Best explanation of Method of Images by far. I've been memorizing the two or three problems traditionally discussed in lecture, whenever I've needed to for an exam. Now, after a long time, deep into my 5th year of the PhD, it finally makes sense. Thanks!
This was superb explanation of a very complicated topic. I hope you do other lectures. Perhaps you can lecture for the Great Courses Company or give a course for Coursera. Not only were you clear but also made this interesting.
I was trying to solve it the exact same way, but I didn't specify the potential for A and B, which gave me only 1 equation instead of 2, and I got stuck with 2 variables anyway. Thanks for this video, helped a lot.
After spending hours reading physics books, your explanation makes it way more easy to digest the topic. By any chance, do you have a follow up lecture relating to multilayer imaging of charge enclosed in four planar surface?
I finally understood this proof. Thanks. One question though. Is the potential inside the sphere (if there is no extra charge inside) zero, like it is at its surface?
QUESTION: You have considered two points on the sphere where potential equals zero but how can one make sure that all the points on the sphere have been included?
I have the same question as Curious Bit. So I accept we've made the potential equal to 0 at A and B. But how are we sure that we made the potential 0 everywhere on the sphere?
@@two697 I think it's to do with the uniqueness theorem. If the potential satisfies the boundary conditions at at least two bits of the boundary then it's the only solution. en.wikipedia.org/wiki/Uniqueness_theorem_for_Poisson%27s_equation
I have an exercice similar: Calculate the potential produced by a point charge q placed at distance d from the center of a conducting sphere of radius R *having total charge q* And i don't know what change. :s And i have one question, why your potential=0, it's not a constant?
Because it's conducting, and the potential on any conductor at equilibrium (like in any of these static charge problems) is constant. Reason: conductors have to have a 0 electric field, because any electric field that would exist on the surface of a conductor would force the free charges to move until they reach equilibrium with each other (aka no net forces on them, aka no electric field). And then electric field is the negative gradient of potential, so if electric field is 0, the potential must be constant. And then what he-who-shall-not-be-named said: grounded means set that potential to 0.
Best explanation of Method of Images by far. I've been memorizing the two or three problems traditionally discussed in lecture, whenever I've needed to for an exam. Now, after a long time, deep into my 5th year of the PhD, it finally makes sense. Thanks!
the only best explanation i have found on you tube
Mohammed Ayalew Thanks! I'm glad I could help.
Agreeeeeed
Thank you very much for a simple and clear explanation, your 15 minute video was much better then an one hour lecture at my university.
mark111112222212 Thank you for the kind words.
This is hands down the best explanation I've ever seen for this type of problems.
I have surfed for hour but this is the only explanation which helped me and i got everything in 16 minutes .. Thank you so much
By far the best explanation of this concept I've seen. Thanks!
After hours, i finally understand this problem. What a clear and simple explanation. Thanks!
Thank you! I was struggling with this for ages, this is the only example I've found that shows how we find Q and a, very grateful!!
Thank you for such an great explanation this 15 minute worth more than 60 minute lecture at my college.
Thank you very much! My professor has spent 2 classes in this topic, but neither of my classmates nor me, have beeen able to understand.
No problem! I hope I made things clearer.
The veryyy best explanation!!!...
And my search for the concept clearing ends here..
Thankyouu sirr!
Fantastic video. Thank you, friend.
great video!
is there a chance you would upload a solution for finding image charges of a dipole above a grounded plane?
thank you sooooo much! I have been finding a video like this for a long time!!!
This is an elaborate explanation, thanks a lot :)
Wow it was an amazing explanation, thank you so much!
This was superb explanation of a very complicated topic. I hope you do other lectures. Perhaps you can lecture for the Great Courses Company or give a course for Coursera. Not only were you clear but also made this interesting.
Nice explanation.
You're awesome! Please post more videos
Thank you. Very well explained.
This is amazing. Thank you
Lifesaver dude! Thank you so much 😎
I was trying to solve it the exact same way, but I didn't specify the potential for A and B, which gave me only 1 equation instead of 2, and I got stuck with 2 variables anyway. Thanks for this video, helped a lot.
thank sooo very much for making it so clear.
Great explanation sir🙏🙏🙏...from INDIA 🇮🇳
Sir thanku so much,ur explanation is so excellent and this help me alot👍👍👍👍👍
This is a dank explanation, thanks.
Chucktage You're welcome, I'm glad you liked it.
that was a great one , thx :D
best explanation， much better than my professor did.
nice . Thanks you so much, I'm french student in physics and i have understand . Merci beaucoup
If point charge inside a conducting sphere, then what approach should I take?
Thanks a lot.This helped.
you are the best
After spending hours reading physics books, your explanation makes it way more easy to digest the topic. By any chance, do you have a follow up lecture relating to multilayer imaging of charge enclosed in four planar surface?
I don't have anything like that at the moment, but I plan on adding more videos in the future.
Thanks for explaining
thank you very much
super! thank you.
This was a superb
Hi, what happens if the point charge is replaced with a metal sphere of potential V?
Thank you 🙏
What's the potential inside the sphere? Can I use this method if the sphere is not grounded?
I finally understood this proof. Thanks.
One question though. Is the potential inside the sphere (if there is no extra charge inside) zero, like it is at its surface?
yes
thank you sir! from korea
QUESTION: You have considered two points on the sphere where potential equals zero but how can one make sure that all the points on the sphere have been included?
maybe you should write a general equation for potential and substitute (x^2 + y^2 = R^2) that includes all the points on the circle
great, it helped me alot.
thake you very much
Thank you so much
This is great
hi can you help me with a electricity and magnetism problem? It involves the image of a line charge outside of a conducting sphere
Thanks a lot
Good vidio!!!!!!
its really very helpfull.
thank you!!
What is the solution if dV/dr = 0 on the sphere instead of V = 0?
I really need the solution worked out to graduate. Thanks!
If the sphere is connected to a potential, what happens?
thnxs u so much!!!! soo helpfull
Please make video on books you use
I have the same question as Curious Bit.
So I accept we've made the potential equal to 0 at A and B. But how are we sure that we made the potential 0 everywhere on the sphere?
Did you ever find out the answer to this question?
@@two697 I think it's to do with the uniqueness theorem. If the potential satisfies the boundary conditions at at least two bits of the boundary then it's the only solution. en.wikipedia.org/wiki/Uniqueness_theorem_for_Poisson%27s_equation
I have an exercice similar: Calculate the potential produced by a point charge q placed at distance d from the center of a conducting sphere of radius R *having total charge q*
And i don't know what change. :s
And i have one question, why your potential=0, it's not a constant?
The coductor is grounded and so the potential on it is zero.
i am just hoping that you are still making videos
Yes, I do plan on making more. I should be able to make some more in the next few months.
learnifyable ok. thanks .
thank u
Hi !
what's difference if we have the same problem but the charge q is now located inside the sphere ???
Heero Yui You can do a similar analysis, but remember, you can't put an image charge in the area where you are trying to calculate the potential.
learnifyable okay, thanks you !
+learnifyable how can find the elictric field and surface charge of this v
THIS VIDEO IS HELPFUL FOR STEDENTS
Why a blue background?
What happen if the sphere is not grounded?
we have put +R/d*q on the center of the sphere so that electric potential should be equal around the sphere and all the charge quantity be q.
can anyone prove the boundary condition for me plz :(( i dont know why the electric potential on the spere surface is 0
Because it's conducting, and the potential on any conductor at equilibrium (like in any of these static charge problems) is constant.
Reason: conductors have to have a 0 electric field, because any electric field that would exist on the surface of a conductor would force the free charges to move until they reach equilibrium with each other (aka no net forces on them, aka no electric field). And then electric field is the negative gradient of potential, so if electric field is 0, the potential must be constant. And then what he-who-shall-not-be-named said: grounded means set that potential to 0.
reply soon.. at last in case of sphere when i put the boundary condition to checking that the V is right i put Z="R". but V is not becoming zero????