first innings average is 50. so a+b+c+d/4=50 and a+b+c+d=200. also, after 5th innings avg becomes 62. so a+b+c+d+e/5=62. since we already have a value for a+b+c+d we can sub it here and hence, e=110. now they've given he scored more runs in 6th innings and hence he scored 120 runs in 6th innings (that is f = 120). after that, his last 5 innings becomes 80. so, b+c+d+e+f/5=80. take the first equation(a+b+c+d/4=50). we can get the value of b+c+d from here and we get b+c+d=200-a.sub it in b+c+d+e+f/5=80. we have values for e and f. substituing all the values, we get a=30
interesting questions
Good 👍🏻
Sir in first question what about none ( the politician's who favour none)
Sir shouldn’t it be d + e + f + 10 = 22?
first innings average is 50. so a+b+c+d/4=50 and a+b+c+d=200. also, after 5th innings avg becomes 62. so a+b+c+d+e/5=62. since we already have a value for a+b+c+d we can sub it here and hence, e=110. now they've given he scored more runs in 6th innings and hence he scored 120 runs in 6th innings (that is f = 120). after that, his last 5 innings becomes 80. so, b+c+d+e+f/5=80. take the first equation(a+b+c+d/4=50). we can get the value of b+c+d from here and we get b+c+d=200-a.sub it in b+c+d+e+f/5=80. we have values for e and f. substituing all the values, we get a=30
In 1st question, isn't it 50% of 78%?
In 1st question, isn't it 50% of 78%?