@@Hari-uy3rm Actually dun have. When u use hairpin u want to have a compact size. Therefore, the width needs to be small. So just choose 1mm and 2mm for the gap.
Thanks for the great video. Could you explain how you calculated the wavelength/4 of "L" to be 20.4mm? I know that that the standard free space lambda / 4 is around 15 mm for 2 GHz and 6.15 Er but I couldn't find a suitable answer for the guided lambda calculation online. Is it in one of your other videos?
Thank you for your question. Yes, here: Filter Design Part 23. Microstrip Design: How to Use the Apps to Determine the Width & Length. ua-cam.com/video/vNX6-sO9JZs/v-deo.html
Thank you sir for this much awaited tutorial ✌. Looking forward to EM simulation video
Thank you for your strong support too. Noted on the EM simulation video. :)
What is the criteria to decide the width of the resonator like how you decided the width to be 1mm here. Should it be near 50 ohms?
@@Hari-uy3rm Actually dun have. When u use hairpin u want to have a compact size. Therefore, the width needs to be small. So just choose 1mm and 2mm for the gap.
Is ready. You should be able to see the video: ua-cam.com/video/MIGZRm-gnoc/v-deo.html
Thanks again for your strong support!!!
Yeah sir thank you ❤
Thanks for the great video. Could you explain how you calculated the wavelength/4 of "L" to be 20.4mm? I know that that the standard free space lambda / 4 is around 15 mm for 2 GHz and 6.15 Er but I couldn't find a suitable answer for the guided lambda calculation online. Is it in one of your other videos?
Thank you for your question. Yes, here:
Filter Design Part 23. Microstrip Design: How to Use the Apps to Determine the Width & Length.
ua-cam.com/video/vNX6-sO9JZs/v-deo.html
Amazing. Thank you. Your contributions on UA-cam are valued!
Thanks. :)
Dun mind to help this Channel by Like this Video & Subscribe to this Channel.
Thank you :)