👉 Practice Sheet - Go to Batch - Subject Section - Open DPP PDF Section. 📕 SPRINT Class-9th - physicswallah.onelink.me/ZAZB/0y4x6bma 📕 Telegram For Quizzes :- t.me/foundationwallah
@@HarshMadheshiya hey I am not getting the practice sheets can you tell how to get the practice sheets because when I opened its showing to pay for that.
00:02 Understanding motion and average velocity 02:41 Get the support you need to excel in the exam 07:26 Motion is defined as the continuous change in position of an object. 09:54 Understanding motion and rest in relation to surroundings 14:58 Motion is a relative term dependent on the observer 17:20 Understanding the concept of motion 21:47 Difference between uniform and non-uniform motion 24:04 Acceleration in uniform versus non-uniform motion 28:33 Covering equal distance in equal time intervals 30:52 Physical quantities can be measured but love, color, and sadness cannot. 36:24 Distance and displacement in physics 38:39 Understanding the concept of shortest distance and displacement 43:31 Calculating total distance and displacement 45:52 Displacement can be zero even if distance is covered 50:38 Unit of speed in CGS is meter per second 53:12 Calculating distance and average speed in physics experiments 57:45 Acceleration is the rate of change of velocity. 1:00:30 Acceleration can be positive or negative based on velocity changes 1:05:09 Finding the acceleration of a bus given initial and final velocities and time 1:07:43 Understanding uniform and non-uniform acceleration 1:12:07 Understanding uniform and non-uniform acceleration 1:14:20 Understanding origin, positive and negative distances, independent and dependent variables 1:19:22 Understanding scaling and graph plotting concepts 1:21:42 Understanding the slope of a distance-time graph helps determine uniform motion. 1:26:38 Understanding constant velocity and distance calculation. 1:29:15 Understanding velocity-time graph in motion 1:33:48 Understanding the three equations of motion and their variables 1:36:23 Understanding velocity and acceleration equations 1:41:30 Understanding Accelerated Motion and Uniform Circular Motion 1:43:54 Convert R to kilometers & seconds to meters, Calculate average speed 1:48:33 Importance of hard work in telling stories
1:08:22 Hw 1 -: Given - U = 0 V= 40 km/h Therefore by converting it we get v = 11.11 m/s And t= 600 (s) Now acceleration = V-U/ t By substituting the values =11.11-0/600 Which gives a= 0.0185 m/s^2 I hope I am correct
FOURTH LAW OF MOTION:- Every book remains at the state of rest until and unless any external or internal exams appear, and then the speed of turning pages will be directly proportional to the amount of syllabus to be completed in time and the tension in mind remains constant...
44:00 1 - B 16 2-A 0 3- (B) magnitude & direction 4 - (B) Distance is greater than displacement 5 - Vector 6 - Yes , a object can have zero displacement if it comes back to its initial position
SUMMARY _____________ The video covers the concept of motion, including distance, displacement, speed, velocity, uniform and non-uniform motion, and acceleration. It explains the difference between distance and displacement, and how to calculate average speed and velocity. The video also discusses uniform circular motion and the equations of motion. Key moments: 00:00 Understanding the concept of motion and how objects change their position with time is crucial. Consistent effort and focus are essential to excel in exams and achieve good results. -Importance of consistent effort and focus in achieving success in exams and understanding motion concepts. -Reflecting on past efforts and preparing diligently for upcoming exams to improve results and progress to the next class. -Exploring the concept of motion, displacement, speed, and velocity in physics to enhance understanding and excel in exams. 08:08 Understanding the concept of motion and rest in relation to observation is crucial. Objects in motion or at rest depend on the observer's perspective, defining absolute and relative terms. -Exploring the concept of motion and rest in relation to observation and perspective. -Discussing the examples of Statue of Unity and Statue of Liberty to illustrate the concept of motion and rest. 16:14 Uniform motion refers to an object covering equal distances in equal intervals of time, maintaining a constant speed, while non-uniform motion involves covering unequal distances in equal intervals of time with changing speeds. -Definition of uniform and non-uniform motion. Uniform motion maintains constant speed, covering equal distances in equal time intervals. -Example of uniform motion with consistent speed. The concept of covering equal distances in equal time intervals explained. -Contrasting uniform and non-uniform motion. Non-uniform motion involves changing speeds, covering unequal distances in equal time intervals. 24:17 Understanding the concept of uniform and non-uniform motion is crucial in physics. Observing equal time intervals and distances covered by different objects helps differentiate between the two types of motion. -Explaining the significance of uniform and non-uniform motion in physics and the impact on acceleration. -Analyzing the motion of different objects over equal time intervals to determine uniform or non-uniform motion. -Discussing the concept of physical quantities and how they are measured, including examples like height, weight, and color. 32:21 Understanding the concept of distance and displacement is crucial in physics. Distance is the actual path covered, while displacement is the shortest distance between two points. -Differentiating between physical quantities like scalar and vector quantities is essential in physics education. -Explaining the concept of distance and displacement using a running athlete as an example. -Illustrating the difference between actual path length and displacement through a practical measurement example. 40:28 Understanding displacement in physics is crucial. It is the shortest distance between the initial and final points of an object's motion, often resulting in zero displacement. -Explaining the concept of displacement and its significance in physics. -Differentiating between displacement and distance covered by an object in motion. -Discussing scenarios where an object's displacement can be zero based on its starting and ending points. 48:34 Understanding speed, velocity, and their relation to distance and time is crucial in physics. Speed is distance divided by time, while velocity is speed in a specific direction. -Difference between speed and velocity, and their basic definitions. -Conversion of speed and velocity units from meters per second to kilometers per hour. -Calculation of average speed using total distance and total time taken. 56:40 Acceleration can be positive, negative, or zero based on changes in velocity. Positive acceleration means increasing speed, negative means decreasing speed, and zero means constant speed. -Understanding positive, negative, and zero acceleration based on changes in velocity. Positive acceleration indicates increasing speed, negative acceleration indicates decreasing speed, and zero acceleration indicates constant speed. -Explaining acceleration in the context of objects in motion. Positive acceleration occurs when speed increases, negative acceleration when speed decreases, and zero acceleration when speed remains constant. -Defining distance traveled by a body in a given direction in a unit of time. Speed is calculated as distance upon time, representing the distance covered in one second. 1:08:38 Understanding uniform and non-uniform acceleration is crucial in physics. Objects experiencing uniform acceleration change velocity at equal intervals of time, while non-uniform acceleration results in velocity changes at unequal intervals. -Uniform acceleration involves consistent velocity changes over equal time intervals, crucial in physics concepts and calculations. -Non-uniform acceleration leads to varying velocity changes over unequal time intervals, impacting object motion and physics principles. 1:12:50 Objects moving with non-uniform acceleration experience unequal changes in velocity over equal intervals of time, leading to non-uniform motion. Graph plotting plays a crucial role in understanding motion and scaling is essential to represent distances accurately. -Non-uniform acceleration causes unequal changes in velocity over equal time intervals, impacting motion characteristics. -Graph plotting is vital for comprehending motion dynamics and analyzing velocity changes. -Scaling in graph plotting ensures accurate representation of distances and prevents distortion in data interpretation. 1:21:05 Understanding slope in distance-time graphs is crucial. It helps determine speed, uniform motion, and non-uniform motion in objects' velocity-time graphs. -Slope calculation aids in finding speed and uniform motion in distance-time graphs. -Velocity-time graphs reveal uniform and non-uniform motion based on constant velocity or changing speed. -Analyzing the area under velocity-time graphs helps determine distance covered by objects during motion. 1:29:25 Understanding the relationship between velocity, time, acceleration, and displacement is crucial in physics equations. By analyzing graphs and equations, one can calculate key parameters accurately. -Interpreting velocity-time graphs helps determine acceleration and displacement. The slope of the graph indicates acceleration and provides valuable information in physics calculations. -Equations of motion involve variables like initial velocity, final velocity, acceleration, time, and displacement. Solving these equations accurately is essential for physics problem-solving. -Practical application scenarios like calculating acceleration and displacement for moving objects from rest are demonstrated. Understanding the given parameters is key to solving physics problems effectively. 1:37:28 Understanding uniform circular motion and accelerated motion concepts is crucial in physics. The direction of motion changes in accelerated motion, while speed remains constant in uniform circular motion. -Difference between uniform circular motion and accelerated motion. Understanding how direction changes in accelerated motion and speed remains constant in uniform circular motion. -Calculating average speed in physics. Explaining how to calculate average speed using distance and time measurements. -Solving a physics problem involving jogging. Analyzing the time taken for a jogger to cover distances between points A, B, and C. 1:45:36 Understanding the concept of average speed and total distance covered in a given time is crucial for solving physics problems efficiently and accurately. -Calculation of total time, distance, and average speed helps in solving physics problems effectively. -Exploring displacement, initial and final points, and minimum distance between them enhances problem-solving skills in physics. -The importance of hard work, focus, and confidence in achieving success in academics and exams is emphasized. Generated BY sider.ai Thank me later :)
30:45 Amar's and Anthony's car speed are in *uniform motion* as they are covering equal distance in equal time interval. Whereas, Akbar's car speed is in *non-uniform motion* because the speed is changing.
H.W.1.---------------- U(initial velocity)=0 v(final velocity) = 100/9 m/s time duration = 10*60s = 600s Acceleration (a) = (v-u)/t a= (100/9) m/s/600 s = 0.0185 m/s² (approx). or Initial velocity of the train, u = 0 (since the train is initially at rest) Final velocity of the train, v = 40 km/h = 40*5/18 = 11.11 m/s Time taken, t = 10 min = 10 × 60 = 600 s Acceleration = a= v-u/t = 11.11 * o/600 = 0.0185 m/s2 Hence, the acceleration of the train is 0.0185 m/s2. I HOPE THIS WILL HELP YOU, AND ALL THANKS TO THE TEACHER, 😁
1. Option B 2. Option C 3. Option A 4. Option B 5. Option A 6. Option B 7. Option B 8. Option A 9. Option C 10. Option C 11. Option A 12. Option A 13. Option C 14. -1.1 m/s2 15. 6 m/s 16. 96 m 17. 50 km/h and 13.8 m/s H.W 1. 26.6 m/s is the avg. speed of Abdul's trip
Newton's 4th laws says that every book continuous to be in rest until and unless internal and external exam appear and speed of page turning is directly proportional to the syllabus to be cover and tension in the mind remain constant
Newtons's Law of Ashiqui:- Every ashiqui continues to do ashiqui until an internal or external,i.e, by home or girl's family, 'flying chapal' is thrown upon his face by a 'lovely girl'. This external/internal 'flying chapal' is called 'Bezzati' which is directly proportional to 'Besharmi', however,'Bezzati remains constant. 😊😊
Guyss this lecture is so useful my physics teachers 😭teaches well but I don't understand what she says this lecture was literally so😳 helpful my exams will start from 15 😇July but I'm starting the syllabus from today (STUDY AS SOON AS POSSIBLE BECAUSE IT IS 9TH) ❤ (LIKE THIS SO EVERYONE CAN SEE THIS COMMENT AND BE MOTIVATED)
To find the acceleration of train, we can following the formula:- A = u - v /t Given:- U = 0 [ as the train start from rest ] V = 40 km/h T = 10 minutes = 10/60 hours = 1/6 hours Now, let's calculate the acceleration using the given values :- A = U - V/ T = 0 - 40 = 40 km/h = 40 km/h / (1/6) = 40* 6 km/h = 240 km/ h²
1:10:50 What Is The 1st Child Doing In The Bus 🚌?(Sus) Ans: The Child Is Doing Something Suspicious 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 Edit : Watch In 2X Speed :D
Bhaiyon or beheno 😅😅 Jis jis ke pa1 ya yun kaho unit 1 ke exam a rahe he vo thoko like button 👍👍or ha jis ne kuch nhi padha he or video exam se ek din pehle dekh raha he un logo ko mera solute👏👏
1--->>>> 16 m 2--->>>> 0 m 3--->>>> B) magnitude+ direction 4--->>>>B) distance> displacement 5--->>>>vector quantity *?*--->>>>Yes it can be 0 as if an object(x) has to reach the initial to final destination and it is the same (y) then , the displacement must be 0.
Que 1 =16m Que 2 =0 Que 3=magnitude and direction Que 4=distance > displacement Que 5=vector Que 6= yes if the object have same starting and ending point
'36:28' Sir, you said that," Distance is a Scaler Quantity", hearing which a doubt emerged in my mind that 'Distance is a Vector Quantity' but later '47:31' question 5, you said that " Distance is a Vector Quantity" please notice that.
Homework 1:- Initial velocity or u= 0 m/s Final velocity or v= 40×100÷3600m/s =11.1m/s Time taken or t= 10 minutes 10×60second = 600 seconds Accerleration or a= Final velocity(v) - Initial velocity(u) ÷ time taken(t) = 11.1 - 0 ÷ 600 =0.0185 m/s square
I can't imagine ki mujhe samaj aa gaya and yet i am wrak in math and physics agr 100% hua toh mujhe 80% toh aaa gya 🎉🎉🎉🎉🎉😊😊😊😊 thankyou soo much sir thank u physics wallah team you are best' 😊
This is the way of teaching.... school mein teacher chadi le ke ajata hai aur agar question pucho to class se bahar nikal dete hain yaha question puchne ki gunjaish hi nhi rehti aisa padhate hain ... thanks a lot pw for this Amazing faculty with a amazing teaching method 😊❤
Sir Har ek makke ke Dane ko same environment nahi mil raha hai qki Kuch Dane niche mai gas ki flame ke pass hai aur kuch Dane upper hai jis-se kuch Dano ko Jada heat mil rahi hai aur kuch Dano ko kam heat mil rahi hai -"CHEMISTRY"😎😎😎
👉 Practice Sheet - Go to Batch - Subject Section - Open DPP PDF Section.
📕 SPRINT Class-9th - physicswallah.onelink.me/ZAZB/0y4x6bma
📕 Telegram For Quizzes :- t.me/foundationwallah
Sir DPP question 14 have no figure
Sir DPP question 14 has no figure
@@HarshMadheshiya hey I am not getting the practice sheets can you tell how to get the practice sheets because when I opened its showing to pay for that.
There is a issue in ios
But If u have android then reopen or reinstall app
Please tell answer of 15 question
A or B
The A/R one
I wrote B
Its not given In answer key
I wish everyone get 95+ percent in his/her class
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100 percentage 😮😮😮
You get 0 out of 100😂
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I pray the person who liked my comment will get 99% out of 100
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33:44 I am leaving now please like to remind me tomorrow
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Q aap hi examinor ho kya jo aap 99.99% doge
00:00 - Introduction
05:50 - Motion
20:06 - Uniform and non-uniform motion
30:55 - Physical quantity
34:54 - Distance and displacement
48:44 - Speed and velocity
58:15 - Acceleration and types
1:08:37 - Uniform and non-uniform acceleration
1:17:11 - Distance-time graph
1:26:06 - Velocity-time graph
1:33:49 - Equations of motion
1:38:36 - Uniform circular motion
1:47:28 - Thank You Bacchon!
Thanks so much❤
Thank u so much 🙂
30:46 34:22 34:24 34:24 34:24 34:24 34:25 34:25 34:25 34:25 34:26 34:26 34:26 34:26 34:26 34:27 34:27 34:27 34:28 34:16
01:08:12 - Answer is:
Initial position (u) = 0 m/s²
Final position (v) = 40 km/h = 40 x 5/18 = 200/18
time (t) = 10 minutes = 10 * 60 = 600 seconds
a = v - u / t
so, (200/18 - 0/18) / 600 = 200 - 0 / 600 * 18 = 200 / 10800 = 2/108 = 1/54
Hence, acceleration = 1 / 54 m/s²
Thanks you confirm my ans
THANKS
Yes, this is the correct answer
Bro why you took m/s² as initial velocity this is not acceleration
And if we are talking about speed in question how velocity can come
00:02 Understanding motion and average velocity
02:41 Get the support you need to excel in the exam
07:26 Motion is defined as the continuous change in position of an object.
09:54 Understanding motion and rest in relation to surroundings
14:58 Motion is a relative term dependent on the observer
17:20 Understanding the concept of motion
21:47 Difference between uniform and non-uniform motion
24:04 Acceleration in uniform versus non-uniform motion
28:33 Covering equal distance in equal time intervals
30:52 Physical quantities can be measured but love, color, and sadness cannot.
36:24 Distance and displacement in physics
38:39 Understanding the concept of shortest distance and displacement
43:31 Calculating total distance and displacement
45:52 Displacement can be zero even if distance is covered
50:38 Unit of speed in CGS is meter per second
53:12 Calculating distance and average speed in physics experiments
57:45 Acceleration is the rate of change of velocity.
1:00:30 Acceleration can be positive or negative based on velocity changes
1:05:09 Finding the acceleration of a bus given initial and final velocities and time
1:07:43 Understanding uniform and non-uniform acceleration
1:12:07 Understanding uniform and non-uniform acceleration
1:14:20 Understanding origin, positive and negative distances, independent and dependent variables
1:19:22 Understanding scaling and graph plotting concepts
1:21:42 Understanding the slope of a distance-time graph helps determine uniform motion.
1:26:38 Understanding constant velocity and distance calculation.
1:29:15 Understanding velocity-time graph in motion
1:33:48 Understanding the three equations of motion and their variables
1:36:23 Understanding velocity and acceleration equations
1:41:30 Understanding Accelerated Motion and Uniform Circular Motion
1:43:54 Convert R to kilometers & seconds to meters, Calculate average speed
1:48:33 Importance of hard work in telling stories
Bhai kitne ghante Lage likhne mein 😂
Tumne phadne se jyada time to ise likh ne me waste kar diya 😂😂
Thank you ❤! This helped me
00:00Introduction
05:50 - Motion
20:06 - Uniform and non-uniform motion
30:55 - Physical quantity
34:54 - Distance and displacement
48:44 - Speed and velocity
58:15 - Acceleration and types
1:08:37 - Uniform and non-uniform acceleration
1:17:11 - Distance-time graph
1:26:06 - Velocity-time graph
1:33:49 - Equations of motion
1:38:36 - Uniform circular motion
1:47:28 - Thank
❤
Bhai you youtuber
😮
I pray that the person who would like this comment will get 96 out of 100
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But i got 79 out of 100 this is not fair
Agar nhi hua toh dekh lena
Nhi bhai mujhe to 100 chahiye nhi like krun ga kya kar lega khud mein pray kar Lunga lekin tumhe like nhi dunga😂😂😂😮😂😂😂
1:08:22 Hw 1 -:
Given - U = 0
V= 40 km/h
Therefore by converting it we get v = 11.11 m/s
And t= 600 (s)
Now acceleration = V-U/ t
By substituting the values =11.11-0/600
Which gives a= 0.0185 m/s^2
I hope I am correct
Right ❤
Don't write the decimal value do like this
Acceleration=v-u/t
200/18/600
200/10800
2/108
1/54 ms^-2
👍
@@Vaibhavfrombgmi thanks Bhai Mera galat ho rha tha ✨✨✨
Me here who is thinking that it is zero because of no change in valocity
v = 200/18 m/s
not 11.11
And i pray the person who likes. My coment will get 99% ❤
It's not depend on to like your comment it's depend only on hard work 🙂
Thanks for comment pr hme like nhi krna 😕
⏳ TimeStamps -
00:00 - Introduction
05:50 - Motion
20:06 - Uniform and non-uniform motion
30:55 - Physical quantity
34:54 - Distance and displacement
48:44 - Speed and velocity
58:15 - Acceleration and types
1:08:37 - Uniform and non-uniform acceleration
1:17:11 - Distance-time graph
1:26:06 - Velocity-time graph
1:33:49 - Equations of motion
1:38:36 - Uniform circular motion
1:47:28 - Thank You Bacchon!
I wish every one get 97+
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FOURTH LAW OF MOTION:-
Every book remains at the state of rest until and unless any external or internal exams appear, and then the speed of turning pages will be directly proportional to the amount of syllabus to be completed in time and the tension in mind remains constant...
This man should we awarded
Relatable 😂😅
Ya retable 😂😂😂
This is already a meme 😂
Abhi to Naya session start hua hai aur abhi Bhai Aisa keh rhe ho 😭💀😵
HW 1 1:08:08
Velocity= V-U/t
Time= 10min=600sec
V-U= 40km/hr (bcs its uniform)
Converting it to m/s
40×5/18 = 200/18 m/s
Now V-U/t
=> 200/18/600 = 200/18×600
=> 200/10800
=> 2/108
=> 1/54 m/s²
Bhai Mera 1/18 m^2
Tune converting Karte samay kataya Nahi hai
@@rachitroy2968 galat aaya hai
@@rachitroy2968 correct
44:00 1 - B 16
2-A 0
3- (B) magnitude & direction
4 - (B) Distance is greater than displacement
5 - Vector
6 - Yes , a object can have zero displacement if it comes back to its initial position
India has won T20 world cup 2024 toh koi sad nhi hoga 😅😅
Haa
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Tumari kya jata
1:08:35
a=v-u/t
Final velocity=0
Initial velocity=40km/h
40×5/18=200/18
Time=10min
10×60=600
=200/18/600
=200/18×1/600
Cancellation
1/18×3
1/54.
18 se divide kyu kiya gya
SUMMARY
_____________
The video covers the concept of motion, including distance, displacement, speed, velocity, uniform and non-uniform motion, and acceleration. It explains the difference between distance and displacement, and how to calculate average speed and velocity. The video also discusses uniform circular motion and the equations of motion.
Key moments:
00:00 Understanding the concept of motion and how objects change their position with time is crucial. Consistent effort and focus are essential to excel in exams and achieve good results.
-Importance of consistent effort and focus in achieving success in exams and understanding motion concepts.
-Reflecting on past efforts and preparing diligently for upcoming exams to improve results and progress to the next class.
-Exploring the concept of motion, displacement, speed, and velocity in physics to enhance understanding and excel in exams.
08:08 Understanding the concept of motion and rest in relation to observation is crucial. Objects in motion or at rest depend on the observer's perspective, defining absolute and relative terms.
-Exploring the concept of motion and rest in relation to observation and perspective.
-Discussing the examples of Statue of Unity and Statue of Liberty to illustrate the concept of motion and rest.
16:14 Uniform motion refers to an object covering equal distances in equal intervals of time, maintaining a constant speed, while non-uniform motion involves covering unequal distances in equal intervals of time with changing speeds.
-Definition of uniform and non-uniform motion. Uniform motion maintains constant speed, covering equal distances in equal time intervals.
-Example of uniform motion with consistent speed. The concept of covering equal distances in equal time intervals explained.
-Contrasting uniform and non-uniform motion. Non-uniform motion involves changing speeds, covering unequal distances in equal time intervals.
24:17 Understanding the concept of uniform and non-uniform motion is crucial in physics. Observing equal time intervals and distances covered by different objects helps differentiate between the two types of motion.
-Explaining the significance of uniform and non-uniform motion in physics and the impact on acceleration.
-Analyzing the motion of different objects over equal time intervals to determine uniform or non-uniform motion.
-Discussing the concept of physical quantities and how they are measured, including examples like height, weight, and color.
32:21 Understanding the concept of distance and displacement is crucial in physics. Distance is the actual path covered, while displacement is the shortest distance between two points.
-Differentiating between physical quantities like scalar and vector quantities is essential in physics education.
-Explaining the concept of distance and displacement using a running athlete as an example.
-Illustrating the difference between actual path length and displacement through a practical measurement example.
40:28 Understanding displacement in physics is crucial. It is the shortest distance between the initial and final points of an object's motion, often resulting in zero displacement.
-Explaining the concept of displacement and its significance in physics.
-Differentiating between displacement and distance covered by an object in motion.
-Discussing scenarios where an object's displacement can be zero based on its starting and ending points.
48:34 Understanding speed, velocity, and their relation to distance and time is crucial in physics. Speed is distance divided by time, while velocity is speed in a specific direction.
-Difference between speed and velocity, and their basic definitions.
-Conversion of speed and velocity units from meters per second to kilometers per hour.
-Calculation of average speed using total distance and total time taken.
56:40 Acceleration can be positive, negative, or zero based on changes in velocity. Positive acceleration means increasing speed, negative means decreasing speed, and zero means constant speed.
-Understanding positive, negative, and zero acceleration based on changes in velocity. Positive acceleration indicates increasing speed, negative acceleration indicates decreasing speed, and zero acceleration indicates constant speed.
-Explaining acceleration in the context of objects in motion. Positive acceleration occurs when speed increases, negative acceleration when speed decreases, and zero acceleration when speed remains constant.
-Defining distance traveled by a body in a given direction in a unit of time. Speed is calculated as distance upon time, representing the distance covered in one second.
1:08:38 Understanding uniform and non-uniform acceleration is crucial in physics. Objects experiencing uniform acceleration change velocity at equal intervals of time, while non-uniform acceleration results in velocity changes at unequal intervals.
-Uniform acceleration involves consistent velocity changes over equal time intervals, crucial in physics concepts and calculations.
-Non-uniform acceleration leads to varying velocity changes over unequal time intervals, impacting object motion and physics principles.
1:12:50 Objects moving with non-uniform acceleration experience unequal changes in velocity over equal intervals of time, leading to non-uniform motion. Graph plotting plays a crucial role in understanding motion and scaling is essential to represent distances accurately.
-Non-uniform acceleration causes unequal changes in velocity over equal time intervals, impacting motion characteristics.
-Graph plotting is vital for comprehending motion dynamics and analyzing velocity changes.
-Scaling in graph plotting ensures accurate representation of distances and prevents distortion in data interpretation.
1:21:05 Understanding slope in distance-time graphs is crucial. It helps determine speed, uniform motion, and non-uniform motion in objects' velocity-time graphs.
-Slope calculation aids in finding speed and uniform motion in distance-time graphs.
-Velocity-time graphs reveal uniform and non-uniform motion based on constant velocity or changing speed.
-Analyzing the area under velocity-time graphs helps determine distance covered by objects during motion.
1:29:25 Understanding the relationship between velocity, time, acceleration, and displacement is crucial in physics equations. By analyzing graphs and equations, one can calculate key parameters accurately.
-Interpreting velocity-time graphs helps determine acceleration and displacement. The slope of the graph indicates acceleration and provides valuable information in physics calculations.
-Equations of motion involve variables like initial velocity, final velocity, acceleration, time, and displacement. Solving these equations accurately is essential for physics problem-solving.
-Practical application scenarios like calculating acceleration and displacement for moving objects from rest are demonstrated. Understanding the given parameters is key to solving physics problems effectively.
1:37:28 Understanding uniform circular motion and accelerated motion concepts is crucial in physics. The direction of motion changes in accelerated motion, while speed remains constant in uniform circular motion.
-Difference between uniform circular motion and accelerated motion. Understanding how direction changes in accelerated motion and speed remains constant in uniform circular motion.
-Calculating average speed in physics. Explaining how to calculate average speed using distance and time measurements.
-Solving a physics problem involving jogging. Analyzing the time taken for a jogger to cover distances between points A, B, and C.
1:45:36 Understanding the concept of average speed and total distance covered in a given time is crucial for solving physics problems efficiently and accurately.
-Calculation of total time, distance, and average speed helps in solving physics problems effectively.
-Exploring displacement, initial and final points, and minimum distance between them enhances problem-solving skills in physics.
-The importance of hard work, focus, and confidence in achieving success in academics and exams is emphasized.
Generated BY sider.ai
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Waaahhh bhaiii😊😊
1:30:26
Sir Area of Velocity-time graph gives displacement not distance..
Distance is given by the area of speed-time graphh..
Motion in straight line is in syllabus of us (class 9)...To jab motion straight line mein hota hain tab to distance and displacement same hi hua na
@@Arnab_Mahapatra_9 jii nhiii... Straight line m motion backward direction m bhii toh ho sktaa hh..
@@Arnab_Mahapatra_9 kya huaa bolti band😂🤣
@@Aainehaqbhai but same direction me ho, to fir to same bhi keh sakte hain, right ?
Chup raho google kar lo
30:45 Amar's and Anthony's car speed are in *uniform motion* as they are covering equal distance in equal time interval.
Whereas, Akbar's car speed is in *non-uniform motion* because the speed is changing.
Bcz acceleration is changing
Ravi Teja movie
16:10
1- Relative
2- Position
3- Stationary
1:44:19 question asks abdul .and see the timing pf his expression at this point.. .maqsad😂
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@@Unknownguy_259 Hello i am your friend
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H.W.1.---------------- U(initial velocity)=0
v(final velocity) = 100/9 m/s
time duration = 10*60s = 600s
Acceleration (a) = (v-u)/t
a= (100/9) m/s/600 s = 0.0185 m/s² (approx).
or
Initial velocity of the train, u = 0 (since the train is initially at rest)
Final velocity of the train, v = 40 km/h = 40*5/18 = 11.11 m/s
Time taken, t = 10 min = 10 × 60 = 600 s
Acceleration = a= v-u/t = 11.11 * o/600 = 0.0185 m/s2
Hence, the acceleration of the train is 0.0185 m/s2.
I HOPE THIS WILL HELP YOU, AND ALL THANKS TO THE TEACHER, 😁
Nice bro 🎉
Bro thanks to you I have just copied your comment and sent. Dil se thank you ❤😅😊
@@toxicgaming_2.0 mai gira hoya banda jama nich baliye 😂😂
16:05
1.b) relative
2.c)position
3.a)stationary
Tommorow is my pt and best of luck to everyone for their sci exams🎉🎉 maine kuch ni pda
16:10
1)relative
2)positive
3)stationary
44:02
1)16m
2)0m
3) distance is greater than displacement
4)vector
Please like it
🎉@@KrishuSingh-f3pI liked it❤
Fees school mein de rehe hai or padne UA-cam ke pass aa rehe h 😅😅
Baat toh sahi h
@@umashankargupta4814 bhai itni konse school mein hoti h 😂😂
😂😂
@@UnKnow-gp1bs it's true 😂😂
Lol btw what's your name brother
1:35:57 Sir, The acceleration is 2cm/s^2 not 2m/s^2. So, the final answer will be 0.06m/s^2
I pray you all got a 100% in annual exam🎉
54:08
Sir you actually used 3 x 10⁸ m/s but in the question it says 3 x 10⁸ m s-¹
m/s and m s-1 are same....
@@ridhimasingh807 thanks for the clarification, I really appreciate it 🙂🙂
7. 16.7 m s 1:44:25 lative 16:06
2.position 16:06
3.stationary
4 154slope 8/5 1:32:19
Kon kon 8th khatam hone ke bad April ma ye ch padhai kar raha hai
Mai
Yes 😂
Yeah
🎉
Me
U=0 (given)
V=40/hr(given)
Formula of acceleration=v-u/t
V=40*5/18. =200/18
200/18 - 0 /10 min (600sec)
200/18*600
1/3*18
1/54. = Acceleration 1:08:16
1. Option B
2. Option C
3. Option A
4. Option B
5. Option A
6. Option B
7. Option B
8. Option A
9. Option C
10. Option C
11. Option A
12. Option A
13. Option C
14. -1.1 m/s2
15. 6 m/s
16. 96 m
17. 50 km/h and 13.8 m/s
H.W 1. 26.6 m/s is the avg. speed of Abdul's trip
Thanks bro I confirmed the last one
@@Gosammerglowyour welcome
Newton's 4th laws says that every book continuous to be in rest until and unless internal and external exam appear and speed of page turning is directly proportional to the syllabus to be cover and tension in the mind remain constant
😂😂
😅😅
Newtons's Law of Ashiqui:-
Every ashiqui continues to do ashiqui until an internal or external,i.e, by home or girl's family, 'flying chapal' is thrown upon his face by a 'lovely girl'.
This external/internal 'flying chapal' is called 'Bezzati' which is directly proportional to 'Besharmi', however,'Bezzati remains constant.
😊😊
Pagal ha kya bewakoof
😂😂😂😂@@prakashgagrai7524
32:07 sir kyu yaad dilaya 19 nov ki raat ko 19 December me video Dalke😢😢😢
😢😢😢😭😭
I don't understand this 1:36:49
I Understand 90-92% chapter
But some topics I don't understand better 😢😢
But I will try my best 💯👍to understand it
Time 1:32:15
Ans - slope = acceleration =1.6m/s²
1:27:21 That kid is "Walking" at a Speed of 180km/h.👏👏
1:36:25 Yeaah Ofc! "Right" Answer with "Correct" Unit👏👏
Finally found a comment on this i thought no one noticed lol
Guyss this lecture is so useful my physics teachers 😭teaches well but I don't understand what she says this lecture was literally so😳 helpful my exams will start from 15 😇July but I'm starting the syllabus from today (STUDY AS SOON AS POSSIBLE BECAUSE IT IS 9TH) ❤
(LIKE THIS SO EVERYONE CAN SEE THIS COMMENT AND BE MOTIVATED)
How much did you got in your 9th class
To find the acceleration of train, we can following the formula:-
A = u - v /t
Given:-
U = 0 [ as the train start from rest ]
V = 40 km/h
T = 10 minutes
= 10/60 hours
= 1/6 hours
Now, let's calculate the acceleration using the given values :-
A = U - V/ T
= 0 - 40
= 40 km/h
= 40 km/h / (1/6)
= 40* 6 km/h
= 240 km/ h²
1:10:50 What Is The 1st Child Doing In The Bus 🚌?(Sus)
Ans: The Child Is Doing Something Suspicious 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀 💀
Edit : Watch In 2X Speed :D
AYOO WHATT BROOOO 💀💀!!
2024 students here..😂😂
Me 2.
Me
Padh le bhayi
@@anuradhasingh6908 whi kr rhi tum?
Me also kyu ki mujhe Rakshak sir ki Baat smjh nhi aati😢
Sir appne bahut accha explanation kiya but physical quantity me world cup final 32:15 ke alava koi dusra example nhi Mila tha sir😢😢😢
Bhaiyon or beheno 😅😅
Jis jis ke pa1 ya yun kaho unit 1 ke exam a rahe he vo thoko like button 👍👍or ha jis ne kuch nhi padha he or video exam se ek din pehle dekh raha he un logo ko mera solute👏👏
Dude!!....salute
Btw thank you for ur salute 😅
😂😂
Salute bhai!!!
1--->>>> 16 m
2--->>>> 0 m
3--->>>> B) magnitude+ direction
4--->>>>B) distance> displacement
5--->>>>vector quantity
*?*--->>>>Yes it can be 0 as if an object(x) has to reach the initial to final destination and it is the same (y) then , the displacement must be 0.
Que 1 =16m
Que 2 =0
Que 3=magnitude and direction
Que 4=distance > displacement
Que 5=vector
Que 6= yes if the object have same starting and ending point
Kitne chapter ho gye 😅
Yes when that object reached to the same initial point therefore displacement =0
15:40 but sir if any question in exam come like - the statue of unity is in motion or not , so what is the correct ans ??
Motion is relative so the statue can be at rest for one observer and in motion for another
@@Nedeyz if this question come in true or false so what is correct ans??
@@Gorishankar_recipes this type of question will not come in exam
Just sue your school for gods sake
'36:28' Sir, you said that," Distance is a Scaler Quantity", hearing which a doubt emerged in my mind that 'Distance is a Vector Quantity' but later '47:31' question 5, you said that " Distance is a Vector Quantity" please notice that.
@instagramshorts6672 Yes I heard it but in both the timings I mentioned in both times he says different, one time scaler and another time vector.
Bhai mai world cup haar ne gaam ab Tak nhi bhula pa rha tha phir se sir ne yaad dila diya 😭😭🥲🙃🙃
😢😢😢😢
😢😢
Like me Kon kon class 8th ke final ke baad 9th ka tyari kar raha hai
10th ke baad Mai hu yha 9th revise karne ke liye 😢😅
Me
Us brother us 😅😅@@abulkaish989
Me
Me
1:27:12 the boy made a world record by running 50 metres in 3 second. 100 metre in 6 second.
While the usain bolt ran 100 metres in 9.6 seconds😅😅
😂😅
32:27 Phir se world cup 😢😢😢
phir sai rula diya
Kyu nhi horha move on 😭
kyu nhi ho rahi padhai @@akarshivaishnav6261
who will like this comment he or she will get good news 😊😊
Kis bat ki😅
@@annapurnajadahao8974swarg Jane ke
bhai muje pregnant nahi hona
Hi tum Kon ho
Kya baat hai
2024 _2025 batch ?
Hello
🙌🏻
Yup
Yup
Hii
2:40 directly watching this 🥴🥴🥸❣️
Homework 1:-
Initial velocity or u= 0 m/s
Final velocity or v= 40×100÷3600m/s
=11.1m/s
Time taken or t= 10 minutes
10×60second
= 600 seconds
Accerleration or a=
Final velocity(v) - Initial velocity(u) ÷ time taken(t)
= 11.1 - 0 ÷ 600
=0.0185 m/s square
1:08:30 H. W 1 ans 0.0185m/s²
Mera bhi yahi aaya kya ye sahi hai ??
34:47 "agar kisi ne bhagne ki koshish ki to sumajh lena"😇😶😬🤣🤣🤣👍
Thankyou for 2 likes🤧🤧🤧
I can't imagine ki mujhe samaj aa gaya and yet i am wrak in math and physics agr 100% hua toh mujhe 80% toh aaa gya 🎉🎉🎉🎉🎉😊😊😊😊 thankyou soo much sir thank u physics wallah team you are best' 😊
Time 1:32:15
Slope = acceleration=1.6m/s²
Amazing lecture ❤❤
I hope I will get good marks with amazing lecture+ my hard work ❤❤
21:16 horror jumpscare 😂
1:39:06 sir you are my favourite teacher of physics me aapse class 8 se padh rahan hun tab se mujhe physics me maja aane laga
The amount of times he keeps fixing/touching his hair ☠️☠️☠️☠️
Omg fr it just scratches my brain dayum
Kamal (k², maths) sir ka video dekho ye kuch nahi lagega
In school when your teacher teaches you not understand but when alok sir teach your all doubt clear 😅😊😊❤
1:08:26 homework 1 Acceleration =1/54 m/s sq
1:32:23 Slope= Acceleration = 8/5 m/s sq
43:54.
Q1. B 16
Q2. A 0
Q3. B magnitude and direction
Q4. B distance is greater then displacement
This is the way of teaching.... school mein teacher chadi le ke ajata hai aur agar question pucho to class se bahar nikal dete hain yaha question puchne ki gunjaish hi nhi rehti aisa padhate hain ... thanks a lot pw for this Amazing faculty with a amazing teaching method 😊❤
1:35:59 acceleration 2 metre per second sq nai 2 cm per second he
Video start at.5:21
Save ur time
1/54ans 1:08:16
Decimal me hoga 0.185m/s^2
Scaler - only required magnitude to measure
Vector - require magnitude as well as direction
I understand wht is magnitude... but direction?? How can we take a scaler quantity example??
1:32:06 Answer:-
Slope = Acceleration
=y2 - y1/ x2 -x1
=32 - 16/ 20 - 10
= 16/10 or 8/5 m/s
Is I'm right 😅😅
I wish who like this comment will get 99%in class
I wish everyone got 98 percent in their final term
Thank you so much for your lovely response ❤❤❤❤
❤
Sir Har ek makke ke Dane ko same environment nahi mil raha hai qki
Kuch Dane niche mai gas ki flame ke pass hai aur kuch Dane upper hai jis-se kuch Dano ko Jada heat mil rahi hai aur kuch Dano ko kam heat mil rahi hai -"CHEMISTRY"😎😎😎
22:56 speed 2x per dekho lag raha hai sir dance kar rahe hai 😅
Haam😂😂😂😂😂
how much student said that pw is not learning platform it just emotion
28:23 😮sirrrrr😅😂
1:32:21 slope - 8/5 metre per second square.
Same!!
1 .relative
2. Position
3. Stationary
17:15
HW Ques :- average speed = 3 m/sec
average velocity = 0 m/sec ( because Displacement is "0" )
Kaisa
Sir you teaches very nicely I was watching your video recently 3 weeks ago and my all concepts is clear of this chapter. Thankyou❤❤
43:16 I am living this lecture remind me Tomorrow ❤
C9me to study bro
1:14:15 bhaiya don't know the spelling of origin 😅😅
Question1. Relative
Question 2.position
Question 3.Stationary
34:50 pe magnitude + direction and follow triangle law of vector addition
I understand this full chapter 👍... Thank you so much😊 sir... For explain this chapter
Thank you so much sir for this amazing lecture ☺🥰✨🙏
Me alok Chaubey watching alok Chaubey sir😂
Hii
@@RaviRanjan-lu5es hi
Hii
Wah kyaa baat hai.. 😂😂
Hii
Sir If A Person Move in A Circular Way Where He Is Standing Than Is He In Motion?
yes