejrandom6592 2 роки тому +3

    I was amazed by the fact that, it seems just so simple now the way you can solve for nth fib number

  • @GeoffryGifari
    @GeoffryGifari 2 роки тому +1

    darn knowing abstract algebra seems very useful for stuff like this

  • @DepozidoX
    @DepozidoX 2 роки тому +1

    Looking at 11:50, these can serve as transformations between the addition and multiplication worlds. I think that such transformations could be really useful to solve some hard number theory problems.

    • @Supware
      @Supware  2 роки тому

      Not number theory per se but 3b1b has a couple videos (e.g. 'Euler's formula with introductory group theory' ) about these ideas :)

  • @TheActurialRepository
    @TheActurialRepository Рік тому +1

    Thank you, this was sublime.

  • @ZeDlinG67
    @ZeDlinG67 2 роки тому +2

    this is what Grant had in mind when started the #some

    • @Supware
      @Supware  2 роки тому +2

      This is certainly becoming a passion :p and I probably wouldn't have gotten started without the nudge from Grant

  • @GeoffryGifari
    @GeoffryGifari 2 роки тому +2

    all of these sound real arcane. you mathematicians are real life wizards

    • @angeldude101
      @angeldude101 2 роки тому +1

      Well the previous video on this channel was on _Umbral_ Calculus, which seems to have been named such because it looked like witchcraft.

  • @inventorbrothers7053
    @inventorbrothers7053 5 місяців тому +2

    Just superb

  • @Duskull666
    @Duskull666 Рік тому

    As a physics and electrical engineering student this absolutely jaw dropping!

  • @scottmiller2591
    @scottmiller2591 9 місяців тому

    Looking forward to more videos like this one.

  • @OdedSpectralDrori
    @OdedSpectralDrori 2 роки тому +1

    great video, super fun but insightful.

  • @asthmen
    @asthmen Рік тому +1

    These are really fun topics! One question about your DE example, (D + 3)(D + 2) f = 0. Is it not possible for (D+2) f to land in the kernel of (D+3) without f itself being in that kernel? Obviously (D+2) f = 0 means f is in Ker(D+2), so... let g = (D+2) f. Then (D+3) g = 0 implies g \in Ker(D+3), so g = c exp(-3x). Then (D+2) f = g = c exp(-3x) means that
    f = c (D+2)^-1 exp(-3x) + h, h \in Ker(D+2)
    is there something in the commutativity properties of (D+2) and (D+3) that says that (D+2)^-1 g has to stay in Ker(D+3)?

    • @Supware
      @Supware  Рік тому +1

      There are people smarter than me in the Discord server who can answer questions like this effectively :p

  • @gabrieletrovato3939
    @gabrieletrovato3939 5 місяців тому +1

    Thank you so much!! 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

  • @Henriiyy
    @Henriiyy 2 роки тому +1

    "Despite the lack of rigour..." As a physicist, this makes me comfortable xD

  • @logicprojects
    @logicprojects 2 роки тому +1

    Great video! What an interesting way to think about things!

  • @LukePalmer
    @LukePalmer 2 роки тому

    This is the coolest math I have seen in a long time. Love it, thank you!!

  • @00000ghcbs
    @00000ghcbs 2 роки тому +1

    Duuude, great stuff, keep it coming

  • @yash1152
    @yash1152 Рік тому

    Wow, there's also a new section of corrections in youtube. wowwww!!

  • @GustavoOliveira-gp6nr
    @GustavoOliveira-gp6nr 2 роки тому +1

    This is way too cool

  • @Fru1tyy
    @Fru1tyy 2 роки тому +1

    These are some novel concepts that I've not seen before, interesting stuff

    • @Supware
      @Supware  Рік тому

      no idea why I didn't give this a heart earlier :D

  • @crueI
    @crueI 2 роки тому +1

    Subbed immediately.

  • @Thejosiphas
    @Thejosiphas Рік тому

    fire. i wish they taught us this in odes!!!! i hate analysis & love operator algebras

  • @cthoyt
    @cthoyt 2 роки тому +1

    super cool, can't wait for the next one

  • @ichigo_nyanko
    @ichigo_nyanko 2 роки тому +3

    Where can I learn more about this stuff-umbral calculus, the shift operator, etc? It's all so cool and interesting I'm amazed I was never taught any of this before! It looks like it has some really cool applications as well. It doesn't have to be books, videos, anything is okay. Telling me what the subject is called would go a long way! Is operational calculus part of abstract calculus or are they separate things? The same with umbral calculus, is that part of abstract calculus?
    Where did you learn this stuff?
    I also always annoyed at people factoring differential equations but being completely unable to explain why that is okay.

    • @Supware
      @Supware  2 роки тому

      It seems operational and umbral calculus are just different names for different approaches to this stuff. 'Functional calculus' is another keyword, and I've been recommending Roman's and Rota's books on the subject. Most of my personal "research" so far has just been translating Wikipedia I'm afraid lol
      "Abstract Calculus" doesn't mean anything canonically as far as I know, it's just the name I gave to this series

    • @angelmendez-rivera351
      @angelmendez-rivera351 2 роки тому

      @@Supware I think abstract calculus probably refers to calculus in arbitrary topological spaces, generalizing to the maximum.

    • @mastershooter64
      @mastershooter64 2 роки тому

      I bet it's a part of functional analysis and operator algebras

  • @calvingakunju7580
    @calvingakunju7580 2 роки тому

    these ideas are so beautifully explained

  • @dj_laundry_list
    @dj_laundry_list 2 роки тому +4

    l am so insanely mad that I wasn't taught calculus, or at least DiffEq this way. Learning the algebra of any kind of operators (or mathematical objects in general) should be considered essential

    • @Supware
      @Supware  2 роки тому

      Agreed!

    • @jinjunliu2401
      @jinjunliu2401 Рік тому

      For linear operators that'd be something you might see in a linear algebra course :)

  • @mrtfttkhv
    @mrtfttkhv Рік тому

    I wish I were thought solving DEs like this

  • @pacificll8762
    @pacificll8762 2 роки тому +1

    You make such great videos !

  • @symbolspangaea
    @symbolspangaea 2 роки тому +1

    Amazing video!! Thank you so much!

  • @wyboo2019
    @wyboo2019 9 місяців тому

    i used something similar to this to derive the binet formula when i was just trying new things without concern for rigor
    usually you derive the binet formula using a generating function, but I actually imagined the (naturally-indexed) fibonacci numbers as the components of a vector in an infinite-dimensional vector space (ie f = 1e1+1e2+2e3+3e4+5e5+8e6+...) and then, i kind-of defined into existence a linear transformation that brought every basis vector to the next-indexed one, ie. s(e_i)=e_(i+1), pretended i had an inverse for this even though obviously one doesn't exist for e1, and it led to a polynomial in s applying to the fibonacci vector equaling the RHS, so the next problem was to find the inverse of this polynomial in s
    i got stuck there, until i realized i could factor the polynomial in s into two monomials and then just apply the inverse to each monomial separately, eventually bringing me to the Binet Formula as well as some very cool identities involving power series of the golden ratio i was unaware of
    its a very fun thing to work through i highly encourage, because ive never seen anyone else fiddle with a "generating vector"
    but essentially my approach seems to just be 'operational calculus' but translated to the language of linear algebrs

  • @minimath5882
    @minimath5882 2 роки тому +1

    Amazing

  • @jaafars.mahdawi6911
    @jaafars.mahdawi6911 Рік тому

    0:53 i think this one's gonna be fun..
    Me (all along): it definitely is.

  • @yash1152
    @yash1152 Рік тому

    5:47 > _"it's about time we introduce a new linear operator: the unit shift"_
    i guess that's where my existing knowledge with operator calculus ends in this video.
    (except that some knowledge that i have is not covered here so far, maybe further in video)
    8:57 > _"where right side ain't just zero"_
    yeah, i guess this will cover the remaining part of my knowledge
    *Edit:* no! the aim/answer is same, but the method here is doing it from scratch

  • @michaelriberdy475
    @michaelriberdy475 2 роки тому +1

    Wonderful

  • @PavanKumar-xv1hg
    @PavanKumar-xv1hg 2 роки тому +1

    wait how did the last part of solving the differential equation come like the so called complementary function ? at 10:53

    • @Supware
      @Supware  2 роки тому +1

      y = (1-D)^-1(0) ⇔ (1-D)y = 0 ⇔ y = Dy

    • @PavanKumar-xv1hg
      @PavanKumar-xv1hg 2 роки тому

      @@Supware ok thanks that cleared things up for me !

  • @user-xv6cg1vf3w
    @user-xv6cg1vf3w 2 роки тому +1

    Wow, imagine defining a partial derivative operator that way. Also there is no need to define special notation for Fourier and Laplace transform because we have the D inverse operator. F f = D^-1 f * exp, L f = D^-1 f * exp(iω) or F f = I f*exp, L f = I f * exp(iω)

  • @bentationfunkiloglio
    @bentationfunkiloglio 2 роки тому +1

    Mind blown

  • @malicksoumare370
    @malicksoumare370 2 роки тому +1

    This video is very very coooolllll.....

  • @bennyloodts5497
    @bennyloodts5497 Рік тому +1

    REALLY COOL STUFF!
    Quality in form and content: some world-class video. My compliments and looking forward to the next video 🙂

  • @accountname1047
    @accountname1047 2 роки тому +1

    Nice video

  • @michaelriberdy475
    @michaelriberdy475 Рік тому

    We need more supware

  • @Mikey-mike
    @Mikey-mike Рік тому

    Good lecture video.
    I've just found your channel and have subscribed.

  • @citycrafter578
    @citycrafter578 2 роки тому

    man, absolutely amazing

  • @ianweckhorst3200
    @ianweckhorst3200 8 місяців тому

    Oooh more stuff from umbral calculus

  • @tuckerhart510
    @tuckerhart510 2 роки тому

    I need more, function iteration pls

  • @engelsteinberg593
    @engelsteinberg593 2 роки тому +1

    Recomended lecture?

  • @jens6076
    @jens6076 2 роки тому

    Amazing! Thank you.

  • @jkid1134
    @jkid1134 2 роки тому

    Very hard to articulate how good this video is

  • @rajinfootonchuriquen
    @rajinfootonchuriquen Рік тому

    Thanks you so much :)

  • @plucas2003
    @plucas2003 3 місяці тому +1

    omg where are the rest of the series??

    • @Supware
      @Supware  3 місяці тому +2

      I'll make more when I have enough ideas 😅 it's a little frustrating but I really don't wanna make a third video that doesn't match the quality of the first two

  • @starkissed5795
    @starkissed5795 2 роки тому +1

    The goat 🐐

  • @Wielorybkek
    @Wielorybkek 2 роки тому +1

    operators are so cool :o

  • @yash1152
    @yash1152 Рік тому

    0:17 ha, no I - cards for me, no links in description either :)

  • @wargreymon2024
    @wargreymon2024 Рік тому

    It's informational and inspirational, even better than 3B1B

    • @Supware
      @Supware  Рік тому

      The highest of compliments, thank you!

  • @vnever9078
    @vnever9078 2 роки тому +1

    THIS IS HOW YOU MAKE A MATH VIDEO.......

  • @Applied_Theory
    @Applied_Theory 2 роки тому

    Great stuff, thanks

  • @MessedUpSystem
    @MessedUpSystem Рік тому

    I LOST IT WHEN HE DIVIDED BY 1-D AND EXPANDED AS A GEOMETRIC SERIES HAHAHAHA

  • @mehulborad2400
    @mehulborad2400 2 роки тому +1

    INSANE

  • @PeterBarnes2
    @PeterBarnes2 2 роки тому

    Replaced by Laplace transforms!? This theory has the capacity of including the Laplace transform! It's the same as that (D+s)^-1 operator you showed, but written in the form of a definite integral of a dummy variable, rather than as taylor series!

  • @GeoffryGifari
    @GeoffryGifari 2 роки тому +1

    i read about functionals, which map functions to a number. is it right to say that operators and transforms map functions to other functions?

  • @tobiaspeelen4395
    @tobiaspeelen4395 Рік тому

    When you derived a formula for the Fibonacci numbers, I immediately recognised Binet’s formula, who was the one to discover it after Euler. Now I can’t stop thinking if they also used this way of deriving the formula, or if they used different tools. If somebody knows, can they please tell me?

    • @Supware
      @Supware  Рік тому

      Interesting question! I don't know, but this is a pretty natural way to come up with the formula and Binet was active around the time this stuff was a thing

  • @mastershooter64
    @mastershooter64 2 роки тому +1

    This must be related to functional analysis and operator algebras

  • @danieldias3192
    @danieldias3192 2 роки тому +1

    I don't understand how the complementary function added at the end of the geometric series expansion solution works. How does (1 - D)^-1 * 0 equal ce^x? Where can I find more info on this?

    • @Supware
      @Supware  2 роки тому +2

      y = (1-D)^-1(0) ⇔ (1-D)y = 0 ⇔ y = Dy
      I'm afraid I haven't found any info for this kinda thing yet; I'll post about resources both in the comments and on the Discord server as I come across them :)

  • @mathacademy-jeeimocuet6566
    @mathacademy-jeeimocuet6566 7 місяців тому

    Excellent Excellent Excellent👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏👏

  • @TylerPerlman
    @TylerPerlman 2 роки тому

    Reminds me of the use of annihilators to solve inhomogeneous linear ODEs

    • @Supware
      @Supware  Рік тому +1

      Sounds like I have more googling to do...