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sir in the second last qs 20:39 standard deviation is given 2 yrs so shouldnt we consider sigma square as 4 , ie , x = (sigma^2)*z + u , = 4*(-1.88) + 10 ?
Our x is mean + z*sigma.. mean is 10 and sigma is 2. So 4 will not come..
sir for 11:23 Q6.7 , if we have a non normalized dist with X
Yes, you need to find z value first and then use tables..
@@DrMathaholic yess sir got it
sir in the second last qs 20:39 standard deviation is given 2 yrs so shouldnt we consider sigma square as 4 , ie , x = (sigma^2)*z + u , = 4*(-1.88) + 10 ?
Our x is mean + z*sigma.. mean is 10 and sigma is 2.
So 4 will not come..
sir for 11:23 Q6.7 , if we have a non normalized dist with X
Yes, you need to find z value first and then use tables..
@@DrMathaholic yess sir got it