The capacitor can only flow a small amount of charge (current x time) before its voltage is charged up to equal to the magneto voltage. No current flows once the two sides are equal voltage (equipotential). This causes current to stop flowing, which means current flow in the primary transitions from high current to low current. A change in current and hence change in magnetic flux through the primary induces (via magnetic induction) a voltage in the secondary. Because the secondary is wound around the same magnetic core as the primary but with many more turns, a much higher voltage develops in the secondary, enough to create a spark when dielectric breakdown occurs across the spark plug.
Also please understand how current works, the secondary coil DOES NOT INDUCE A HIGH CURRENT instead in induces a HIGH VOLTAGE CURRENT, most times this current will be low, as energy is conserved P = V*I when we increase V , I must decrease respectively for a fixed Power P
Pease review this video again, the working of capacitor and contact breaker is ambiguous, 1) what is the point of the capacitor in this circuit ? 2) When the magnetic poles change won't that change the direction of current ? Please explain this clearly !
The capacitor is charged when the contact points are open and then instantaneously discharges which causes the change of flux in the secondary coil to double, this induces even more high voltage compared to no capacitor. Capacitor also prevents arcing across the points.
OMG. THANK YOU! I've watched and tried to understand the magneto system many times. This was VERY CLEAR AND HELPFUL! Thank you!
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Thank you! This video was really helpful and very well presented.
Wow! That was amazing explanation, without wasting any time 👌🏻👍🏻
Thankyou very much sir love from india 🇮🇳
Why does magnetic field change around coil when current starts flowing through capacitor
Since capacitor store charge so ,ore current flow to primary coil
The capacitor can only flow a small amount of charge (current x time) before its voltage is charged up to equal to the magneto voltage. No current flows once the two sides are equal voltage (equipotential). This causes current to stop flowing, which means current flow in the primary transitions from high current to low current. A change in current and hence change in magnetic flux through the primary induces (via magnetic induction) a voltage in the secondary. Because the secondary is wound around the same magnetic core as the primary but with many more turns, a much higher voltage develops in the secondary, enough to create a spark when dielectric breakdown occurs across the spark plug.
Absolutely very valuable information video
Informative
Thank you
Amazing !
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Super explaination brother 🎉🎉❤
Dear Vinayprakash, we hope you have an amazing experience & learn lots of exciting stuff! :)
Nice explanation sir....it is very helpful to understand this concept
🙌
Thank You 💙 sir
Thank you so much
I subscribed immediately
Thanks a lot sir
nice video my favourite
We hope you have an amazing experience & learn lots of exciting stuff! :)
Also please understand how current works, the secondary coil DOES NOT INDUCE A HIGH CURRENT instead in induces a HIGH VOLTAGE CURRENT, most times this current will be low, as energy is conserved P = V*I when we increase V , I must decrease respectively for a fixed Power P
Pease review this video again, the working of capacitor and contact breaker is ambiguous, 1) what is the point of the capacitor in this circuit ? 2) When the magnetic poles change won't that change the direction of current ? Please explain this clearly !
The capacitor is charged when the contact points are open and then instantaneously discharges which causes the change of flux in the secondary coil to double, this induces even more high voltage compared to no capacitor. Capacitor also prevents arcing across the points.
🤪🤪🤪
who rotate that magnet because engine is not cranked yet
That's what I am thinking 🤔