Thanks so much. I'm three years out of math and My professors question was like "is _ and _ porportional when checking clearance" but they are a mix of logarithmic, linear, and quadratic equations all similarly derived. This helped
11:42 "that is the equation" ... of the curve fit. It might be interesting to note that it is close to T^2 = ((2*pI)^2) / g * L, which comes from the small-angle approximation in high school physics classes: T = 2 * pi * sqrt(L/g)
Regarding the first example no change, the relation ship is that as x changes y stays the same. This would be true in the case of an object moving at constant velocity v vs t is a flat line.
My teacher did this for a single class (and his equations turn out to be wrong) and just the very next class he is taking a quiz for it, and has asked us to “figure it out online”. I’m a sophomore high schooler, things like this don’t happen in other classes.
You don't know what you did for me I was not able t understand graphs ik it is silly but I was literally crying that. I can't understand this lil thing thankyou a billion tims
I think you meant y α 1/x², which is an "inverse square" relationship, such as gravitational force vs distance, which obeys an inverse square law (F α 1/d²). There is a reason that is not listed--the "inverse square" graph shape looks like and inverse at first glance. So what you should do is to linearize it by graphing y vs 1/x, and the new graph becomes a top opening parabola. So now you see that y α 1/x². It's just following the linearization process twice. Otherwise, you would not know if an inverse shaped graph is 1/x or 1/x².
If I understand you correctly, on a y vs. x graph, you are asking about an equation such as 5=x*y? This would be an inverse relationship. Rearrange it to be y=5/x. To linearize this, you would graph y vs. 1/x. If this is not what you meant, please clarify and I'll try to answer.
Not sure if you'll reply but my textbook says to square root my x values to form a linear graph whereas yours says to square it. Which one is correct or do you know why mine is different?
If you first try to linearize for y proportional to 1/x, you would then get a parabola, and you would recognize the need to linearize again to y vs. 1/x². Two steps.
This man saved me from another 13 hours of looking for something that didn’t exist
relatble
This is exactly what I needed for my physics exam, I didn't understand anything my teacher said, but you were so helpful!!! THANK YOU
I’m making goddamn Mac and Cheese, and nobody can stop me.
I'm only watching this because of online classes
lmaoo same
Same
same here
same here why
likewise
Thanks so much. I'm three years out of math and My professors question was like "is _ and _ porportional when checking clearance" but they are a mix of logarithmic, linear, and quadratic equations all similarly derived. This helped
11:42 "that is the equation" ... of the curve fit. It might be interesting to note that it is close to T^2 = ((2*pI)^2) / g * L, which comes from the small-angle approximation in high school physics classes: T = 2 * pi * sqrt(L/g)
THANK YOU SO MUCH!! This helped for tomorrow's quiz :)
did ya pass?
@@qabaselfurjani3973 i guess well never know
Thanks a lot , I really appreciate your effort. May god keep on blessing you.
now it finally makes sense omgg
this was a really helpful video! really well explained.Thank you so much
I’m your 1K follower ;)
Found this really helpful, thanks.
Nice! You really cleared up my confusion. Thanks, man.
Thanks a lot
Wow this was so helpful & easy to understand. Like no words. Tysm! Keep em coming pls!
you are the king of physics
Regarding the first example no change, the relation ship is that as x changes y stays the same. This would be true in the case of an object moving at constant velocity v vs t is a flat line.
Thanks sir ...this helped me a lot🙏❣️
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THATS MY PHYSICS TEACHER
😂😂
THANK YOU I FINALLY UNDERSTAND
This video helped me, therefore I am offering my engagement in return.
this dude teaches so well woah
thank you so much :)
Graphical Analysis. Very COOL!
sir may god bless you thank you so much
Some heroes don't wear capes
U r genious bcs u teachs us very deeply
It really helps me a lot. Thanks for your sharing. Have a good luck!
wow!!! i thought its not that easy ... but now got it clear...
thankyou so much :)
saranya M same man physics looks tough but nah
thanks, mate!
what about a graph which looks like a sector, with the origin as centre
Thank you so much !!! You saved me man☺️
How do you find slope if you can’t really see the rise over run
legend
Very well explained. Thank you MrEScienceTheater.
this guys saved my ass from messing up in my quiz
My teacher did this for a single class (and his equations turn out to be wrong) and just the very next class he is taking a quiz for it, and has asked us to “figure it out online”. I’m a sophomore high schooler, things like this don’t happen in other classes.
Richard Nixon it does.
Thank you, that was very informative 😃😃
You don't know what you did for me I was not able t understand graphs ik it is silly but I was literally crying that. I can't understand this lil thing thankyou a billion tims
I think you are missing one case (y^2 α 1/x) isn’t that usual on physics results?
I think you meant y α 1/x², which is an "inverse square" relationship, such as gravitational force vs distance, which obeys an inverse square law (F α 1/d²). There is a reason that is not listed--the "inverse square" graph shape looks like and inverse at first glance. So what you should do is to linearize it by graphing y vs 1/x, and the new graph becomes a top opening parabola. So now you see that y α 1/x². It's just following the linearization process twice. Otherwise, you would not know if an inverse shaped graph is 1/x or 1/x².
@@tomerekson_lphs7045 i see, thanks!
This is brilliant!, thank you so much!
thank you!
Thank god I found this it was so helpful
What if you did length squared instead?.. Would you still get a linear graph?
Great video!
What about exponential decay? Is there a rule for this that fits?
Where did you get your y intercept?
Thanks for the informative video!
Aww
Thanks a bunch for your help
💞💞
THANKS SO MUCH, iwas gonna die in atar physics
Sup bro.
Holy crap, 1 year ago, I passed hooray
Your next buddy
What does the slope represent? s^2 / meter?
You solved all my problem !!! Thanks
How did you find the slope and y intercept?
You are genius sir👍👍👍👍
thank you so much!
this is soooooo goooood thank you sooo much
what if we have a curve that only becomes linear with x*y?
If I understand you correctly, on a y vs. x graph, you are asking about an equation such as 5=x*y?
This would be an inverse relationship. Rearrange it to be y=5/x. To linearize this, you would graph y vs. 1/x. If this is not what you meant, please clarify and I'll try to answer.
what about the graph of voltage during charging of a capacitor. saturating exponential growth.
Not sure if you'll reply but my textbook says to square root my x values to form a linear graph whereas yours says to square it. Which one is correct or do you know why mine is different?
I suppose you find the answer by now, mind sharing it because I have the same question
Cool, ❤❤❤
Please I have never heard of 5% rule 😢😢
How will you graph y propotional to 1/x²
If you first try to linearize for y proportional to 1/x, you would then get a parabola, and you would recognize the need to linearize again to y vs. 1/x². Two steps.
@@MegaPhysicsdude so graph 1/y vs x, and that gives you a parabola?
That is correct. For an inverse square relationship, if you graph for 1/x, you would then see a parabola.
Nice class
Tnq 😊😊
i am trying to do this for sme calculation i need for work.... the graph is not linear though I used this method... what could be wrong?
Are you sure you named the graph correctly? Is it already linearized?
Thank youuu so much..
❤🇧🇩
I don't understand isn't that time must be independent and length is the dependent?
No. You adjust the length of the pendulum and then time the period corresponding to that length.
thanks Man
oml bless. u saved me
Thanx sir
I love you
This is the video I was finding .........
just subscribed :)
that high pitch screeching AHH
I find it comfortable lmao
How did you find the slope and the y-intercept?
ty
dosent work 2022
thx m8
THANK UUUUU
I have a quiz in an hour
periodt.
Thank you for this helping video
Nice but abit lost
Bernard star calculate
Expain it clerly with more briefly i thought many of viewers not got this
Man I hate physics
when you thought he was making position vs time graphs the entire time and now on top of having wasted your time, you are more confused than ever ( _:
💜💜💜🤘
THANKS SO MUCH, iwas gonna die in atar physics