Factors of -6 divided by factors of 1 are possible zeroes. 1 is the easiest to use. Try it. Synthetic division shows the polynomial is divisible by (x-1), so x=1 is a factor. What's left is x^2 - 5x + 6 The factors of 6 that add to -5 are -2 and -3. (x-2)(x-3)=0 x = 2 and x=3 The zeroes/solutions are x=1, 2, and 3. BTW, it's not an exponential equation. It's a polynomial equation. Exponential equations involve exponents that are variables.
Sometimes u wrote it is a polynomial equation and sometimes exponential one. Polynomial equation The variables are the bases. Exponential equitation The variables are exponents.
Factors of -6 divided by factors of 1 are possible zeroes. 1 is the easiest to use. Try it.
Synthetic division shows the polynomial is divisible by (x-1), so x=1 is a factor.
What's left is x^2 - 5x + 6
The factors of 6 that add to -5 are -2 and -3.
(x-2)(x-3)=0
x = 2 and x=3
The zeroes/solutions are x=1, 2, and 3.
BTW, it's not an exponential equation. It's a polynomial equation. Exponential equations involve exponents that are variables.
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Nice Alternative 👍
YEs, correct approach, the problem does not deserve to be in Olympiad, may be for kindergarten though
Sometimes u wrote it is a polynomial equation and sometimes exponential one.
Polynomial equation
The variables are the bases.
Exponential equitation
The variables are exponents.
Thank you for the comment.