Determining Derivatives from Graphs (3 of 3: Reversing the process)

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  • Опубліковано 2 лис 2024

КОМЕНТАРІ • 13

  • @arianasiordia6899
    @arianasiordia6899 3 роки тому

    I'm struggling at Berkeley and these videos just helped me a lot, thank you!

  • @nathancasey1183
    @nathancasey1183 5 років тому +1

    Hey Eddie. i would just like to say thank you so much for coming to glossop high school today. it was great wish for you to come back again.

  • @nunotorres6314
    @nunotorres6314 5 років тому +4

    I haven't had maths in 3 years and never really liked it but i love your videos

  • @paulhaso
    @paulhaso 5 років тому +2

    You are a literal god of a teacher. Thank you.

  • @chintuwhitehattjr880
    @chintuwhitehattjr880 5 років тому +1

    love you man, you make me love thinking. thank you very much

  • @tamutalon12
    @tamutalon12 5 років тому

    Going one step further and connecting the third graph to the first with points of inflection would have been a good thing to do as well. Other than that this is a great explanation of how to find graphs with derivatives!

  • @vaktovia
    @vaktovia 5 років тому +3

    Finally early to a video

  • @ichron
    @ichron 5 років тому

    this dude came to my highschool - pretty rad

  • @joao_pedro_c
    @joao_pedro_c 5 років тому

    Amazing videos, thanks for uploading

  • @tamilagil
    @tamilagil 3 роки тому

    Thank you ❤️

  • @tawseefahmad1131
    @tawseefahmad1131 5 років тому

    Awesome👍

  • @gedlangosz1127
    @gedlangosz1127 5 років тому +6

    Again, the point of inflection has been ignored. This is the point where the gradient stops increasing and starts decreasing.
    On the graph of the derivative (the parabola) it is the maximum point, which is half way between the roots. On the schetched function, Eddie has drawn it much too close to the second turning point.