Ep. 010 - Homophonic Substitution, encryption and decryption
Вставка
- Опубліковано 14 сер 2021
- Ninth of the real cipher types - Homophonic Substitution
Processes for encryption and decryption.
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Cast:
The Chief: Curtis Hoffmann
Editing, direction, sound, error generation:
Curtis Hoffmann - Наука та технологія
Four practice Homophonic Substitution ciphers to cut your teeth on (from easy to more difficult). The word in the parentheses is a hint, and exists in the plaintext.
Title card (cipher)
24 35 98 54 55 24 54
53 74 19 58 60 88 58
40 25 80 11 40 30 05
34 68 95 76 73 26 78
hs-1: Dr. Seuss - it could be worse (happens)
83 73 23 99 11 00 98 26 80 29 95 06 25 67 19 22 73 87 36 36
26 06 79 45 00 13 01 87 42 70 40 73 57 70 70 68 73 54 30 49
91 58 45 00 81 49 47 34 70 02 12 01 70 38 32 70 12 74 12 22
91 27 30 06 70 85 00 60 04 91 12 95 59 90 91 58 12 10 54 85
17 07 81 35 57 17 07 13 49 19 99 04 23 80 95 59 58 59 78 26
53 93 40 01 91 34 64 54 60
hs-2: Dr. Seuss - it doesn't have to be easy (chance)
86 02 76 39 53 03 01 52 78 24 33 26 09 80 63 96 26 35 30 67
52 05 31 05 15 80 66 26 71 03 63 51 76 72 53 42 36 67 31 82
07 30 52 05 52 09 39 23 10 62 49 14 26 05 62 86 44 81 79 82
82 22 43 49 44 85 82 57 86 53 14 52 92 75 72 08 86 51 63 81
86 96 99 91 97 69 25 79 30 18 39 13 44 85 86 96
hs-3: Dr. Seuss - Preconceptions (pleasing)
23 08 63 69 93 64 50 56 08 11 62 56 79 11 31 45 95 30 20 47
95 26 96 80 05 24 20 12 59 78 57 08 69 02 55 11 83 06 79 61
23 18 79 85 11 83 55 76 25 99 50 31 64 31 02 55 65 42 82 12
26 50 84 45 91 69 74 08 85 16 91 07 84 31 26 92 42
hs-4: Charles Schulz - Introspection (no hint)
63 31 83 20 90 80 57 76 08 26 28 80 20 16 67 16 55 20 97 36 84
24 52 79 90 16 84 00 26 97 35 55 67 53 47 62 20 23 43 11 20 80
22 59 84 75 39 88 04 58 78 36 23 47 84 71 11 85 80 45 75 63 97
41 89 64 59 83 47 09 50 26 63 24 89 52 85 24 84 22 90 04 64 16
27 76 02 85 88 47 09 79 43 58 31 03 76 58 26 49 53 09
Thank you, Sir. I appreciate this educational material.
You can't find quality content like this anywhere else on UA-cam. I've been searching a long time for a good tutorial on homophonic substitution ciphers. Thank you
Glad you liked it!
Hmm. I received a question about numbering, but for some reason, UA-cam isn't showing the question from that user when I look for it. Healy, if you're reading this, I apologize.
Numbering starts at whatever key value you choose. If you want the key to be "code," then the first line will start numbering at 03 (A=01, C=03), then when it reaches 25 for the first line, it drops back to 01 and starts incrementing up again. Picking a different key letter (i.e. - "P") means that numbering for that line will start at a different value (16).
The best introduction ever
Thanks!
Thank you, that helped me alot.
where alphabet " J "...?
Hi Robi, thank you for your question.
For this cipher type, we can only have 25 letters for the alphabets. So J doubles up with I.