Work Done In Isothermal Reversible Expansion Of An Ideal Gas Derivation Class 11 Physics Term 2
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- Опубліковано 25 січ 2022
- Work done in isothermal reversible expansion) of an ideal gas derivation from thermodynamics chapter class 11 term 2 Physics. I have discussed the derivation of work done in isothermal reversible expansion of an ideal gas which is from chapter 12 of class 11 Physics and it is very important derivation for final exams of class 11 term 2 in 2022.
The formula for isothermal process is also very important for final exams as numerical problems based on this concept are frequently asked in exams.
PDF notes of work done in isothermal process: drive.google.com/file/d/16PAW...
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Class 11 Physics term 2 important numericals: • Class 11 Physics Term ...
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💥Most important books for term 2 preparation (do any one of these):
Arihant class 11 chapter wise question bank: amzn.to/3JOWtPl
Oswaal class 11 chapter wise question bank: amzn.to/3vdIO09
Xam idea class 11 chapter wise question bank: amzn.to/3Ihm5UN
MTG class 11 chapter wise question bank: amzn.to/3shbTWU
Together with Class 11 term 2 chapter wise question bank: amzn.to/3Hfv7QI
Oswaal complete bundle for class 11 term 2: amzn.to/3shEA62
Arihant complete bundle PCM term 2: amzn.to/35mQX7y
💥Most important videos for term 2
Class 11 Physics term 2 important numericals: ua-cam.com/video/G0NoPoEOEks/v-deo.html
Class 11 Physics term 2 important theory questions: ua-cam.com/video/tZF-0p4y5gQ/v-deo.html
Class 11 Physics important derivations: ua-cam.com/video/VTHkiNaHNIM/v-deo.html
Best way to write Physics derivations: ua-cam.com/video/fvtr3yebcBw/v-deo.html
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dw= -pdv or +pdv
And also pls explain where the value of dw becomes -pdv ?
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Blunder mistake workdone= -intigrate pdv this is right formula
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If the process is isothermal
Why you are putting HEAT to increase pressure
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Integration mai -Pdv aayega ya positive Pdv
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Positive
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Sir I think you are doing wrong because it is external pressure but not internal pressure
Yes but because the piston is moving upward without acceleration so external force (and pressure) must be equal to external force
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Work done in an Isothermal Process
Work done in an isothermal expansion. Consider n moles of an ideal
gas contained in a cylinder having conducting walls and provided with
frictionless and movable piston, as shown in the figure below. Let P be
the pressure of the gas.
Work done by the gas when the piston moves up through a small distance
dx is given by
dW = P A dx = PdV
where A is the cross-sectional area of the piston and dV = Adx, is the small increase in the volume
of the gas. Suppose the gas expands isothermally from initial state 1 1 ( , ) P V to the final state 2 2 ( , ) P V .
The total amount of work done will be
2
1
V
iso
V
W PdV
For n moles of a gas, PV = nRT or nRT P
V
2 2
2
1
1 1
2
2 1
1
1
[ln V]
= nRT [ln V ln V ] ln
V V
V
iso V
V V
nRT W dV nRT dV nRT
V V
V
nRT
V
2 1
1 2
2.303 nRT log = 2.303 nRT log iso
V P
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