Sir i am first attending your class i like so much sir sir one ques is there I mpreparing for neet i can follow u for physicspls tell sir i will surely see your lecturrs i like you lectures it is very helhpul pls tell me sir
Sir dont know how to thank yuh :) and my exam is on 20 feb ..this year was so short just 6 months!!..i hope my exam will come of easy level as completing 11th syllabus was difficult for us : ( after 10 cls ,11 cls level was at good height *(i feel so) i wish everyone good luck
Thanku so much sir... tomorrow is my exam and I'm very scared.. but after watching this video I'm confident.. u just clear my all doubts and now I'm ready for my test...🙂🙂once again thanku so much abhiskek sir😌😌
bcz of my late decision to join academy for neet i have a lot to manage bcz of backlog but bcz of sir it is getting really easy for me thankyou for your hard work sir
Answer of last question is 44.5 meter of distance travelled by object in 12th second. Thanks for this great session sir, i am highly grateful to you for this video as I was struggling with questions and basics were not much clear but after this video I have full confidence that i can solve question of this chapter too Best video that i have came across for this topic so far thanks a lot 🙏
TOMMOROW IS MT FT AND WATCHING IT AT 2 AM THANKU SO MUCH SIR FOR THIS GREAT AND HELPFUL LECTURE. AND YOURS SUBSCRIBERS ARE ''295''K RIP SIDHU MOOSEWALA.
This feature is making his money not making your future ok he will make your future then he will provide you with better knowledge not in 1 hour full chapter ok
Sir .. in the monkey q. The relative velocity of the monkey with th train will ve -18 km/h as the monkye was running against the motion of the train and the final answer will be 36km/h
Can you please admire the fact that this teacher was teaching us till 1:30 a.m. in morning. Hats off to such teachers Thank you so much sir for such an amazing One shot
@@Ziya_0909 t=5s. v= 25m T= 8s. V= 34m T= 12s. V= ? V= u+at 25= u+ 5a. ......i 34= u+8a. ......ii On subtracting i from ii, a= 3m/s² Putting the value of a in eq i, U=10m/s Sn= u+ 1/2.a.(2n-1). [n=12] Sn= 10+1/2×3 (24-1) Sn= 10+1/2×69 Sn= 44.5m
tomorrow is my half yearly exam, i was so tensed as i was left with some chapters and this video of yours helped me alot,sir you and your videos acted as my savior as i am clear with all the topics and all ready for tomorrow's exam Thanks alot sir 😇😊 That was actually worth watching it!❤
At 50:04 the answer will be -36 not 72 as the monkey is running against the train direction and becaues of this there will be subtractions not addition in velocity. Please review this comment as it can cause dought in student mind so please .
Sir... May i know aap kon si batch ki taraf se study video banate he ...ya may be aap khud akele hi padhate hai but jo bhi ho sir aap bohot accha padhate hai 😊😊
User sir you have explained this in Banaras and any one cannot explain this in Banaras you are the powerful and the smart teacher cersei my family don't see my this I have written mistake 😔😔😔
Sir is this sufficient for jee .....as I know this is not enough and yaa sir you should also make one shot on numericals which are based on special cases so that this can help us to sharp our mind ... please sir
@@vidhibabbar Ok so the formula is Sn=u+1/2 a (2n-1) where u=10, a=3, n=12 just put the values in this formula then, Sn=10+1/2*3(2*12-1) Apply bodmas rule then solve = 10+3/2(2*12-1) =10+3/2(24-1) =10+3/2*23 =10+23*3/2 =10+69/2 after l.c.m. =20/2+69/2 =20+69/2 =89/2 =44.5 Answer
Buy my Physics Book - amzn.to/3PZzGqj
@@khanieltsok
Sir questions answers ki bhi video create kijiye na sir👀
Sir questions answers ki bhi video create kijiye na sir👀
Thanks you so much brother
❤
Sir i am first attending your class i like so much sir sir one ques is there I mpreparing for neet i can follow u for physicspls tell sir i will surely see your lecturrs i like you lectures it is very helhpul pls tell me sir
*~1 like and subscribe = Infinity ♾️ year your mother's life please bhaiyo bheno kar do yarr🥺~*
Ye koi tareeka h bheek mangne ka 🤡
Sharam kr sanatani ho kr like ki bheekh mang rha h
😮🎉😊😮😮🎉😂😊😢😂😂😢😢😊🎉😮🎉😢😅😂
Bruh kuch bhi 💀
Done
this is a true life saver for half yearly exams , thank you so much sir for providing such amazing content .
what skl same here
@Harsh Vlogs bro can u give me ur paper?? Toh thodi practice ho jayegi
Really bro that's true 💯❤️🔥
Yeah 👍
ya you are right mai bhi half yearly ke ek din pehle padh rhi hu
Arjuna jee 2.o attendance here jiski 11 barbad ho chuki hai😢
Present🎉
@@Killerharsh895 us bhai us
Puri tarah se barbad ho gyi hai
Puri khatam
Barbad😢
What my teacher did not explain in 10 days, he explains in 1 hr 👏👏
are you able to solve hcv ?
Bhai
@@enchantedsoul8796 🤣🤣
Cauz he teaches in English and your English is like💩
Is this vdo helpful for neet 2023 agr hum 11th bhul ge h ab ye dekh k questions lga le pyq bs??
57:32 Sn = 10 + ½ × 3 (2×12-1)
= 10 + 1.5 × 23
= 10 + 34.5 = *44.5 m*
Thank you sir for class 🔥
Thanks for correction bro
74m🤕
320m💀☠️
m per s
bhai mera 6.022*10 ki power 24 particles arha
Anyone 2024😢😊
Yes
Present buddy
Yah
Yeah I am
Yes
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
Answer of last question is 44.5
And thank you sir for this amazing video
plzzz send the full solved answer of last question plz
mine is 46.2
@@riasingh3502 but mera answer toh 44.5 aaya
Same answer brother
@@murmuanju19 mara bhi 44.5 answer aaya ha
Sir please make on every chapter of 11th
Edit --- A ncert question series also
Yes sir
Yes sir
Yes sir🙂🙂🙂🙂
Yes sir
Yes bro
57:47 Sn =u + 1/2 a (2n-1)
= 10+ 1/2 ×3×(24-1)
= 10 + 69/2
= 20+69/2
= 89/2
= 44.5 m
How do you add 20 ? In the eq. In 4th line and why? I don't understand can you please explain me ?
LCM@@DMXHindiGaming
You are such an underrated teacher, I truly adore this channel .... huge respect to you sir ☺ thank you so much
Yeah he is such a nice teacher
@@pacificprop4 bro doesn't even know the definition of underrated 😭💀
@@gracie9717 ok, try to appreciate sir in simple way
Yeah sir is doing alot for us .. 🙂is it sufficient for school exams??? Pls tell
@@NavjotKaur-yc6uz practice more questions
Hats off to our sir who makes video till 12.30 at night to teach us 🙂👏👏
alakh panday sir makes video in 3Am 🙏
@@Premansh_tak ya alakh sir is very talented teacher & they all do so much of hard work . I also watch his videos 🙂🙂
@@Premansh_tak yes but abhishek sir is also very humble i love both of them
At 10pm
@@sumanshukla456 But I dont like alakh sir
Sir answer of last question is 44.5 . THANKYOU SIR FOR THIS AMAZING LECTURE 😇
My Physics final exam is on 1/03/2023 🙂 May God save me
Edit : I passed guys😂😭God saved me
same.. :(
;(
Bhaii darr lg rha
MÉRÏ V SÍSØ😩🖖😂
Mine too
This man really deserves 50 million+ subscribers. ❤️❤️❤️👍👍👍👍💪💪💪
exactly💯💯
Kuch bhi
bro yeh kuch jyada ho gaya, 5-6 million bhi theek hai
@ѕυяуαиѕн ʝαιи внαι кαниє мє куα ʝααтα нαι?
@@suryanshjain2106 ℓ
TimeStamp-
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
Credit goes to Abhishek Sir...
COPY PASTE ACHA KR LETE HO 🤣12:40 PE SAME MISTAKE SEED😂 LOL BRO
BUT THANKS
Who are watching this video 1 day before final exams
Like thoko
Sir at 50:20 it is 36km/hr because monkey was running in same direction and running against the velo. Of train
Dude its 72km/hr
👍
@@dhruvsingh7621 bro please check the calculation and then try to understand the concept and then read my statement please..
Yes its 36km/hr or 10m/s
thankyou sm, I was really confused:)
Kiskah exam kal hai ??😁🤗🍀
🙋♀️
😢
Unit test hai kal
Mera nhi h
Idhar
Sir dont know how to thank yuh :) and my exam is on 20 feb ..this year was so short just 6 months!!..i hope my exam will come of easy level as completing 11th syllabus was difficult for us : ( after 10 cls ,11 cls level was at good height *(i feel so) i wish everyone good luck
Are you davian
Which School
I am a DAVian and tomorrow is my physics exam and also I am PCMB student
@@karma5394 yeah:)
@@mokshjain2049 yeah i m too :)
This teacher is very amazing fir those students who are preparing one night before the exam😂😂
Thanks for motivating me that this video is helpful 😂
No one night bro ... In 1-2 hours 😂😂😂 ... After 2 hour my exam was start 😂
@@Yadav_Gamer001how your exam Went then ? Me also watching this video one day before exam 😂
@@msparigaming7817 mera to bro pass hona muskil lag rha
@@Yadav_Gamer001 sister bole sakta ho mera chemistry ka boahut bekar Gaya physics ka patanhi kya hoga 🥲pray karo mera kal ka paper tou acha Jaye
( At 7:29 ) sir displacement is always equal or smaller than distance. It can never be bigger than the distance...❤
shut up
Right
Wow what a short explanation of whole chapter ... Such an amazing skill of teaching 🔥
jai allah hu akber
44.5m =SN
Thanks You SIR ..Your Lecture was Very Helpful✨
Mtlb ????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????
correct answer
how? can you explain?
@@syedinaya use
Sn=u+a(n-1/2)
Yess..!!
Distance = 44.5 m..... Thank you sir for your wonderful explanation ❤❤...... really you are a great teacher 😀 😊 👍
or vo monkey wale ka
Me Watching Just 2hrs before my Exam... This generation kids are such a legends...😂😂😂😂 Including me...
TimeStamp-
0:00 Introduction
1:27 Motion
4:30 Distance / Displacement
10:57 Speed / Velocity
12:40 Seed(average/ instantaneous)
14:58 Velocity(average/ instantaneous)
15:45 Question 1
17:05 Question 2
19:17 Acceleration
20:07 Position time Graph
29:14 Question 3
30:12 Velocity time Graph
33:46 Acceleration time Graph
35:15 Question 4
39:15 Relative velocity
44:11 Question 5
50:26 Equation of Motion
53:05 Question 6
55:31 Question 7
Thnks buddy
Is this vdo helpful for neet 2023 agr hum 11th bhul ge h ab ye dekh k questions lga le pyq bs??
@@ayushbhatt4880Is this vdo helpful for neet 2023 agr hum 11th bhul ge h ab ye dekh k questions lga le pyq bs??
Bestest explaination found ever,
Solving all kinds of question easily 🙏!!
Thank you so much sir,
Hare krishna🙏
Sir thanku so much for finishing Full chapter in only 1 hr ❤️❤️
Answer is 44.5 m
Thnk u so much sir for this amazing video ... It helped me a lot✌️
Ans is 45.5
@@rashneetkaur8452 please 🥺 provide solutions
Salute to you sir you are teaching students at 12 am
Thanku so much sir... tomorrow is my exam and I'm very scared.. but after watching this video I'm confident.. u just clear my all doubts and now I'm ready for my test...🙂🙂once again thanku so much abhiskek sir😌😌
Vectors ke numerical bnao
Like this comment for next video 🙂😜
After wasting 2 hour on UA-cam . Finally founded this video. You teaches very well
bhai teacher ache padhate hain par inko syllabus nhi pata inhone motion under gravity and ground nhi padhaya aur uniform motion bhi nhi padhaya. SAMJHA...🤦♂
bcz of my late decision to join academy for neet i have a lot to manage bcz of backlog but bcz of sir it is getting really easy for me thankyou for your hard
work sir
Same thing happened with me
Can I do my neet preparation with his lecture?
@@devansharma8458 yes you can but keep practicing mcq type questions ❤️
Answer of last question is 44.5 meter of distance travelled by object in 12th second.
Thanks for this great session sir, i am highly grateful to you for this video as I was struggling with questions and basics were not much clear but after this video I have full confidence that i can solve question of this chapter too
Best video that i have came across for this topic so far thanks a lot 🙏
How?
57:47 Sn=u+1/2a(2n-1)
=10+1/2×3(2×12-1)
=10+1/2×3×23
=10+1/2×69
=20+69/2
=89/2
=44.5m
TOMMOROW IS MT FT AND WATCHING IT AT 2 AM THANKU SO MUCH SIR FOR THIS GREAT AND HELPFUL LECTURE.
AND YOURS SUBSCRIBERS ARE ''295''K RIP SIDHU MOOSEWALA.
Same
Bruhh 🔥
I appreciate that sir is working very hard for us😀
Kon kon final exam ki preparation ke liye yaha aaya hai ??😂😅
Mein didi ji 😁
😂or Lage bhi pade he
Koi ni
Sir you are the best teacher of physics thank you sir , huge respect you sir
Sir aapne 50:00 pe 3rd answer galat kiya h , or sir 58:14 par apka us formula se gatal answer aayega us ka simple answer h v=10+(3 × 12) , v=46m/s 😘
He is teaching this lecture at 23 am. We should be thank full to these type of teachers of help us to study in free . 🥰
This feature is making his money not making your future ok he will make your future then he will provide you with better knowledge not in 1 hour full chapter ok
You are the best teacher of physics in UA-cam
No word to define your teaching
Thank you so much sir .🥰👍
Ha
Jee main ?
Answer is 44.5m.
Sir you made my concept crystal clear.
Thank you sir😇👍👏
from your Dedicated Student -Jitisha.
But I got 45
I got 41.4 m
I got 363
But how my ans is 184
Mera bhi sam he bro🙂
Answer of relatives velocity is wrong!!!!!
Sir really thank you i hope you will cover all the chapters of ncert in all science subjects 😀
Aap jaisa koi physics pda hee nahi sakta sir
You will grow more and more 💜💜💜💜
Phy wallah
@@khushboopandey4140 aji physics wallah mujhe to uska kuch samaj nhi aata ye sir badhiya padhate h inhe to m 10th se follow karra hu
Sir .. in the monkey q. The relative velocity of the monkey with th train will ve -18 km/h as the monkye was running against the motion of the train and the final answer will be 36km/h
Tomorrow is my physics exam and Iam here to cover the syllabus :'(
It was so helpful for me to understand this chapter thankyou🤎
kaisa gya exam inse padhke
@@PapaPlayerGaming7Is this vdo helpful for neet 2023 agr hum 11th bhul ge h ab ye dekh k questions lga le pyq bs??
Answer of question is 44.5 m
And it was amazing video ever found
Thank u sir for ur best explanation
Mine answer is also same 😎
I get 45?
sir del nahi delta bola karen confusion hota hai dono mai
Sir at 50:10 i think the velocity of monkey will be 54-18=36 bcoz it is running against the motion of train
ANSWER PLZZ
yahhhhhhhhhhhh
Can you please admire the fact that this teacher was teaching us till 1:30 a.m. in morning. Hats off to such teachers
Thank you so much sir for such an amazing One shot
Best of luck for tomorrow exam 😅
Good luck bro
Same 😢
Answer : 44.5 m
Amazing session Sir ❤️!!
Same 🔥
Are yaar mera 264.5 answer aa raha h
how it came
Ans: 44.5m
@@theskeleton2577 same yar mera bhi
Answer of the last numerical is 44.5
Thankyou so much sir🙏🏻
HW answer :- 44.5m
How
@@Ziya_0909 t=5s. v= 25m
T= 8s. V= 34m
T= 12s. V= ?
V= u+at
25= u+ 5a. ......i
34= u+8a. ......ii
On subtracting i from ii, a= 3m/s²
Putting the value of a in eq i,
U=10m/s
Sn= u+ 1/2.a.(2n-1). [n=12]
Sn= 10+1/2×3 (24-1)
Sn= 10+1/2×69
Sn= 44.5m
@@krittikajoshi9510 thanks sister
@@Ziya_0909 most welcome😄
@@krittikajoshi9510 u.=10 ,a=3
Sn = u +a/2 (2n-1)
58:14 -- 44.5m thank you sir for this video 🥰🥰
Same to you
Right
Outstanding sir i never seen a lecture like this you teachs very well in less time love you i understand the whole chapter jn 60 minutes thanks
Answer 44.5= Sn
Helpful lecture for final exams
Tq so much sir 🙏🙏
Correct
Correct
sir u are the best physics teacher in the world . i m following u since last year . sir plz upload letures of chemistry soon plzz
44.5m
Answer of last question
Sir you are really the Best ❤️ . Huge respect to you .
44.5 , nice explanation thanks a lot
Yup , right 👍
tomorrow is my half yearly exam, i was so tensed as i was left with some chapters and this video of yours helped me alot,sir you and your videos acted as my savior as i am clear with all the topics and all ready for tomorrow's exam
Thanks alot sir 😇😊
That was actually worth watching it!❤
did it helped ?coz i have'nt done this chapter at all
@@humajasmine3215 yeah ! It did ..I also didn't read the chapter even once !!
I am also
89/2 = 44.5
In 12th second its velocity is 44.5 m/s.
His subscribers rose rapidly from 117k to 262k in 10 months
What a great achievement for you sir❤
Because of me 🔥
@@afzakhan4134 roohafza refreshing
It's not rapid bro 😭
and now 321k
@@saumiljain4528 AND NOW 1.1 MILLION
😵Mera 22/05/23 ko physics ka U.t hai adha dimag 🧠 mai ja raha 😅 or adha uppar se 😂
Thank you sir soo much
Tomorrow is exam and it helped a lot
Thanks for saving ✌✌
did it rly help u with your half yearly exams
@@Samriddhimish yes I was able to do some questions from this chapter
@@vlogia3728 i hv only 7 days left how should I complete 4 chapterss
@@Samriddhimish yes of course do as much you can
Uday 2025 attendance here jinki 11 barbad ho chuki hai 😢
At 50:04 the answer will be -36 not 72 as the monkey is running against the train direction and becaues of this there will be subtractions not addition in velocity. Please review this comment as it can cause dought in student mind so please .
Bhai topper se dekhkar aske yaha gyan mat pel
@Shivam Singh
Ur explaination is really so good ❤️❤️
Sir i think that part c speed of monkey with respect to ground should be 36km/hr as it is moving against the motion of train A
Physics is just about realisation and imagination of concepts..
In short "EASY"❤..........
Thank you so much sir tomorrow is my half yearly exam this video is very helpful for revision thank you again......
Phyics ke all chapter sirrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr
44.5 🙏🏻 very helpful video sir
14:50 Mai kya karu meri bike ka speedo meter tut gaya hai 😂😂😂
😂😂😂😂😂😂😂😂😂😂😂
57:43 Sn= 10+½×3(2×12-1)
= 10+½×69
=10+69/2
=89/2
=44.5m
aaj kis kiska mid term hai😹😹
Mera 😂
@@MR___BEAN56 hehe😹😹
@@MR___BEAN56 top krenge😹
What a beautiful explanation in less time.. Hats off you sir... Really you are very great...❤🔥
2025 student attendance here 👇🏻👇🏻👇🏻👇🏻👇🏻🖕🏻🖕🏻🖕🏻
Hey MashaAllah, i used to watch alakh sir to clear doubt, but bow now i find him,
The best among best 😍😍😍. Love u sir from Nepal 🇳🇵 ❤️ 💖
❤
Thanks sir apki Vajah se mere exam se pehle Ye chapter clear Ho gya 😊😊😊
Sir... May i know aap kon si batch ki taraf se study video banate he ...ya may be aap khud akele hi padhate hai but jo bhi ho sir aap bohot accha padhate hai 😊😊
Inka khud k chnl h
Thank you so much sir for this video it really helps me to understand the topics well Once again thank you sir 😊
Thankyou soo much sir . Never knew a chapter can be taught within an hour. You are far better than those Public School Teachers.
Motion in a plan
Very beautiful explanation sir you are making our confident strong
Starting m thoda introduction dije sir 😊
User sir you have explained this in Banaras and any one cannot explain this in Banaras you are the powerful and the smart teacher cersei my family don't see my this I have written mistake 😔😔😔
Thank YOU so much sir for this wonderful session loved it !! ♥
Thank you so much sir 💓 you are very helpful to us.
Sn= u+1/2a(2n-1)
S12= 10+1.5×23
S12 = 44.5m
Distance = 44.5 m
Thank you sir for this wonderful lecture
I understand everything
There is Jee mains test in my coaching on 23 july sunday .
how
how
Sir is this sufficient for jee .....as I know this is not enough and yaa sir you should also make one shot on numericals which are based on special cases so that this can help us to sharp our mind ... please sir
Thanks for such a great support ❤️
58:01 The answer is 44.5 m... Thank you sir for your lectures, they are the best out there for oneshot exam preps...
Can you please tell how
@@vidhibabbar Ok so the formula is Sn=u+1/2 a (2n-1)
where u=10, a=3, n=12
just put the values in this formula
then,
Sn=10+1/2*3(2*12-1)
Apply bodmas rule then solve
= 10+3/2(2*12-1)
=10+3/2(24-1)
=10+3/2*23
=10+23*3/2
=10+69/2
after l.c.m.
=20/2+69/2
=20+69/2
=89/2
=44.5 Answer
@@omchaurasia thnkuu soo much !!
@@vidhibabbarbut my answer is 175!
Sir kl mera test hai or maina jitni video dekhi voh 3 yeah 4 ghante ki thii but aapki vedio amazing sb smjh aagya or ab mai prepare huu for test