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Pythagorean Theorem:a² + b² = c²By diagram, b = 3 and by statement c = 4 (sine = opposite / hypotenuse).a² + 3² = 4²a² = 16 - 9 = 7a = √7 = BC
Pythagoras: a² + b² = c² for a right angled triangle. In this case a = AC = 3 c = AB = 4 and b = BCso 3³ + BC² = 4² -> BC² = 16 - 9 = 7 and BC = V7
AB = 4 ? That is not given.
@@Kleermaker1000 Sinus angle B = 3/4 and sinus B = AC/AB = 3/4 so AB = 4
@@panlomito O well, I know very little about geometry.
Sin = opposite/hypotenuseplugging in gives✓7 = 2.65
Sin angle x = opposite side/hypotenuse, so here, using Pythagorean threaten, side BC = ✔️7.
opp / hyp 3/4 pyth theor = sq rt 7. thanks for the fun.
√7🥱
Square root of 7
Pythagorean Theorem:
a² + b² = c²
By diagram, b = 3 and by statement c = 4 (sine = opposite / hypotenuse).
a² + 3² = 4²
a² = 16 - 9 = 7
a = √7 = BC
Pythagoras: a² + b² = c² for a right angled triangle. In this case a = AC = 3 c = AB = 4 and b = BC
so 3³ + BC² = 4² -> BC² = 16 - 9 = 7 and BC = V7
AB = 4 ? That is not given.
@@Kleermaker1000 Sinus angle B = 3/4 and sinus B = AC/AB = 3/4 so AB = 4
@@panlomito O well, I know very little about geometry.
Sin = opposite/hypotenuse
plugging in gives
✓7 = 2.65
Sin angle x = opposite side/hypotenuse, so here, using Pythagorean threaten, side BC = ✔️7.
opp / hyp 3/4 pyth theor = sq rt 7. thanks for the fun.
√7🥱
Square root of 7