using de Moivre's theorem to express sin nθ and cos nθ in terms of sinθ and cosθ ExamSolutions
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- Опубліковано 28 лют 2013
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I passed A level mathematics examinations a few years ago and I have enrolled in electrical engineering with a computer science program. if I had not found your channel a few years ago, my mindset towards mathematics would have never changed. Thank you, sir!
Wow...I just discovered your channel today and I'm happy using it during the Corona Virus Lockdown. I've been watching your complex Numbers videos and I've gained a lot.Thanks🙏
Thank you. This is a great method to check my answer to expanding cos(5x) into cos(x). I wish I could use this theorem since expanding by the compound-angle formulas took me 1 hour.
This has been so so helpful!! Thanks so much for uploading. I just found your page yesterday and I’m understanding the maths I’m currently doing a lot easier. Subscribed and will be keeping an eye out for future vids!!🤩😎
Thank you for subscribing. Best wishes.
thanks this was so helpful , i can't begin to express how helpful this was
That's okay. Thanks for watching.
thank youuuuuuuu .this helped to cure my crazinesss towards math.
Thank you, this was so helpful to me!
Tq soo much u really help me a lot thanks once again
Wow. This helped me so much. Can't thank you enough.
That's good.
Just use the binomial expansion for (c+is)^6 and compare real parts just like I did in the video.
Thanks a lot pal
Thanks sir u are great
thx great help
Thank you thank you thank you so much, your explanation is veeeery clear!!!!
Thank you for watching
this is the definite of sweet science, you explained it with no reservation
using CIS notation makes it so much easier - thank you!!
You're welcome
awesome. Thank you so much
+Jermias Ronald Sahureka You're welcome.
Thank You. That was a very good explanation of that problem.
Appreciated
Yes
ExamSolutions yes sir
Great explanation, thank you :D
+Johan du Plessis Thank you.
Great video, I've only got one question: if the question only gives us something like cos5 theta, then we can assume that z = cos5 theta + isin5 theta?
its very intresting
thnx....clearly i have got this,,,,,,,
Well done
thanks
What if it was like that (Express sin4θ in terms of sinθ)?
!!thank you so much
That's okay. Thanks for using.
thank you sir..
You are welcome. I am pleased to hear it helped.
how do you express Cos 6θ in terms of sums and differences of powers of Sinθ and Cosθ do you only use De Moivre's or also binomial?
Muchisimas gracias, me sirvió muchisímo... pero no sé como realizar el mismo pero con seno (sen4 °)
Tq very much..
You're welcome
Are we allowed to use this abbreviation during the exam?
Do it in multiple choice section
How to calculate cos8x interms of sinx
makasihhh...
can I also do something like expressing/simplifying the sin^n to cos or sin using de moivre's theorem?
like sin^4 is equals to
3/8-1/cos2theta+1/8cos4theta
can I still get that using de moivre's theorem cuz I'm not really good at algebraic manipulation
Yes. Check this out. www.examsolutions.net/tutorials/expressing-sinn%ce%b8-cosn%ce%b8-terms-sink%ce%b8-cosk%ce%b8/?level=A-Level&board=Edexcel&module=Further-Core-Maths-A-Level&topic=1898
I need expansion of sin 4(teta) in terms of cos (teta)
Express "tan5theeta " in terms of "tan theeta". using De'movres theorm . how to solve this equation???
Nice vid, just wondering how I’d do the reverse of this? Like finding sin^n in terms of sin(kx) etc
I think this is what you are after. www.examsolutions.net/tutorials/expressing-sin-n%ce%b8-cos-n%ce%b8-terms-sin%ce%b8-cos%ce%b8/?level=A-Level&board=Edexcel&module=Further-Core-Maths-A-Level&topic=1898
@@ExamSolutions_Maths That's the wrong link. This is the one he needs:
www.examsolutions.net/tutorials/expressing-sinn%ce%b8-cosn%ce%b8-terms-sink%ce%b8-cosk%ce%b8/?level=A-Level&board=Edexcel&module=Further-Core-Maths-A-Level&topic=1898
Wouldn't we need to write let c=cosx and s=sinx before doing the expansion?
That's up to you. It can save space which is an advantage.
Nice explanation but writing imaginary part was a waste of time
Bhh he b be