GCSE Chemistry Revision "Limiting reactant"

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  • Опубліковано 18 лют 2017
  • GCSE workbooks www.amazon.co.uk/Dr-Shaun-Don...
    School licenses from 40p per copy www.freesciencelessons.co.uk/...
    In this video, we explore the idea of a limiting reactant. We use this idea to work out the mass of the product that we can make in a chemical reaction, even if we are not told which reactant is in excess.
    This video is based on the AQA spec. If you are following a different exam board then you should check your specification. The Amazon link above is an affiliate link. This provides a small commission which helps to support freesciencelessons. The cost remains the same to you. If you prefer not to use this, you can search Amazon for the Freesciencelessons workbooks.

КОМЕНТАРІ • 283

  • @dariadorociak751
    @dariadorociak751 6 років тому +593

    Sir you are a literal angel for this world, I am doing my gcses next week and you are truly saving me I improved so much after watching your videos, thank you so much for spending your time on doing these videos and trying to help us, you make a huge difference for this world, thank you again

    • @no-vn6tk
      @no-vn6tk 5 років тому +4

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    • @ShreyBrawlStars
      @ShreyBrawlStars 3 роки тому +12

      How was your gcse?

    • @ghaffz6744
      @ghaffz6744 Рік тому +3

      @@ShreyBrawlStars how was yours?

    • @AmanTheMan
      @AmanTheMan 3 місяці тому

      ​@@ghaffz6744how's yours?

  • @AB-fr1sx
    @AB-fr1sx 5 років тому +864

    Its 2:04am right now and im watching this video 😂 got my GCSE tomorrow wish me luckkk 🤲🏽😭

  • @rhyswynne5914
    @rhyswynne5914 2 роки тому +153

    watching these less than 24 hours before my chem paper 1 exam ;)

  • @mub1012
    @mub1012 7 років тому +354

    ur channel is really helpful, even my teacher can't explain like this.

    • @Freesciencelessons
      @Freesciencelessons  7 років тому +218

      No problem and thanks for the comment. If you could, it would be great if you would recommend my channel to your friends.

    • @unaestrella1876
      @unaestrella1876 4 роки тому +63

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    • @omamashaheer2815
      @omamashaheer2815 3 роки тому +13

      @@unaestrella1876 bruh

  • @simpleclover8422
    @simpleclover8422 5 років тому +196

    Saving everyone's GCSEs one video at a time!

  • @iyaan7648
    @iyaan7648 5 років тому +86

    Yo this brief explanation . I am dying of how good this is .can't understand shit my teacher explains

  • @xandercromarty3652
    @xandercromarty3652 5 років тому +86

    Mate you have rescued my chemistry and I can't thank you enough
    Come to our after prom, I have a feeling ur a sesh king

    • @qt_s
      @qt_s 3 роки тому +7

      how did the prom go

  • @yashaswar1973
    @yashaswar1973 4 роки тому +34

    Honestly, I can't thank you enough
    You are so helpful and the difference you make to us is phenomenal

  • @alishan6265
    @alishan6265 5 років тому +33

    You'll be always in my prayers
    Thankyou🙂

    • @Freesciencelessons
      @Freesciencelessons  5 років тому +34

      Thank you, I really appreciate that. I hope that you get the grades that you want in your exams.

    • @alishan6265
      @alishan6265 5 років тому +11

      Ahhhhhh that's the best thing on internet today🙏❤❤Thankyousomuch❤

  • @wg8375
    @wg8375 3 роки тому +7

    This guy is so helpful, i just wanna buy thousands of his revision guides and give them out

  • @masterkiller4353
    @masterkiller4353 5 років тому +12

    I am nearly completed all my notes on your videos. These videos are just the best and I think I will get atleast a 7 in all sciences because of you. Thanks.

  • @tobybower9235
    @tobybower9235 5 років тому +3

    All of these calculation videos that you’ve done were an absolute life saver on the chem igcse ty v much

  • @LilSixy
    @LilSixy 6 років тому +49

    Thank you. You made it even more simple than the CGP revision guide

    • @marcobaby9975
      @marcobaby9975 5 років тому +4

      Albert bob that’s literally what I was about to say

    • @zaraeaton3378
      @zaraeaton3378 2 роки тому +3

      I was just about to say that too

    • @OJrB100
      @OJrB100 2 роки тому +1

      I was about to say that tooo

  • @amalshafernando7993
    @amalshafernando7993 5 років тому +4

    i had never learnt this before, but i got it in just one video! thanks a million

  • @its.sophee4817
    @its.sophee4817 4 роки тому +7

    i’m in top set science and when we learnt this in class i was so confused but after this i got it straight away a total life saver

  • @gx7167
    @gx7167 4 роки тому

    You explain in 5 mins what my teacher fails to explain in 1 hour
    Absolute god send

  • @RabisaFaisal
    @RabisaFaisal 3 місяці тому +5

    It's 5:42 am right now and I have to give the exam today at 8am 😅😅

  • @jamiebyrne3119
    @jamiebyrne3119 2 роки тому +2

    Sean you saved my bloody GCSEs

  • @Chinxagain
    @Chinxagain 5 років тому +12

    My chemistry exam is at 9am today and it’s 7:06 right now and you’re so helpfullll

  • @f3r178
    @f3r178 5 років тому +4

    Thank you so much, my teacher just confused me with all these equations but you made it so easy!

  • @aminakaii3683
    @aminakaii3683 6 років тому +5

    Give this man a Nobel.

  • @kevob5592
    @kevob5592 6 років тому +4

    Cheers, this has really helped me understand this topic.

  • @Fatimaurl
    @Fatimaurl 4 роки тому +1

    Thanks a lot for explaining so great, your videos helped a lot for my tests and exams

  • @ledge1474
    @ledge1474 7 років тому +14

    We are just about to do this after Half Term ^_^ Thanks :D

  • @johnson2465
    @johnson2465 3 роки тому +1

    Very nice.Easily understood.Lots of love from India 🇮🇳

  • @jakejillian7026
    @jakejillian7026 Рік тому

    Literally the best guy to watch! 🤩

  • @kishanpopat6313
    @kishanpopat6313 5 років тому +6

    legend. absolute legend

  • @rikhil_8818
    @rikhil_8818 6 років тому +35

    So are limiting reactants just the one with the smallest mole value, then that mole value carries on to the product?

  • @Warrior7426
    @Warrior7426 Рік тому

    Exam tomo morning and im binge watching this guys vids

  • @makro477
    @makro477 2 роки тому +1

    U are the reason of my A i got for my IGCSE exam

  • @Ann-dd2kl
    @Ann-dd2kl 4 роки тому +16

    I’m doing my year 11 chemistry mock tomorrow and you’ve literally been so helpful, Thankyou!

    • @mlak5935
      @mlak5935 4 роки тому +3

      good luck u got this

    • @Freesciencelessons
      @Freesciencelessons  4 роки тому +11

      No problem. I hope that your mock went well.

    • @Ann-dd2kl
      @Ann-dd2kl 4 роки тому +1

      mlak ty

    • @Ann-dd2kl
      @Ann-dd2kl 4 роки тому +1

      Freesciencelessons ty

    • @samwell2386
      @samwell2386 4 роки тому +3

      @@Ann-dd2kl I have mine tommorow lol

  • @sp1cy596
    @sp1cy596 2 роки тому

    you are just the best to ever exist

  • @xannie4508
    @xannie4508 4 роки тому

    ommggg tysm for this, it was extremely helpful

  • @gamingwithemerald2969
    @gamingwithemerald2969 6 місяців тому

    Got my chemistry mock tomorrow. Wish me luck!

  • @aldanaalkhalaf3345
    @aldanaalkhalaf3345 5 років тому

    this is very helpful thank you!

  • @KEN-nh5zc
    @KEN-nh5zc 2 роки тому +5

    Just binged watched this , i'm doing a test to enter higher and damn this is hard but you make it so simple !! thank you for your efforts :D

  • @oscarpeters5309
    @oscarpeters5309 2 роки тому +1

    its nearly midnight, we've got this

  • @sarahrutter4084
    @sarahrutter4084 6 років тому +2

    You're a saviour.

  • @jabirhasan01
    @jabirhasan01 3 роки тому

    It was helpful, sir. Nice presentation.

  • @mowfulasajahan2188
    @mowfulasajahan2188 4 роки тому +1

    Thnqq soo much sir for you great clear and easiest explanation about limiting reactant.
    Actually I was trouble in this chapter but now hopefully I can do all the ques by my self.
    Thnq soo much Sir!!
    Hats off you sir!!!

  • @TomiWebPro
    @TomiWebPro Рік тому

    Thanks, saves me time going to my teacher and further confusing me!

  • @leo9982
    @leo9982 Рік тому +5

    Watching this right before my Chem paper 1 ask me in a couple of months and I’ll tell you how it went (unlike everyone else)

  • @sumii7480
    @sumii7480 2 роки тому +3

    the smile at the end got me wheezing

  • @GFMkidsComedy
    @GFMkidsComedy 5 років тому +1

    Really helpful!

  • @cloudiii9543
    @cloudiii9543 6 років тому +2

    Thank You!

  • @labskan5334
    @labskan5334 Рік тому

    thank you for saving my life

  • @user-fh6lx1fb2g
    @user-fh6lx1fb2g 2 роки тому

    It’s the morning of my gcse exam for Chen, wish me luck:)

  • @aidenkk2395
    @aidenkk2395 27 днів тому

    In 1 hour I have my chemistry exam and I am watching video right now😇

  • @emmadavidson3605
    @emmadavidson3605 5 років тому +1

    thank you so much! really helpful x

  • @el1889.
    @el1889. 5 років тому +16

    its actually easy wtf, my guy

  • @samirabegum5608
    @samirabegum5608 5 років тому

    Thank you! 🙏🏼

  • @abdullahbinmasood3956
    @abdullahbinmasood3956 6 років тому +1

    Thank you very much sir😀😀😀😀

  • @walaejemjama3930
    @walaejemjama3930 Рік тому

    you just saved my IGCSE student life

  • @YoItzTina
    @YoItzTina 27 днів тому +1

    3 hours before my exam starts.. Gl to everyone

  • @rubusidaeus8913
    @rubusidaeus8913 6 років тому +4

    Ahh that smile :) I love it xx

  • @elishahaali8714
    @elishahaali8714 6 років тому +12

    Hi, where can I find the workbook?
    Thanks

  • @duffguy2259
    @duffguy2259 5 років тому

    Absolutely legendary

  • @8tthat
    @8tthat 27 днів тому

    11 min before the exam 😍‼️

  • @Chiratalg
    @Chiratalg 7 років тому +41

    Hey can you upload faster......or are you trying your hardest but this is the fastest rate you can go at? The only reason i am asking is because you are the ONLY reliable science channel in the hole of youtube, and you are the one that helps me before exams or just during general revision.
    One more thing, you have a lot of videos but still havent began uploADING stuff that we are doing.
    Thanks

  • @JoshTDaly
    @JoshTDaly 5 років тому

    Very good!!!

  • @misan2002
    @misan2002 5 років тому

    please sir can u answer this question
    how do i know what has been fully used up?

  • @luq44
    @luq44 5 років тому

    what an absolute madlad

  • @heather-sj2pi
    @heather-sj2pi 3 роки тому

    so the number of moles of the limiting reactant = the number of moles of the product, and you can find the mass of the product by taking said amount of moles and doing moles=mass/Mr?

  • @electrafyin
    @electrafyin 6 років тому

    best teacher evaaaaaa

  • @pylewastaken
    @pylewastaken 3 роки тому

    THANK YOU SO MUCH

  • @theterminator7113
    @theterminator7113 4 роки тому +1

    I’m doing the the ocr exam board so is this the same as ocr

  • @ronakkumar0754
    @ronakkumar0754 3 роки тому

    I actually love you

  • @nickycrisp2176
    @nickycrisp2176 5 років тому

    You are my inspiration

    • @f3r178
      @f3r178 5 років тому

      Nicky Crisp ok

  • @graceblainey2936
    @graceblainey2936 5 років тому +6

    I hate that I'm doing this now. The gcse is tomorrow n I'm still treating this like a mock

  • @user-nv8bu9si7e
    @user-nv8bu9si7e 5 років тому +1

    THank you mate very litty

  • @jasvirmehrok4190
    @jasvirmehrok4190 4 роки тому

    Thank you, your videos are so helpful!! I came across this question to work out the mass of the product however instead of moles, it uses the mass of the reactants: Calculate the mass of aluminium oxide formed when 135g of aluminium is burned in air. How do I work this out?

    • @ed-gl3pr
      @ed-gl3pr 2 роки тому +2

      This is two years late but you'd have to work out mass = moles × Mr

  • @marthaemily6581
    @marthaemily6581 5 років тому

    Is the reactant with less moles always the limiting reactant?

  • @gretab5002
    @gretab5002 5 років тому

    How does 0.5 moles of Mg react with 1 mole of Cl2 to give 1 mole of the product?

  • @saidibrahim4084
    @saidibrahim4084 6 років тому +1

    thanks

  • @nicolevarghese6068
    @nicolevarghese6068 6 років тому +6

    where is the link to his revision workbook?

  • @wahhaj1872
    @wahhaj1872 3 роки тому +2

    would we get the chemical equation for the reaction in the question in the exam or are we supposed to work it out

  • @ajgmz
    @ajgmz Рік тому +2

    3:57 How did you find out the Relative formula mass. Please help. Thanks

    • @Freesciencelessons
      @Freesciencelessons  Рік тому +5

      Add together all of the relative atomic masses of the atoms present in the compound.

    • @ajgmz
      @ajgmz Рік тому +2

      @@Freesciencelessons Thank you so much!😇

  • @myoiri
    @myoiri 2 роки тому

    thx so much

  • @Hale-eb5gp
    @Hale-eb5gp 2 роки тому +3

    4:28 wasnt it Mass= mr x mole? but you put mass = mole x Ar so im kinda confused on this :(

    • @Hale-eb5gp
      @Hale-eb5gp 2 роки тому +1

      OH i think i kinda get it now lmao its currently 1am so my brains working slower

  • @simonday1040
    @simonday1040 6 місяців тому

    how do u find relative formula mass

  • @jaimoljohn4319
    @jaimoljohn4319 5 років тому +1

    what if the limiting reactant was just magnesium and the mass wanted to find was copper would it still be affected?

    • @deepankumarsakthivel2466
      @deepankumarsakthivel2466 5 років тому

      it would because if magnesium was the limiting reactant, not all of the copper sulfate would react, hence the mass of copper produced would be smaller

  • @ollieholloman3227
    @ollieholloman3227 4 роки тому

    why did you give the mass when the question said how many moles?

  • @AA-px3sw
    @AA-px3sw 3 роки тому +4

    Hi urgent question: is this the same as reagents in excess?
    Thanks hope to hear from you :D

    • @Freesciencelessons
      @Freesciencelessons  3 роки тому +1

      The limiting reagent is the one that is not in excess.

    • @AA-px3sw
      @AA-px3sw 3 роки тому +1

      Freesciencelessons ok thank you!

  • @PIXELGamerzXvlogs
    @PIXELGamerzXvlogs 4 роки тому +1

    My schools shit thanks man your a legend

  • @pcboris3085
    @pcboris3085 6 років тому +1

    Im doing combined science higher , does this still apply to me????

    • @roseways
      @roseways 6 років тому

      Not Lacazette ye it does

  • @sakibkhan5383
    @sakibkhan5383 5 років тому +2

    So the amount of moles that is smaller is the limiting reactant?

  • @angelasanyu650
    @angelasanyu650 6 років тому +1

    so is the number of moles for the product always the same as the number of moles for the limiting reactant?

    • @sumayyahassan4989
      @sumayyahassan4989 3 місяці тому

      i was wondering that too, do you know the answer?

  • @euphoria1942
    @euphoria1942 6 років тому +7

    So is the limiting factor mole is equal to the product of mass we are trying to find out?

    • @hobituitary1233
      @hobituitary1233 6 років тому +1

      Bella and BTS oh hello army

    • @syubiased6854
      @syubiased6854 6 років тому +1

      Hoseoks water bottle oh hello again

    • @hannah-ho9yd
      @hannah-ho9yd 5 років тому

      @@hobituitary1233 i saw u on his other videos!

  • @izzyrose8377
    @izzyrose8377 3 роки тому

    thank you so muchhhhhh

    • @qt_s
      @qt_s 3 роки тому

      you’re welcome

  • @Angela-zt1mt
    @Angela-zt1mt 17 днів тому

    wait can someone help me cuz at 3.33 why is it that the moles of sodium chloride are 0.25?
    cuz i did that sodium hydroxide was 1 so after the reaction the excess wld be 0.75 and thats how much sodium chloride would be. i dont know im sorry

    • @Freesciencelessons
      @Freesciencelessons  17 днів тому +2

      The hydrochloric acid is the limiting reactant and there are 0.25 moles of that. That means that 0.25 moles of sodium hydroxide will react with it (they react in a 1:1 molar ratio). 0.25 moles of hydrochloric acid will produce 0.25 moles of sodium chloride.

  • @Conmacsworld
    @Conmacsworld 6 років тому

    Isn’t this just the same formula to answer the question as reacting masses 1&2 i don’t see the difference

  • @psyarti
    @psyarti 27 днів тому

    i’ve got my exam in an hour (it’s currently 8am..) and this is my resort to pass 💀💀

  • @APSEAPSE
    @APSEAPSE 5 років тому +2

    I love you!!!haha

  • @SR-oe4xg
    @SR-oe4xg 5 років тому

    hi sir are u doing a levels

  • @eyup8943
    @eyup8943 Рік тому

    What do you do when theirs a number at the front of the symbol like 2na?

    • @leo9982
      @leo9982 Рік тому

      Then it’s 2 moles to whatever many moles the other one has

  • @3aloosh623
    @3aloosh623 Рік тому

    I love you :)

  • @abdussattar4716
    @abdussattar4716 3 роки тому

    I live in Bangladesh and i don't know how to get his revision book. Is this available on net or do i need to buy it?

    • @wg8375
      @wg8375 3 роки тому

      I checked now, and you can get it on amazon to be delivered to Bangladesh, however the shipping is quite expensive :)

  • @LunaLov3good
    @LunaLov3good 4 роки тому

    Is there a difference between limiting reactants and limiting reagents ?

    • @qt_s
      @qt_s 3 роки тому

      pretty much the same, but the reactant is more specifically the substance consumed in the chemical reaction.

  • @harsonpakeer7499
    @harsonpakeer7499 2 роки тому

    in the test will they say in the question which one is the limiting reagant?thanks!

    • @Freesciencelessons
      @Freesciencelessons  2 роки тому +1

      If they only give a mass for one reactant, you can assume that this is limiting. However, if they give the mass for more than one reactant, you will need to work out which one is limiting from the number of moles.

    • @harsonpakeer7499
      @harsonpakeer7499 2 роки тому

      @@Freesciencelessons thank you but how would you find out which is one limiting if they dont tell you?. thanks

  • @arsenal1456
    @arsenal1456 5 років тому +6

    2019?