Grade 9: Variations - Inverse Variation

[@miko_elle]

super helpful talaga nahirapan ako mag hanap ng vids dito sa yt na ganto ang pag explain, pinahahaba kasi nila hindi tulad nito madali lang at madali makabisado.
thank u sir! 💗💗💗

[@charlymagneleones1204]

Mas nagets ko pa to kesa sa module ko. Thankyouu sir!

[@sirchad]

You're welcome Charly. 😊

[@timmster4036]

i understood most of what you said but it was still helpful thank you!

[@eulassimp2720]

Sir thank you po mas naiitindihan ko dito Ang mga lesson kesa sa ibang Video tuturial

[@sirchad]

Thanks for appreciation Rudy. 😊

[@botorjohenesiiib.2841]

AAAAAaaa thankyou so much po! ikaw nalang po teacher ko Huhu

[@sirchad]

Most welcome Botor, Johenes III B. 😊

[@bananaa4203]

Mas Madali pa talaga ito sa Module Namin Sir.. Salamat Po

[@sirchad]

You're welcome. 😊

[@juanmateo1673]

Grabe sir chad thank you po di ko po kasi maintindihan yung nasa module buti na lang nagupload na po kayo ng ganitong lesson thank you po💕

[@sirchad]

You're welcome Jm. I am grateful to know that I can help. 😊

[@ivhanglen6488]

Thank you so much po sir kung kailan pasahan na mamaya ngayon ko lang na gets 🤣

[@sirchad]

You're welcome Ivhan. 😊 Sabi nga nila, "It's better late than never." 😁

[@princessvillejo9643]

Ang ganda po sir 😉♥️ tenkyu po

[@sirchad]

You're welcome Kian. 😊

[@crazyroilan9429]

Ty po talaga po 🤣 magulo po kasi yung equation pinagtuturo po sa amin kaya po lahat nalilito

[@sirchad]

You're welcome. 😊

[@mikyramirez7055]

Thanks sir ito po yung hinahanap ko di ko po magets sa libro.huhu salamat po sir always supporting your channel po♥️

[@sirchad]

Thanks for appreciation Miky. Maraming salamat din sa iyong suporta. 😊

[@harveypacurza1178]

If u need more understanding or may mga tanung kau na d po nadisscuss ni sir Chad sa video Nia follow his page and nagrereply po sia❤️

[@sirchad]

Thanks for the support ER3N YT. 😊

[@harveypacurza1178]

@@sirchad wlang anuman sir slamat sa pagturo saken knina hope mag gro grow pa ung yt nio at ganiyan pa ren po ung pagtuturo nio pag medyo umangat na po kau

[@sirchad]

@@harveypacurza1178 thank you also. 😊 Rest assured that I will do my best in order to help more students. 👍

[@giancarlboston5160]

very helpful omg

[@julieannayala9829]

Thank you po Sir😊

[@sirchad]

Always welcome Julie Ann 😊

[@aenims6653]

Kung sa direct variation.
a) divide
b) substitute
c) multiply
Sa inverse variation naman
a) multiply
b) substitute
c) divide
May situation po ba na pwedeng magiba yung operations na gagamitin?

[@sirchad]

Hello Nicole. Thanks for your question. The solution will be depending on the statement of the problem. Specially in combined variations cases. 😊

[@kenniyyyy5447]

Nice 👌🏼

[@sirchad]

Thanks Ken. 😊

[@aenims6653]

Sir medyo naguguluhan po ako sa kaganapan ng x, pag po sasagutin ang c, kailangang dodoblehin yung value ng x?, (Bawal po ba syang hindi nalang galawin)

[@sirchad]

Hello Nicole, anong ibig mong sabihin sa dodoblehin ang value ng x? Can you share the question itself?

[@aenims6653]

@@sirchad napansin ko po kasi 8 yung given sa x tapos naging 16 sya nung sinosolve na yung 'c' kaya naisip ko po na baka dinodoble sya? Naguguluhan den po akoಥ‿ಥ

[@sirchad]

Depende kasi yun sa given Nicole. Ano ba ang problem na hindi mo masagutan. You can message me in my Facebook Page to discuss it. 👍😊

[@justinecaguiclaendaya2857]

Hai po sir! Paano po kapag ang tanong ay if x varies as the square of y and inversely as z? Pano po ang magiging solution doon po sir?

[@sirchad]

Hello JUSTINE, the equation will be x=y²/z. 😊

[@justinecaguiclaendaya2857]

@@sirchad thank you always sir!!!💓💓

[@sirchad]

@@justinecaguiclaendaya2857 you're welcome. 😊

[@johnanthonycanonoy3393]

Hi po sir chad how about namn po pag ganito , Constant of variation xy = 5(2/5) = 3(2/3) = 2(1) = 2
Equation xy = 2 or y = 2 / x
Dko lng po magets sa module ko po bakit may (1) sa tabi po ng 2

[@lemonieyahhh]

Pa'no po kapag fraction yung nasa "K"

[@sirchad]

It is fine even the k is fraction. 😊

[@jayoinometse6331]

Sir sa sanmo kinoha y when x=16
Pls pasagot

[@sirchad]

Hi Jay. That is what is asked in the problem. Meaning, that is given information for us to solve it.

[@ysmiejavier573]

Hai sir pano po nakuha yung 16 sorry po naguguluhan po kase ako