[Adv] | Pathfinder Kinematics | CYU 34, 35 & 37
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- Опубліковано 28 вер 2024
- Telegram Discussion Group : t.me/+mBY5xDPe...
Pathfinder |Kinematics | Check Your Understanding 34 | CYU 34
34. Two cars are moving at constant speeds; one on a circular path of radius R = 200 m and the other on a straight road. Magnitude v of velocity of one car relative to the other has been recorded at regular intervals of time and data thus obtained is represented in a graph as shown in the figure. Calculate speeds of both the cars relative to the ground.
Pathfinder |Kinematics | Check Your Understanding 35 | CYU 35
35. A stone is projected from the ground with a velocity 10 m/s and its trajectory is drawn to an unknown scale on a graph paper. The horizontal range and the maximum height on the graph are 1.0 m and 0.25 m respectively. The graph paper is glued on a horizontal tabletop. If an insect moves along the trajectory on the graph paper with a uniform speed 1.0 cm/s, what should the modulus of its maximum acceleration be? Acceleration due to gravity is 10 m/s2.
Pathfinder |Kinematics | Check Your Understanding 37 | CYU 37
37. A particle P is moving with a constant speed u on a straight line that makes an angle with the positive x-direction of a coordinate system. When P crosses the y-axis at a point (0, 1), another particle Q starts from the origin and chases P with a uniform speed v (v u). The chaser Q always maintains its velocity vector towards the chased P.
(a) How long after Q starts from the origin, will it catch P?
(b) If both the chaser Q and the chased P move with equal speeds (i.e. u = v), what will be the minimum distance between them and what will be the maximum magnitude of acceleration of the chaser Q?
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![[Adv] | Pathfinder Kinematics | Check Your Understanding | CYU 30, 31 & 32](http://i.ytimg.com/vi/d9wNGHFdMbE/mqdefault.jpg)
![[Adv] | Pathfinder Kinematics | Check Your Understanding | 24 & 25](http://i.ytimg.com/vi/48FT3Lo0dz4/mqdefault.jpg)
hello sir i used to watch ur vids. I got around 70 marks in phy in jee adv 2024 and i am now going to iit delhi mech branch. you were of great help thanks a lot sir.
Congrats bro on 9k
Plz comeback 🙏
maza aata hai aapki videos dekh kar please videos banate rahiega...♥♥♥
3:26 bro Relative velocity max is 40 (Given in graph)
So 2usin(theta/2) = 40
U=20m/s
Bro why to find dv/dt
You are right bro. Even I got the answer without finding acceleration. The relative velocity was Vr = 2u cos (θ/2) and put θ = ωt, where ω = u/R. Thus Vr = 2u cos(ut/R). Now from graph, at t=0, Vr=40. Thus 40 = 2u cos(0), giving directly u = 20 m/s exact answer no approximation.
@@ThePhysicsGuruBro that 's great
But these problem can be solved orally
Imagine two vector A and B
Angle between the vector is changing with time
V(relative) = √[(va)^2 + (vb)^2 - 2(va)(vb)cos(theta)]
By the graph at t = 0
v(relative) = 40 (maximum value ) means angle Between them is 180
And at t= 25 V(relative)= 0 (Minimum) means angle between them is 0 and both have same magnitude.
Problem solved , both vectors are having same magnitude of 20 each.
Even we can find w of circular motion w= 2π/T
T= 50 (by graph)
Relative acceleration can also be fine .
04:40 It should be cos theta/2 . Lucky the answer didn’t change though 😅
Bro which app do you use for solving on ipad
Wow. Kinematics got over
Sir why are not coming now a days
Hi Sir. When are you coming back
Sir please come back
❤❤❤
Sir why no show off now a days?
❤️❄️
When will new video come ?
Sir are you alive ?
Or busy with semester exams ?
Wonderful explanation ❤
kinematics speedrun
Your telegram dp is killing me 😂😂😂
@@rudradutta2741 😂😂
Dear Sir, in Q35, you did not calculate the scale of the graph. I found that the scale is 10, means the actual range is 10m and actual max height is 2.5 m. Hence I got acceleration of insect as 0.2 x 10^(-4) instead of 2 x 10^(-4). Even the book's answer key is 2 x 10^(-4). Kindly consider the scale also. I will share my calculations if you ask me.
Hey great point, the calcs for actual range and actual height is perfect. But the insect is moving along the scaled down version of the graph so we have to consider the ROC for the given graph itself so we don't have to upscale it back.
@@Phyx_IITM ok sir thats a valid point. The insect is moving on the graph paper.
Bro can you please provide your email id. So that we students can share problems in which you can help us. Thank you for all your amazing efforts
bro can you do electromagnetism next pls
I found your videos at the end of my preparation (like almost a month before jee). I got ~90 in physics but messed up chemistry pretty badly so I ended up with IITK aerospace. Your question selection and approach definitely improved my physics considerably. Thank you 🙏
any suggestion for 11th std person bhaiya...
hey i have come up with an extremely intuivitive alternate solution method to this problem. Can you help me verify if its right.
Tell it
Bhai yaarr mujhe ye batao mai cengage bahut acche se laga rha hoon as a dropper ..enough hai na ya module bhi lagauu koi ?
Ya bss pyqs and cengage ..batadoo bhaiiiiiiii bhot confused hoon
kar toh pehle! aur kuch zarurat nahin.
@@pranavtiwari8018 okok
Hey, I wanted to ask a great question of rotational motion. Do you have an email id or a discord account where I can contact you?