14-2 Kinetics of a Particle: Work and Energy | Chapter 14: Hibbeler Dynamics | Engineers Academy

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  • Опубліковано 21 гру 2024

КОМЕНТАРІ • 14

  • @grantjohnson2811
    @grantjohnson2811 10 місяців тому +3

    You're a great help and have been a key component to my success in statics, and now dynamics. My professors are not very good at explaining it in a way that I understand and work through little to no practice problems.

    • @EngineersAcademy2020
      @EngineersAcademy2020  10 місяців тому

      Thanks i am always here to help. Plz share my channel on your social media.

  • @karamsy5168
    @karamsy5168 2 роки тому +6

    God bless you bro

  • @ggbrizzy9936
    @ggbrizzy9936 Рік тому +1

    Thank you so much for making this video! You explain it better than my teacher!

  • @johnbach2077
    @johnbach2077 2 роки тому +2

    Helped a bunch, thank you

  • @rehanhyder836
    @rehanhyder836 3 роки тому +4

    KING

  • @bigime4352
    @bigime4352 2 місяці тому

    You've saved my life

  • @shaheryar6962
    @shaheryar6962 3 роки тому +4

    Cheetah of dynamics 🔥🔥🔥

  • @mikec9333
    @mikec9333 Рік тому

    Thank you!

  • @rickijoph
    @rickijoph 7 місяців тому

    Tysm

  • @Anto-kq9oi
    @Anto-kq9oi 6 місяців тому

    hi I don't know if you'll read this but I just stumbled upon your channel and I'm studying this chapter and I have a confusion with this problem on why do we only use the work done by the barrier and not use also the work done by the weight?

    • @karimelfar6870
      @karimelfar6870 6 місяців тому +1

      because weight is in the y direction and work in this problem is in the x direction. Work is always going along the force never perpendicular. Hope this helped

    • @Anto-kq9oi
      @Anto-kq9oi 6 місяців тому

      @@karimelfar6870ooohhhh I see it now, I forgot for a second there that I have to only use the work that moves in the same direction as the displacement and not the perpendicular ones, thank you so much for answering :)