K-ANAGRAMS | Strings | Detailed explanation with code, multiple methods with complexities! 💪🚀✌️

[@hemendrakumarsahu6200]

Mam please continue uploading video

[@ShubhamSingh-gk8vp]

Another great video!!! lets Go!!!

[@srishtikapoor7261]

Present 🙂

[@surojitsantra7627]

🙋

[@surekaraja3572]

Present..Well explained!!

[@parth3075]

Back with a bang! 🔥

[@ankushladani496]

Present mam..

[@sameer9368]

I am having 6 years of experience in IT company...but I love your video and the way you are explaining the concept. I am one of your student and brushing up dsa knowledge...Respect for you.
Please also suggest from where could I prepare system design interview

[@vineettiwari4269]

Ma'am pls continue making the video its helping us a lot

[@themayankgoyal_]

Dii you are awesome

[@vishalkulkarni9390]

Hi Today i have started with your first video that's is binary search looking forward to it

[@UnknownUnknown-sw4hb]

Hi am really learning a lot from your videos thank you so much.
Can you please do one video for this question actually am not able to come up with a solution to this
Given a array find partition which divides array into 2 sub arrays which have equal sum
Ex: (1,4,2,5)
Here 2 is partition bz it divides array into 2 parts (1,4) and (5)

[@cut-a-lyst]

What happened, no new uploads?

[@mohitchandola3435]

videos kb aengi didi .....10 oct. to kb ki chli gyi hai

[@Nishchay-kc1gb]

I am present

[@manideepamara2263]

Thanks for motivating with your series

[@vigneshiyer1765]

Present mam!!

[@nageshjatagond4175]

Present

[@kumarpawansahh]

Didi bass aap continue rakhna baaki humpe chordo

[@prantikofficial]

if(str1.size()!=str2.size()) return false; this thing was missing 8:52

[@arunkumarmohandas4420]

Present. Tried the following and cud get all gfg testcases passed:
class Solution {
boolean areKAnagrams(String s1, String s2, int k) {
if(s1.length()!=s2.length()){
return false;
}
Map mapOfCharacterCounts = new HashMap();
for(Character charctr : s1.toCharArray()){
if(mapOfCharacterCounts.get(charctr)==null){
mapOfCharacterCounts.put(charctr, 1);
}
else{
mapOfCharacterCounts.put(charctr, mapOfCharacterCounts.get(charctr)+1);
}
}// end of loop on first string
int numberOfDeviations =0;
for(Character chrcter : s2.toCharArray()){
if(mapOfCharacterCounts.get(chrcter)!=null){
if(mapOfCharacterCounts.get(chrcter)==1){
mapOfCharacterCounts.remove(chrcter);
}
else{
mapOfCharacterCounts.put(chrcter, mapOfCharacterCounts.get(chrcter)-1);
}
}
else{
numberOfDeviations++;
if(numberOfDeviations>k){
return false;
}
}
}// end of loop on second string
if(numberOfDeviations+mapOfCharacterCounts.size()>2*k){
return false;
}
return true;
}
}

[@mohitchandola3435]

video ki length badhao tabhi to smj aega aur hindi m koshish kro vdo bnane ki

[@aatish4697]

Just came across an Instagram video of yours. Just a question, why use this so little asf clout you've got and immediately started using it to shit on Hindu traditions???

[@manumano3887]

Present