Wow you simplified it a lot. Excellent model to show voltage current math in transistor. I never new that there are two different equivalent circuit for transistor - linear mode where Ic = B*Ib and saturation mode where Ic = (Vc-.2)/Re. Thanks for that simple yet great explaination
@rolinychupetin I see. So there is no mystery here, simply a KVL analysis of back-to-back diodes in a circuit. Brilliant! Why didn't I think of that (LOL). I'll have to find the lesson where you discuss the turn-on (forward?) voltage of the BJT. I am looking forward to more of your lessons. In the meantime, I'll have to watch (and comprehend) the ones you've already created. Thank you!
@aerofart Several assumptions are rolled up into this 0.2V. (1) That the ON BEJ operates at 0.7V (Silicon, eh?); (2) Very importantly, that the BCJ ceases to be OFF if the Vbc goes below 0.5V (Do you remember how we identified the actual turn-on voltage of a pn Silicon junction, not exactly at 0.7 volts, but rather earlier?) ... (continues in another post) ...
@rolinychupetin (continuation of my response ... chars limits of UA-cam, eh?) ... In this case, we are assuming that the BCJ turns on at 0.5V. Then do a KVL analysis around the transistor and you'll find that if Vbe=0.7V and Vce
Wow you simplified it a lot. Excellent model to show voltage current math in transistor. I never new that there are two different equivalent circuit for transistor - linear mode where Ic = B*Ib and saturation mode where Ic = (Vc-.2)/Re. Thanks for that simple yet great explaination
So clear and well explained! Thank you.
This is great, thank you.
Sir Lineares i always know something new when watching your videos.your channel is the best in youtube IMHO.
Heh, you are always too kind. I'm glad the videos are of some help.
awesome! explained perfectly!
thnk u very much!!
@rolinychupetin I see. So there is no mystery here, simply a KVL analysis of back-to-back diodes in a circuit. Brilliant! Why didn't I think of that (LOL). I'll have to find the lesson where you discuss the turn-on (forward?) voltage of the BJT. I am looking forward to more of your lessons. In the meantime, I'll have to watch (and comprehend) the ones you've already created. Thank you!
Thanks.
@aerofart Several assumptions are rolled up into this 0.2V. (1) That the ON BEJ operates at 0.7V (Silicon, eh?); (2) Very importantly, that the BCJ ceases to be OFF if the Vbc goes below 0.5V (Do you remember how we identified the actual turn-on voltage of a pn Silicon junction, not exactly at 0.7 volts, but rather earlier?) ... (continues in another post) ...
so much thankss Godbless you sir!
+Jackielyn Jane Yogawin Amen. Thanks for your kindness.
thanks sir
Thank you sir......
+Idhant Shivhare You are welcome. Glad to be of help.
@rolinychupetin (continuation of my response ... chars limits of UA-cam, eh?) ... In this case, we are assuming that the BCJ turns on at 0.5V. Then do a KVL analysis around the transistor and you'll find that if Vbe=0.7V and Vce
Thanks, liked and subscribed
are there any videos you read poems. I'd definitely listen to them.
Can you comment on >>why