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00:00:00 Intro 00:05:47 Agni Batch Class Details 00:09:56 Sets 00:12:45 Deleted Topics 00:14:17 What is a set 00:28:25 Roster & Set Builder 00:32:35 PYQ 00:39:10 Empty Set (Phi) 00:40:10 Singleton Set 00:42:27 Subsets 00:54:45 PYQ 1:00:19 Subset & Element 1:05:15 Example 9 1:06:53 Intervals 1:11:43 PYQ 1:13:25 Universal Set 1:14:25 Venn Diagrams 1:23:05 Union 1:25:29 Intersection 1:29:25 Set Difference 1:31:58 Complement 1:34:00 Important Formula 1:36:44 Questions 1:51:17 DeMorgan Law 1:54:30 PYQs
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The given information is as follows: (n(A) = 10) (n(B) = 17) (n(A U B) = 23) Substituting the given values: [ n(AU B) = 10 + 17 - 23 = 4 ] Therefore, there are 4 elements common to both sets A and B. 😊
Ans)Formula = n(AUB) = n(A)+ n(B)-n(A^B) n(A^B) = n(A)+n(B)-n(AUB) = 10+17-23 = 27-23 = 4 Therefore , n(A^B)= 4 Thank you so much sir ❤ very interesting classes.I am very enjoying to this classes ♥️. Thank you so much EXAMWINNER ❤❤
Question: n(A)=10 n(B)=17 n(AUB)=23 n(A^B)=? Solution: n(AUB)= n(A)+n(B)-n(A^B) 23= 10+17-n(A^B) 23= 27-n(A^B) n(A^B)= 27-23 n(A^B)= 4 Thank u Allen Sir for the wonderful class...❤️🔥
🔥🔥Be there on Today's💥JEE Physics | Units And Measurement | Chapter 1 | Oneshot Live💥@ 7:00 PM🥳Link : ua-cam.com/users/liveBPE7VtrEIqs?si=tlHPiw359sfZ-kCX
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00:00:00 Intro
00:05:47 Agni Batch Class Details
00:09:56 Sets
00:12:45 Deleted Topics
00:14:17 What is a set
00:28:25 Roster & Set Builder
00:32:35 PYQ
00:39:10 Empty Set (Phi)
00:40:10 Singleton Set
00:42:27 Subsets
00:54:45 PYQ
1:00:19 Subset & Element
1:05:15 Example 9
1:06:53 Intervals
1:11:43 PYQ
1:13:25 Universal Set
1:14:25 Venn Diagrams
1:23:05 Union
1:25:29 Intersection
1:29:25 Set Difference
1:31:58 Complement
1:34:00 Important Formula
1:36:44 Questions
1:51:17 DeMorgan Law
1:54:30 PYQs
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The given information is as follows:
(n(A) = 10)
(n(B) = 17)
(n(A U B) = 23)
Substituting the given values: [ n(AU B) = 10 + 17 - 23 = 4 ]
Therefore, there are 4 elements common to both sets A and B. 😊
good job 😷👍
(AUB)=23 not (A intersection B)
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Ans)Formula = n(AUB) = n(A)+ n(B)-n(A^B)
n(A^B) = n(A)+n(B)-n(AUB)
= 10+17-23
= 27-23
= 4
Therefore , n(A^B)= 4
Thank you so much sir ❤ very interesting classes.I am very enjoying to this classes ♥️. Thank you so much EXAMWINNER ❤❤
Thank you Alen sir for your lovely support 😊❤
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¡__ { }¹^A =A¹
¡¡__ u¹^A =A
¡¡¡__ A uA¹ =u
4-- A¹^A¹=A¹
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{1,2}
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Ans: 10+17-23=4
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𝚂𝚞𝚙𝚎𝚛 𝚌𝚕𝚊𝚜𝚜❤
Question:
n(A)=10
n(B)=17
n(AUB)=23
n(A^B)=?
Solution:
n(AUB)= n(A)+n(B)-n(A^B)
23= 10+17-n(A^B)
23= 27-n(A^B)
n(A^B)= 27-23
n(A^B)= 4
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A={1,2}
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Ans:👇
n(A)=10
n(B)=17
n(AUB)=23
n(AUB)=n(A)+n(B)-n(A^B)
23=10+17-n(A^B)
23=27-n(A^B)
27-23=n(A^B)
4=n(A^B)
Your Answer is correct❤️ Weldone
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