Continuity of function | Theorem | f is Continous iff f (Ā) is subset closure of f(A) | metric space

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  • Опубліковано 5 січ 2025

КОМЕНТАРІ • 32

  • @OMGMaths
    @OMGMaths  3 роки тому +2

    You can download PDF from:
    omgmaths.com/real-analysis/f-is-continous-iff-f-a-is-subset-closure-of-fa-continuity-of-function-real-analysis/
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  • @07ankitanand24
    @07ankitanand24 10 місяців тому

    just a small mistake that (f( f^(-1)(A)) is a subset of A and not equal to A. it is equal iff f is onto. which may not be the case.

  • @VikasSharma-xb4ev
    @VikasSharma-xb4ev 8 місяців тому

    Same problem topology ka rahne par same proof hoga ya different?

  • @malihafatima9239
    @malihafatima9239 3 роки тому +2

    Mam jii u r great... Bht acha smjhaya... Concept clear ho gia ... Superb ❣️

    • @OMGMaths
      @OMGMaths  3 роки тому +1

      Thank You 😊 Subscribe and press 🔔 for updates.
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    • @malihafatima9239
      @malihafatima9239 3 роки тому +2

      @@OMGMaths After your superb vedio lecture, I have already subscribed your channel ☺️☺️

    • @OMGMaths
      @OMGMaths  3 роки тому

      Thank You 😊

  • @aishinikiyara2675
    @aishinikiyara2675 2 роки тому +2

    Very good explanation mam.

    • @OMGMaths
      @OMGMaths  2 роки тому

      Thank You 😊 Your appreciation means a lot lot for me….Please write your valuable reviews at g.page/r/CRP90Pt3uFhFEAg/review
      Like ,share and Subscribe.

  • @saqibshah5307
    @saqibshah5307 3 роки тому

    thank you mam bht acha smjhate haa app

  • @sonali5687
    @sonali5687 Рік тому

    Can i use this same proof for topological space??

  • @simplewayofliving
    @simplewayofliving 2 роки тому +1

    mam,theorems samajh me toh aa jati hai but karne se beech beech me steps bhool jate hai....what to do?

    • @OMGMaths
      @OMGMaths  2 роки тому +1

      written practice is must jo jhada bhuli hai 2-3 time practice karo

  • @tulsisoni2598
    @tulsisoni2598 Рік тому

    Thank you mam 😄

    • @OMGMaths
      @OMGMaths  Рік тому +1

      Glad it was helpful 😊
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  • @malikbilal3251
    @malikbilal3251 2 роки тому

    Bundles of thanks mam.❤

    • @OMGMaths
      @OMGMaths  2 роки тому

      Please give your valuable reviews at g.page/r/CRP90Pt3uFhFEAg/review

  • @pushkarkumar3089
    @pushkarkumar3089 2 роки тому

    Very nice!!!

    • @OMGMaths
      @OMGMaths  2 роки тому

      It's my pleasure 🙏 Subscribe ua-cam.com/users/OMGMaths and press 🔔 for notifications. Keep Watching…and Share with others.

  • @bseacademy2597
    @bseacademy2597 3 роки тому +1

    Excellent mam

    • @OMGMaths
      @OMGMaths  3 роки тому

      Thanks for the visit 😊.......“subscribe” and press 🔔 for updates.
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  • @harshikeshsingh2648
    @harshikeshsingh2648 2 роки тому

    Good

  • @zahrahayyat7865
    @zahrahayyat7865 3 роки тому

    Mam plz ye theorem bh solve krwayen ksi lecture men plz statement ye hai is ki "A mapping of a metric space X into a metric space Y is continuous on X iff f⁻¹(V) is open in X for every open set V in Y"

    • @zahrahayyat7865
      @zahrahayyat7865 3 роки тому

      Plz mam

    • @OMGMaths
      @OMGMaths  3 роки тому

      This is the required result.
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  • @madhubarman4138
    @madhubarman4138 3 роки тому +1

    Thanks mam

    • @OMGMaths
      @OMGMaths  3 роки тому

      Glad it was helpful!
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  • @surajchouhan1125
    @surajchouhan1125 3 роки тому +1

    Regular lecture daliye Mam

  • @322-pinkidhobi9
    @322-pinkidhobi9 2 роки тому

    Let A = {(x, y) ∈ R^2:
    X^2− 3y > 5}. Show that A is an open set in (R^2
    , d2)
    using continuity.

  • @vishalmaurya3194
    @vishalmaurya3194 Рік тому

    😍😍