I was wondering the same today too for the formula s(t)=4.9t^2. I found the answer to the question. It's 9.8 m/s being divided by 2 = 4.9 You see, 9.8 m/s is a constant value representing the acceleration due to gravity. This value is used to determine the motion of objects under the influence of gravity. On the other hand, 4.9 m/s^2 is an arbitrary value used to represent a constant acceleration of an object without gravity. Think about it like this; 9.8 is gravity and 4.9 is speed! Hope that helps.
Really a life saver as I missed some of my college classes and couldn't understand recent classes as i am having no idea of the beginning
Can you please suggest some channels for calculus and dm for first year cse
@@Storyblocks6969 for calculas this is a good channel, and for DM you can learn from any jee channel like pw, vedantu, unacadamy etc
VERY GOOD JOB IN EXPLAINING THIS PROBLEM YOU ARE A LIFE SAVER.
I appreciate the hustle my g big up
Absolutely marvelous. Thank you!
great vedio realy thanks!
THANK YOU
14:26 what is the reasoning behind 4.9?
Galileo discovered this constant experimentally by dropping objects four centuries ago.
I was wondering the same today too for the formula s(t)=4.9t^2. I found the answer to the question. It's 9.8 m/s being divided by 2 = 4.9
You see, 9.8 m/s is a constant value representing the acceleration due to gravity. This value is used to determine the motion of objects under the influence of gravity. On the other hand, 4.9 m/s^2 is an arbitrary value used to represent a constant acceleration of an object without gravity. Think about it like this; 9.8 is gravity and 4.9 is speed! Hope that helps.
sorry but where did you get the 5.1 from
isn't the slope of PR wrong at 10:38
shouldn't it be negative?
Yes, I catch the typo at 11:38.
Thank you.