in the second qns, fault is originated form transformer side, so it must be actual operation time of transformer relay = actual operation time of feeder relay minus 0.5 sec
Sir in third question, the fault originated from transformer. But we calculated TSM for feeder first i.e. feeder relay should operate first which is contradictory. Shouldn't we calculate transformer relay operating time first? (Question at 10:55)
Thank u so much sir for providing free access to this course.. It is helping me alot to clear my concepts. I want to clear my doubt regarding 2nd question tranformer section where we are selecting upper seeting that is 150%..this allows transformer to get overloaded upto 143%.so is it ok to do so?? Or its better to select the lower setting i.e 125%?? 17:18
For this, all types of fault is done at particular point and fault with maximum values will be the actual fault current of that point. Usually LLL fault gives maximum current value and Lg fault gives maximum voltage value.
Ur making these period of time very useful by uploading the videos thanking you sir.. From heartful
Ur videos r very useful so many people sir 💐 💐
in the second qns, fault is originated form transformer side, so it must be
actual operation time of transformer relay = actual operation time of feeder relay minus 0.5 sec
Very good. Thanks 🙏🙏🙏🙏🙏
Sir in third question, the fault originated from transformer. But we calculated TSM for feeder first i.e. feeder relay should operate first which is contradictory. Shouldn't we calculate transformer relay operating time first? (Question at 10:55)
Same doubt
Actual time of operation of transformer relay should be 0.9 - 0.5 =0.4; and TSM =0.4/5.6
@@er.sachidanandsah428 you are absolutely correct
Sir I request you pls make a short video ,why we need different types of relays as we've Inverse relay then why we construct IDMT.
@@lecturesinelectricaleng This short answer clarifies it. i was having same question. Thank you.
thank you sir.
How to check binary O/P during calibration?
how we calculate the fault level for given capacity sub station like 2 x 40 MVA capacity sub station 132 kV/33 kV
??
sir how to check the chart If PSM is 3.33 equal to 5.6 sec
Thanks sir
In Q2 : what the difference between transformer relay current & relay fault current?? Both are in the secondary of the same relay
15:58 timeline
Hi can you make a video about protection coordination?
Thank u so much sir for providing free access to this course.. It is helping me alot to clear my concepts.
I want to clear my doubt regarding 2nd question tranformer section where we are selecting upper seeting that is 150%..this allows transformer to get overloaded upto 143%.so is it ok to do so?? Or its better to select the lower setting i.e 125%?? 17:18
17:18
Thank you sir.
In that case transformer relay can't operate but feeder relay will operate and circuit will be tripped...
Sir again relay ck t 5000/(1000:5) divide and another time 500/(400:5) divide some thing confuse please tell
Sir where will be this PSM present in the relay circuit
@@lecturesinelectricalenggot it sir thank you
In table no given 8 value I mean 3.15
@@lecturesinelectricaleng how it is draw sir
Sir, how can we find fault current in practical.
Suppose everything working fine
For this, all types of fault is done at particular point and fault with maximum values will be the actual fault current of that point. Usually LLL fault gives maximum current value and Lg fault gives maximum voltage value.